C

C

Phương pháp giải:

Muốn tìm một số hạng ta lấy tổng trừ đi số hạng kia.

Lời giải chi tiết:

a) x + 16 = 32

    x = 32 − 16

    x = 16

b) x + 27 = 52

    x = 52 − 27

    x = 25

c) 36 + x = 42

    x = 42 − 36

    x = 6

Bấm vào chữ "Đúng 0" là hiện ra câu trả lời của mik ák

a, x + 32...  .<......41+  x
b,56- y .. >  ..... 45-y
c, x-26 ..<.  ......x-18
d,42 + 21 + x...> .... 42+ 21
g, 52- 47..> ..... 52-47-x
h, 29+ 42- x..<. 42+29+ x

Học tốt!!!

#Bo

a: \(3^2\cdot\frac{1}{243}\cdot81^2\cdot\frac{1}{3^2}\)

\(=\frac{3^2}{3^5}\cdot\frac{3^8}{3^2}=\frac{1}{3^3}\cdot3^6=3^3=27\)

b: \(4^6\cdot256^2\cdot2^4=\left(2^2\right)^6\cdot\left(2^8\right)^2\cdot2^4\)

\(=2^{12}\cdot2^{16}\cdot2^4=2^{12}\cdot2^{20}=2^{32}\)

c: \(4^6\cdot9^5+6^9\cdot120\)

\(=2^{12}\cdot3^{10}+2^9\cdot3^9\cdot2^3\cdot3\cdot5\)

\(=2^{12}\cdot3^{10}+2^{12}\cdot3^{10}\cdot5\)

\(=2^{12}\cdot3^{10}\cdot6=2^{13}\cdot3^{11}\)

Ta có \(8^4\cdot3^{12}-6^{11}\)

\(=2^{12}\cdot3^{12}-2^{11}\cdot3^{11}\)

\(=2^{11}\cdot3^{11}\left(2\cdot3-1\right)=2^{11}\cdot3^{11}\cdot5\)

Ta có: \(A=\frac{4^6\cdot9^5+6^9\cdot120}{8^4\cdot3^{12}-6^{11}}\)

\(=\frac{2^{13}\cdot3^{11}}{2^{11}\cdot3^{11}\cdot5}=\frac{2^2}{5}=\frac45\)

d: \(4^2\cdot25^2+32\cdot125\)

\(=2^4\cdot5^4+2^5\cdot5^3\)

\(=2^4\cdot5^3\left(5+2\right)=2^4\cdot5^3\cdot7\)

\(B=\frac{4^2\cdot25^2+32\cdot125}{2^3\cdot5^2}\)

\(=\frac{2^4\cdot5^3\cdot7}{2^3\cdot5^2}=2\cdot5\cdot7=70\)

4 2 .   25 2 +   32.   125 2 3 .   5 2 = 2 4 .5 4 + 2 5 .5 3 2 3 .5 2 = 2 4 .5 3 5 + 2 2 3 .5 2 = 2.5.7 = 70

số 0 nha bạn 

chac la 4 do

a: 72-19+2021

=53+2021

=2074

b: \(6\cdot5^2-16:2^2\)

\(=6\cdot25-16:4\)

=150-4

=146

c: \(375:\left\lbrace32-\left\lbrack4+\left(5\cdot3^2-42\right)\right\rbrack\right\rbrace-14\)

=375:{32-[4+(5*9-42)]}-14

=375:{32-4-3}-14

=375:25-14

=15-14

=1

12 + 22 + 32 + 42 + 52 + 62 = 222

bạn k mình, mình k lại

12 + 22 + 32 + 42 + 52 + 62 = 222

k mk , mk k lai

\(\dfrac{2^2}{1\times3}\times\dfrac{3^2}{2.4}\times\dfrac{4^2}{3.5}\times\dfrac{5^2}{4.6}=\dfrac{2^2.3^2.4^2.5^2}{1.3.2.4.3.5.4.6}=\dfrac{2^2.3^2.4^2.5^2}{1.2.3.3.4.4.5.2.3}=\dfrac{2^2.3^2.4^2.5^2}{3^3.2^2.4^2.5.1}=\dfrac{5}{3.1}=\dfrac{5}{3}\)

\(\dfrac{2^2}{1\cdot3}\cdot\dfrac{3^2}{2\cdot4}\cdot\dfrac{4^2}{3\cdot5}\cdot\dfrac{5^2}{4.6}\\ =\dfrac{2^2\cdot3^2\cdot4^2\cdot5^2}{1\cdot3\cdot2\cdot4\cdot3\cdot5\cdot4\cdot6}\\ =\dfrac{2^2\cdot3^2\cdot4^2\cdot5^2}{1\cdot2\cdot4^2\cdot4^2\cdot5\cdot6}\\ =\dfrac{2\cdot5}{6}=\dfrac{5}{3}\)

a.( 15 + 37 ) + ( 2 - 37 - 17 )

= 15 + 37 + 52 - 37 - 17

= 15 + (37 - 37) + (52 - 17)

= 15 + 0 + 35

= 50

b.- ( 21 - 32 ) - ( -12 + 32 )

= 21 + 32 + 12 - 32

= ( 21 + 12 ) + ( 32 - 32 ) 

= 9 + 0 

= 9

c ( 38 - 42 + 14) - ( 25 - 27 - 15 )

= 38 - 42 + 14 + (-25) + 27 + 15 

= (38 - 42 + 14) + [( -25 ) + 15] + 27

= 10 + (-10) + 27

= 0 + 27

= 27

#ht