\(7x-\left(33:3\right)\cdot4=5\\ \Leftrightarrow7x=49\\ \Leftrightarrow x=7\)

Vậy x = 7.

7x - ( 33 : 3 ) x 4 = 5

7x - 5 = 11 x 4 = 44

7x = 49

x = 7

1: \(\dfrac{4}{23}+\dfrac{5}{21}+\dfrac{1}{2}-\dfrac{4}{23}+\dfrac{16}{21}\)

\(=1+\dfrac{1}{2}\)

\(=\dfrac{3}{2}\)

2: \(\left(\dfrac{1}{3}+\dfrac{12}{67}+\dfrac{13}{41}\right)-\left(\dfrac{79}{67}-\dfrac{28}{41}\right)\)

\(=\dfrac{1}{3}+\dfrac{12}{67}+\dfrac{13}{41}-\dfrac{79}{67}+\dfrac{28}{41}\)

\(=\dfrac{1}{3}\)

a: Đặt \(A=\frac{\left(x+11\right)^3}{\left(2x+22\right)^2}\)

\(=\frac{\left(x+11\right)^3}{4\left(x+11\right)^2}=\frac{x+11}{4}\)

THay x=-12 vào A, ta được:

\(A=\frac{-12+11}{4}=-\frac14\)

a: 7x+58=100

nên 7x=42

hay x=6

c: x-56:x=16

nên x-14=16

hay x=30

c)x - 56 : 4  = 16

x - 56       = 16 : 4 

x- 56        = 4

x               =4 + 56

x               = 60 

d)101 + (36 - 4x) = 105 

          (36- 4x ) = 105 - 101 

          36 - 4x = 4

                4x = 36 - 4 

                4x = 32

                  x = 32:4

                  x = 8

a: Ta có: \(7x+25=144\)

\(\Leftrightarrow7x=119\)

hay x=17

b: Ta có: \(33-12x=9\)

\(\Leftrightarrow12x=24\)

hay x=2

c: Ta có: \(128-3\left(x+4\right)=23\)

\(\Leftrightarrow3\left(x+4\right)=105\)

\(\Leftrightarrow x+4=35\)

hay x=31

d: Ta có: \(71+\left(726-3x\right)\cdot5=2246\)

\(\Leftrightarrow5\left(726-3x\right)=2175\)

\(\Leftrightarrow726-3x=435\)

\(\Leftrightarrow3x=291\)

hay x=97

e: Ta có: \(720:\left[41-\left(2x+5\right)\right]=40\)

\(\Leftrightarrow41-\left(2x+5\right)=18\)

\(\Leftrightarrow2x+5=23\)

\(\Leftrightarrow2x=18\)

hay x=9

Bn cần bài nào vậy

\(2A\left(x\right)-B\left(x\right)=2\left(-3x^4+3x^3+7x^2-6x-2\right)-\left(-5x^4+2x^3-x^2+7\right)\)

\(=-6x^4+6x^3+14x^2-12x-4+5x^4-2x^3+x^2-7\)

\(\Rightarrow2A\left(x\right)-B\left(x\right)=-x^4+4x^3+15x^2-12x-11\)

a: \(6^{x}:3^3:4=2\)

=>\(6^{x}=2\cdot4\cdot3^3=2^3\cdot3^3=6^3\)

=>x=3

b: \(3\left(x-5\right)^3=81\)

=>\(\left(x-5\right)^3=\frac{81}{3}=27=3^3\)

=>x-5=3

=>x=3+5=8

c: \(7x-2x=6^{17}:6^{15}+3^8:2^6\)

=>\(5x=6^2+\frac{3^8}{2^6}=36+\frac{6561}{64}=\frac{8865}{64}\)

=>\(x=\frac{8865}{64}:5=\frac{1773}{64}\)

1/ (x-63)(x+10)(4x² -188x-2520)

2/ 9(x-1)(2x-1)(64x² + 208x+32)/8