5-x/12+5/12-1/8=3/8
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\(-\dfrac{7}{12}\cdot\dfrac{3}{8}+-\dfrac{7}{12}\cdot\dfrac{5}{8}+1\dfrac{7}{12}\)
\(=-\dfrac{7}{12}\cdot\left(\dfrac{3}{8}+\dfrac{5}{8}-1\right)\)
\(=-\dfrac{7}{12}\cdot\left(\dfrac{8}{8}-1\right)\)
\(=-\dfrac{7}{12}\cdot\left(1-1\right)\)
\(=-\dfrac{7}{12}\cdot0\)
\(=0\)
a: =7/8:(2/9-18+1/36)-5/12
=-7/142-5/12=-397/852
b: =3/7(4/9+5/9:6/12)=2/3
c: =5^8(16/31-47/31)+1/3=-5^8+1/3
d: =7/2(3/8+5/8:4/15)=609/64
Bài giải:
Câu 1: a, \(\left(-2\right).4.5.38.\left(-25\right)\)
\(=\left[\left(-2\right).5\right].\left[4.\left(-25\right)\right].38\)
\(=\left(-10\right).\left(-100\right).38\)
\(=1000.38=38000\)
b,\(\frac{1}{3}+\frac{3}{8}-\frac{7}{12}\)
\(=\left(\frac{1}{3}+\frac{3}{8}\right)-\frac{7}{12}\)
\(=\frac{17}{24}-\frac{7}{12}=\frac{1}{8}\)
c, \(\frac{-5}{8}.\frac{5}{12}+\frac{-5}{8}.\frac{7}{12}+2\frac{1}{8}\)
\(=\frac{-5}{8}.\left(\frac{5}{12}+\frac{7}{12}\right)+\frac{17}{8}\)
\(=\frac{-5}{8}.1+\frac{17}{8}\)
\(=\frac{3}{2}\)
Câu 2: a, \(x-\frac{2}{5}=0,24\)
\(x-0,4=0,24\)
\(x=0,24+0,4\)
\(\Rightarrow x=0,64\left(\frac{16}{25}\right)\)
b,\(\frac{2}{3}.x+\frac{1}{12}=\frac{1}{10}\)
\(\frac{2}{3}.x=\frac{1}{10}-\frac{1}{12}\)
\(\frac{2}{3}.x=\frac{1}{60}\)
\(x=\frac{1}{60}:\frac{2}{3}\)
\(\Rightarrow x=\frac{1}{40}\)
c, \(\left(3\frac{1}{2}-2x\right).1\frac{1}{3}=7\frac{1}{3}\)
\(\frac{7}{2}-2x=\frac{22}{3}:\frac{4}{3}\)
\(\frac{7}{2}-2x=\frac{11}{2}\)
\(2x=\frac{7}{2}-\frac{11}{2}\)
\(2x=-2\)
\(\Rightarrow x=-2:2\)
\(x=-1\)
\(\dfrac{3}{8}\times\dfrac{5}{12}+\dfrac{5}{8}\times\dfrac{5}{12}\)
\(=\dfrac{5}{12}\times\left(\dfrac{3}{8}+\dfrac{5}{8}\right)\)
\(=\dfrac{5}{12}\times1\)
\(=\dfrac{5}{12}\)
3/8 x 5/12 + 5/8 x 5/12
= 5/12 x (3/8 + 5/8 )
= 5/12 x 1
= 5/12