a: \(3^2\cdot\frac{1}{243}\cdot81^2\cdot\frac{1}{3^2}\)

\(=\frac{3^2}{3^5}\cdot\frac{3^8}{3^2}=\frac{1}{3^3}\cdot3^6=3^3=27\)

b: \(4^6\cdot256^2\cdot2^4=\left(2^2\right)^6\cdot\left(2^8\right)^2\cdot2^4\)

\(=2^{12}\cdot2^{16}\cdot2^4=2^{12}\cdot2^{20}=2^{32}\)

c: \(4^6\cdot9^5+6^9\cdot120\)

\(=2^{12}\cdot3^{10}+2^9\cdot3^9\cdot2^3\cdot3\cdot5\)

\(=2^{12}\cdot3^{10}+2^{12}\cdot3^{10}\cdot5\)

\(=2^{12}\cdot3^{10}\cdot6=2^{13}\cdot3^{11}\)

Ta có \(8^4\cdot3^{12}-6^{11}\)

\(=2^{12}\cdot3^{12}-2^{11}\cdot3^{11}\)

\(=2^{11}\cdot3^{11}\left(2\cdot3-1\right)=2^{11}\cdot3^{11}\cdot5\)

Ta có: \(A=\frac{4^6\cdot9^5+6^9\cdot120}{8^4\cdot3^{12}-6^{11}}\)

\(=\frac{2^{13}\cdot3^{11}}{2^{11}\cdot3^{11}\cdot5}=\frac{2^2}{5}=\frac45\)

d: \(4^2\cdot25^2+32\cdot125\)

\(=2^4\cdot5^4+2^5\cdot5^3\)

\(=2^4\cdot5^3\left(5+2\right)=2^4\cdot5^3\cdot7\)

\(B=\frac{4^2\cdot25^2+32\cdot125}{2^3\cdot5^2}\)

\(=\frac{2^4\cdot5^3\cdot7}{2^3\cdot5^2}=2\cdot5\cdot7=70\)

a, ((2.x+54)-32).2=244

((2.x+54)-32)=244:2

((2.x+54)-32)=122

(2.x+54)=122+32

(2.x+54)=154

x+54=154:2

x+54=77

x=77-54

x=23

{(2x+54)-32}.2=244

(2x+54)-32=244:2122

2x+54=154

2x=100

x=50

18

tick nHÉ ngỌC hÀ

647-[y:(46+13+54)]=54-32+46

=647-[ y:( 46+13+54) ]=68

=647-[y:113]=68

=647-68

=579

=579x113

=65427

[ 2. ( 70 - x ) + 72 ]: 2 =46

2. ( 70 - x ) + 72 = 46.2

2. ( 70 - x ) + 72 = 92

2. ( 70 - x ) =92-72

2. ( 70 - x ) =20

70-x=20:2

70-x=10

x=70-10

x=60

[ ( 2.x + 54 ) - 32 ] . 2 = 244 

 ( 2.x + 54 ) - 32 = 244:2

( 2.x + 54 ) - 32 = 122

2.x + 54 = 122+32

2.x + 54 = 154

2.x =154-54

2x=100

x=100:2

x=50

mk vừa làm hoi này cho bạn mà                

C=[(46-32)^2-(54-42)^2]*36-1872 

=(14^2-12^2)*36-1872

=(196-144).36-1872

=52.36-1872

=1872-1872

=0

a)

(-4) . 32 . (-25) . 11

= (-4).(-25) . (32.11)

= 100 . 352

= 35200

b)

-86 . 46 - 46 . 27 + 46 . 23

= 46. ( -86 - 27 + 23)

= 46. (-90) = -4140

Chúc em học tốt!!!

a)

(-4) . 32 . (-25) . 11

= (-4).(-25) . (32.11)

= 100 . 352

= 35200

P/s tham khảo nha