\(\frac{1}{2}+\frac{5}{6}+\frac{11}{12}+\frac{19}{20}+...+\frac{89}{90}\)

\(=1-\frac{1}{2}+1-\frac{1}{6}+1-\frac{1}{12}+1-\frac{1}{20}+...+1-\frac{1}{90}\)

\(=9-\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{90}\right)\)

\(=9-\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{9.10}\right)\)

\(=9-\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+....+\frac{1}{9}-\frac{1}{10}\right)\)

\(=9-\left(1-\frac{1}{10}\right)\)

\(=9-\frac{9}{10}=\frac{81}{10}\)

a: 1152-(374+1152)+(-65+374)

=1152-374-1152-65+374

=(1152-1152)+(-374+374)-65

=0+0-65

=-65

b: \(\left\lbrack53+\left(-76\right)\right\rbrack-\left\lbrack-76-\left(-53\right)\right\rbrack\)

\(=\left\lbrack53-76\right\rbrack-\left\lbrack-76+53\right\rbrack\)

=0

c: \(-48+48\cdot\left(-78\right)+21\cdot\left(-48\right)\)

\(=\left(-48\right)\left(1+78+21\right)\)

\(=-48\cdot100=-4800\)

d:Sửa đề: \(\left(-12\right)\cdot47+\left(-12\right)\cdot52+\left(-12\right)\)

\(=\left(-12\right)\left(47+52+1\right)\)

\(=-12\cdot100=-1200\)

e: \(\left(-1\right)+\left(-3\right)+\cdots+\left(-199\right)+\left(-201\right)\)

=-(1+3+...+199+201)

Số số hạng của dãy số 1;3;...;199;201 là:

\(\frac{201-1}{2}+1=\frac{200}{2}+1=100+1=101\) (số)

Tổng của dãy số 1;3;...;199;201 là:

\(\left(201+1\right)\cdot\frac{101}{2}=202\cdot\frac{101}{2}=101\cdot101=10201\)

=>(-1)+(-3)+...+(-199)+(-201)=-10201

f:

Số số hạng hạng trong dãy số 17;20;23;..;53;56 là:

(56-17):3+1=39:3+1=13+1=14(số)

17+(-20)+23+(-26)+...+53+(-56)

=(17-20)+(23-26)+...+(53-56)

=(-3)+(-3)+...+(-3)

\(=-3\cdot\frac{14}{2}=-21\)

a: \(\dfrac{8}{18}+\dfrac{5}{3}=\dfrac{4}{9}+\dfrac{5}{3}=\dfrac{4}{9}+\dfrac{15}{9}=\dfrac{4+15}{9}=\dfrac{19}{9}\)

b: \(\dfrac{8}{24}+\dfrac{4}{48}=\dfrac{1}{3}+\dfrac{1}{12}=\dfrac{4}{12}+\dfrac{1}{12}=\dfrac{4+1}{12}=\dfrac{5}{12}\)

c: \(\dfrac{20}{15}-\dfrac{4}{45}=\dfrac{4}{3}-\dfrac{4}{45}=\dfrac{60}{45}-\dfrac{4}{45}=\dfrac{60-4}{45}=\dfrac{56}{45}\)

d: \(\dfrac{40}{32}-\dfrac{1}{2}=\dfrac{5}{4}-\dfrac{1}{2}=\dfrac{5-2}{4}=\dfrac{3}{4}\)

ủa r bài nào?

Ở trong sgk hả?

a 11gioư116 phút

a)\(A=\frac{2}{3}+\frac{2}{6}+\frac{2}{12}+\frac{2}{24}+\frac{2}{48}+\frac{2}{96}+\frac{2}{192}\)

\(\frac{1}{2}xA=\frac{1}{3}+\frac{1}{6}+\frac{1}{12}+\frac{1}{24}+\frac{1}{48}+\frac{1}{96}+\frac{1}{192}\)

\(\frac{1}{4}xA=\frac{1}{6}+\frac{1}{12}+\frac{1}{24}+\frac{1}{48}+\frac{1}{96}+\frac{1}{192}+\frac{1}{384}\)

\(\frac{1}{4}xA-\frac{1}{2}xA=\frac{1}{3}-\frac{1}{384}\)

\(\frac{1}{4}xA=\frac{127}{384}\)

\(A=\frac{127}{384}:\frac{1}{4}\)

\(A=\frac{127}{96}\)

\(\frac{1}{2}+\frac{5}{6}+\frac{11}{12}+\frac{19}{20}+...+\frac{89}{90}\)

\(=1-\frac{1}{2}+1-\frac{1}{6}+1-\frac{1}{12}+1-\frac{1}{20}+...+1-\frac{1}{90}\)

\(=9-\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{90}\right)\)

\(=9-\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{9.10}\right)\)

\(=9-\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+....+\frac{1}{9}-\frac{1}{10}\right)\)

\(=9-\left(1-\frac{1}{10}\right)\)

\(=9-\frac{9}{10}=\frac{81}{10}\)

a)Vậy 24 phút 12 giây : 4 = 6 phút 3 giây.

b)Vậy 35 giờ 40 phút : 5 = 7 giờ 8 phút.

c)Vậy: 10 giờ 48 phút : 9 = 1 giờ 12 phút.

d)Vậy: 18,6 phút : 6 = 3,1 phút.

a) 24 phút 12 giây  4;

b) 35 giờ 40 phút  5;

c) 10 giờ 48 phút  9;

d) 18,6 phút  6.

a: \(-177-\left\lbrack89+\left(-177\right)+75\right\rbrack-\left(-25\right)\)

=-177-[89-177+75]+25

=-177-89+177-75+25

=-89-50

=-139

b: \(2\cdot\left\lbrack16+\left(-12\right)-5\right\rbrack+\left(-32\right)-\left(-10\right)\)

\(=2\cdot\left\lbrack16-17\right\rbrack-32+10\)

=2*(-1)-32+10

=-34+10

=-24

c: \(56\cdot53-\left\lbrack57+\left(-75\right)-\left(-9\right)\cdot2\right\rbrack\)

=2968-[57-75+18]

=2968

d: \(16\cdot\left(-45\right)+16\cdot34-\left(-16\right)\cdot\left(-89\right)\)

\(=16\left(-45+34\right)-16\cdot89\)

\(=16\left(-11-89\right)=16\cdot\left(-100\right)=-1600\)

e: \(77\cdot18-\left(-77\right)\cdot60+\left(-77\right)\cdot\left(-22\right)\)

\(=77\cdot18+77\cdot60+77\cdot22\)

\(=77\left(18+60+22\right)=77\cdot100=7700\)