Bài 1:

a.\(\left(x+y\right)^2-\left(x-y\right)^2=\left(x+y-x+y\right)\left(x+y+x-y\right)=2\left(x+y\right)\)

b.\(2\left(x+y\right)\left(x-y\right)+\left(x+y\right)^2+\left(x-y\right)^2=\left(x+y+x-y\right)^2=4x^2\)

a) Ta có: \(\dfrac{x^2}{y^2}:\sqrt{\dfrac{x^2}{y^4}}\)

\(=\dfrac{x^2}{y^2}:\dfrac{x}{y^2}\)

=x

b) Ta có: \(\sqrt{\dfrac{27\left(x-1\right)^2}{12}}+\dfrac{3}{2}-\left(x-2\right)\sqrt{\dfrac{50x^2}{8\left(x-2\right)^2}}\)

\(=\sqrt{\dfrac{9}{4}}\cdot\sqrt{\left(x-1\right)^2}+\dfrac{3}{2}-\left(x-2\right)\cdot\sqrt{\dfrac{25}{4}}\cdot\sqrt{\dfrac{x^2}{\left(x-2\right)^2}}\)

\(=\dfrac{3}{2}\cdot\left(x-1\right)+\dfrac{3}{2}-\left(x-2\right)\cdot\dfrac{5}{2}\cdot\dfrac{x}{2-x}\)

\(=\dfrac{3}{2}x-\dfrac{3}{2}+\dfrac{3}{2}-\dfrac{5}{2}\left(x-2\right)\cdot\dfrac{-x}{x-2}\)

\(=\dfrac{3}{2}x+\dfrac{5}{2}\cdot\left(x\right)\)

=4x

em cảm ơn ạ 

đã tắt máy chưa để cho mình giải nha

Giúp mik nha mọi người :)

a) Ta có: \(\left(3x-2\right)^2+2\left(3x-2\right)\left(3x+2\right)+\left(3x+2\right)^2\)

\(=\left(3x-2+3x+2\right)^2\)

\(=36x^2\)(1)

Thay \(x=-\dfrac{1}{3}\) vào biểu thức (1), ta được:

\(36\cdot\left(-\dfrac{1}{3}\right)^2=36\cdot\dfrac{1}{9}=4\)

b) Sửa đề: \(\left(x+y-7\right)^2-2\cdot\left(x+y-7\right)\left(y-6\right)+\left(y-6\right)^2\)

Ta có: \(\left(x+y-7\right)^2-2\cdot\left(x+y-7\right)\left(y-6\right)+\left(y-6\right)^2\)

\(=\left(x+y-7-y+6\right)^2\)

\(=\left(x-1\right)^2=100^2=10000\)

5: \(=\dfrac{1}{x-y}\cdot x^3\cdot\left(x-y\right)^2=x^3\left(x-y\right)\)

a: ĐKXĐ: x<>y; x<>1/2; x<>-2

b:

\(\left(\frac{x+y}{y}-\frac{2y}{y-x}\right):\frac{x^2+y^2}{y-x}\)

\(=\frac{\left(y+x\right)\left(y-x\right)-2y^2}{y\left(y-x\right)}\cdot\frac{y-x}{x^2+y^2}\)

\(=\frac{-x^2-y^2}{y\left(x^2+y^2\right)}=\frac{-1}{y}\)

\(\left(\frac{x^2+1}{2x-1}-\frac{x}{2}\right)\cdot\frac{1-2x}{x+2}\)

\(=\frac{2\left(x^2+1\right)-x\left(2x-1\right)}{2\left(2x-1\right)}\cdot\frac{-\left(2x-1\right)}{x+2}\)

\(=\frac{2x^2+2-2x^2+x}{2}\cdot\frac{-1}{x+2}=\frac{x+2}{-2\left(x+2\right)}=\frac{-1}{2}\)

Ta có: \(A=\left(\frac{x+y}{y}-\frac{2y}{y-x}\right):\frac{x^2+y^2}{y-x}+\left(\frac{x^2+1}{2x-1}-\frac{x}{2}\right)\cdot\frac{1-2x}{x+2}\)

\(=\frac{-1}{y}+\frac{-1}{2}=\frac{-y-2}{2y}\)