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a: 1/x^2y=1/x^2y
3/xy=3x/x^2y
b: \(\dfrac{x}{x^2+2xy+y^2}=\dfrac{x}{\left(x+y\right)^2}\)
\(\dfrac{2x}{x^2+xy}=\dfrac{2}{x+y}=\dfrac{2x+2y}{\left(x+y\right)^2}\)
MT1: x – y
MT2: 1
MTC: x – y
NTP1: 1; NTP2: x – y.
Quy đồng:

\(\dfrac{1}{3x+xy}=\dfrac{1}{x\left(y+3\right)}=\dfrac{\left(x+y\right)^2}{x\left(y+3\right)\left(x+y\right)^2}\)
\(2x+2y=2\left(x+y\right)=\dfrac{2\left(x+y\right)\cdot x\left(y+3\right)\left(x+y\right)^2}{x\left(y+3\right)\left(x+y\right)^2}\)
\(\dfrac{1}{x^2+2xy+y^2}=\dfrac{3x+xy}{x\left(y+3\right)\left(x+y\right)^2}\)
\(\dfrac{1}{3x+3y}=\dfrac{1}{3\left(x+y\right)}=\dfrac{2\cdot\left(x+y\right)}{6\left(x+y\right)^2}\)
\(\dfrac{1}{2x+2y}=\dfrac{1}{2\left(x+y\right)}=\dfrac{3\left(x+y\right)}{6\left(x+y\right)^2}\)
\(\dfrac{1}{x^2+2xy+y^2}=\dfrac{1}{\left(x+y\right)^2}=\dfrac{6}{6\left(x+y\right)^2}\)
a: \(\frac{x}{x-y}=\frac{x\cdot\left(x-y\right)^2}{\left(x-y\right)\left(x-y\right)^2}=\frac{x\left(x-y\right)^2}{\left(x-y\right)^3}\)
\(\frac{y}{\left(x-y\right)^2}=\frac{y\left(x-y\right)}{\left(x-y\right)^2\cdot\left(x-y\right)}=\frac{y\left(x-y\right)}{\left(x-y\right)^3}\)
\(\frac{1}{\left(y-x\right)^3}=\frac{-1}{\left(x-y\right)^3}\)
b: \(\frac{1}{2x+4}=\frac{1}{2\left(x+2\right)}=\frac{1\cdot\left(x-2\right)}{2\left(x+2\right)\left(x-2\right)}=\frac{x-2}{2\left(x+2\right)\left(x-2\right)}\)
\(\frac{x}{2x-4}=\frac{x}{2\left(x-2\right)}=\frac{x\left(x+2\right)}{2\left(x-2\right)\left(x+2\right)}\)
\(\frac{3}{4-x^2}=\frac{-3}{x^2-4}=\frac{-3}{\left(x-2\right)\left(x+2\right)}=\frac{-3\cdot2}{2\left(x-2\right)\left(x+2\right)}=\frac{-6}{2\left(x-2\right)\left(x+2\right)}\)




Mẫu thức chung: 36 x 2 y 4
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