Bài 2:

E=(1;+∞)

=>E={x∈R|x>1}

F=(-∞;6]

=>F={x∈R|x<=6}

G=(-2;3]

=>G={x∈R|-2<x<=3}

H=[-3/2;1]

=>H={x∈R|\(-\frac32\le x\le1\) }

Bài 1:

a: A={x∈R|x>=-3}

=>A=[-3;+∞)

Biểu diễn:

b: B={x∈R|x<8}

=>B=(-∞;8)

Biểu diễn:

c: C={x∈R|-1<x<10}

=>C=(-1;10)

Biểu diễn:

d: D={x∈R|-6<x<=8}

=>D=(-6;8]

Biểu diễn:

e: E={x∈R|1/2<=x<=5/2}

=>E=\(\left\lbrack\frac12;\frac52\right\rbrack\)

Biểu diễn:

f: x-1<0

=>x<1

=>F=(-∞;1)

Biểu diễn:

Bài 2:

E=(1;+∞)

=>E={x∈R|x>1}

F=(-∞;6]

=>F={x∈R|x<=6}

G=(-2;3]

=>G={x∈R|-2<x<=3}

H=[-3/2;1]

=>H={x∈R|\(-\frac32\le x\le1\) }

Bài 1:

a: A={x∈R|x>=-3}

=>A=[-3;+∞)

Biểu diễn:

b: B={x∈R|x<8}

=>B=(-∞;8)

Biểu diễn:

c: C={x∈R|-1<x<10}

=>C=(-1;10)

Biểu diễn:

d: D={x∈R|-6<x<=8}

=>D=(-6;8]

Biểu diễn:

e: E={x∈R|1/2<=x<=5/2}

=>E=\(\left\lbrack\frac12;\frac52\right\rbrack\)

Biểu diễn:

f: x-1<0

=>x<1

=>F=(-∞;1)

Biểu diễn:

a: \(\frac{2x+2}{5}+\frac{3}{10}<\frac{3x-2}{4}\)

=>\(\frac{4\left(2x+2\right)}{20}+\frac{6}{20}<\frac{5\left(3x-2\right)}{20}\)

=>4(2x+2)+6<5(3x-2)

=>8x+8+6<15x-10

=>8x+14<15x-10

=>-7x<-24

=>\(x>\frac{24}{7}\)

b: \(\frac{2+x}{3}<\frac{3+2x}{5}\)

=>\(\frac{x+2}{3}-\frac{2x+3}{5}<0\)

=>\(\frac{5\left(x+2\right)-3\left(2x+3\right)}{15}<0\)

=>5(x+2)-3(2x+3)<0

=>5x+10-6x-9<0

=>-x+1<0

=>-x<-1

=>x>1

d: \(1+\frac{3\left(x+1\right)}{10}>\frac{x-2}{5}\)

=>\(\frac{10+3\left(x+1\right)}{10}>\frac{2\left(x-2\right)}{10}\)

=>3(x+1)+10>2(x-2)

=>3x+3+10>2x-4

=>3x+13>2x-4

=>3x-2x>-4-13

=>x>-17

e: \(\frac{2x-7}{6}\ge\frac{3x-7}{2}\)

=>\(\frac{2x-7}{6}\ge\frac{3\left(3x-7\right)}{6}\)

=>2x-7>=3(3x-7)

=>2x-7>=9x-21

=>-7x>=-14

=>x<=2

f: \(\frac{2x-1}{3}>\frac{3x+1}{2}\)

=>\(\frac{2x-1}{3}-\frac{3x+1}{2}>0\)

=>\(\frac{2\left(2x-1\right)-3\left(3x+1\right)}{6}>0\)

=>2(2x-1)-3(3x+1)>0

=>4x-2-9x-3>0

=>-5x-5>0

=>5x+5<0

=>5x<-5

=>x<-1