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59 + 18 + 1 = ...
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\(\dfrac{\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+...+\dfrac{1}{20}}{\dfrac{19}{1}+\dfrac{18}{2}+\dfrac{17}{3}+....+\dfrac{1}{19}}\)
\(=\dfrac{\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+...+\dfrac{1}{20}}{1+\left(\dfrac{18}{2}+1\right)+\left(\dfrac{17}{3}+1\right)+\left(\dfrac{1}{19}+1\right)}\)
\(=\dfrac{\dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{20}}{1+\dfrac{20}{2}+\dfrac{20}{3}+...+\dfrac{20}{19}}\)
\(=\dfrac{\dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{20}}{20.\left(\dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{19}+\dfrac{1}{20}\right)}\)
\(=\dfrac{1}{20}\)
1)
a) \(34,2:36=0,95\)
b) \(36,18:18=2,01\)
c) \(5,05:25=0,202\)
d) \(17,25:75=0,23\)
2)
a) \(75,52:32=2,36\)
b) \(4,68:13=0,36\)
c) \(81,6:34=2,4\)
d) \(134,4:42=3,2\)
3)
a) \(882:36=24,5\)
b) \(78:24=3,25\)
c) \(3:15=0,2\)
d) \(15:75=0,2\)
4)
a) \(3:75=0,04\)
b) \(750:300=2,5\)
c) \(390:12=32,5\)
d) \(54:24=2,25\)
12 - 1 = 11 13 - 1 = 12 14 - 1 = 13
17 - 5 = 12 18 - 2 = 16 19 - 8 = 11
14 - 0 = 14 16 - 0 = 16 18 - 0 = 18
\(\frac{11}{19}+\frac{19}{18}+\frac{8}{19}-\frac{1}{18}+5,2\)
\(=\left(\frac{11}{19}+\frac{8}{19}\right)+\left(\frac{19}{18}-\frac{1}{18}\right)+5,2\)
\(=1+1+5,2\)
\(=7,2\)
\(\frac{11}{19}+\frac{19}{18}+\frac{8}{19}-\frac{1}{18}+5,2\)
\(=\left(\frac{11}{19}+\frac{8}{19}\right)+\left(\frac{19}{18}-\frac{1}{18}\right)+5,2\)
\(=\frac{19}{19}+\frac{18}{18}+5,2\)
\(=1+1+5,2=7,2\)
\(\dfrac{18}{17}:9=\dfrac{18}{17}\times\dfrac{1}{9}=\dfrac{18}{153}=\dfrac{2}{17}\)
\(\dfrac{8}{5}-\dfrac{18}{27}=\dfrac{216}{135}-\dfrac{90}{135}=\dfrac{126}{135}=\dfrac{14}{15}\)
\(\dfrac{2}{7}+\dfrac{5}{9}=\dfrac{18}{63}+\dfrac{35}{63}=\dfrac{53}{63}\)
\(18\times32+43\times18+18\times26-18\)
\(=18\times\left(32+43+26-1\right)\)
\(=18\times100\)
\(=1800\)
18 * 32 + 43 * 18 + 18 * 26 - 18
= 18 * ( 32 + 43 + 26 - 1 )
= 18 * 100
= 1800
Có số số hạng là :
( 100 - 1 ) : 3 + 1 = 34 ( số )
Tổng là :
( 100 + 1 ) x 34 : 2 + 83 = 1800
Ta có 59 + 18 + 1 = 59 + 1 + 18 = 60 + 18 = 78
Vậy số cần điền vào chỗ trống là 78