a. 18/72 = 1/4

    15/20 = 3/4

vì 1/4<3/4 nên 18/72<15/20

b. 24/36 = 2/3

    20/50 = 2/5

2/3>2/5 nên 24/36>20/50

a, \(\dfrac{18}{72}\) = \(\dfrac{18:18}{72:18}\) = \(\dfrac{1}{4}\);     \(\dfrac{15}{20}\) = \(\dfrac{3}{4}\)

     Vì \(\dfrac{1}{4}\) < \(\dfrac{3}{4}\)  nên \(\dfrac{18}{72}\) < \(\dfrac{15}{20}\)

b, \(\dfrac{24}{36}\) = \(\dfrac{24:12}{36:12}\) = \(\dfrac{2}{3}\);          \(\dfrac{20}{50}\) = \(\dfrac{20:10}{50:10}\) = \(\dfrac{2}{5}\)

Vì \(\dfrac{2}{3}\) > \(\dfrac{2}{5}\) nên \(\dfrac{24}{36}\) > \(\dfrac{20}{50}\) 

a>\(16^{19}=2^{4^{19}}=2^{76}\\ 8^{25}=2^{3^{25}}=2^{75}\)

16^19>8^25

a) 28 = 2 2 . 7 ; 70 = 2.5.7 .Vậy ƯCLN(28,70) = 2.7 = 14

b) ƯCLN(36, 60,72) =12

c) ƯCLN(60,180) = 60

d) ƯCLN(28, 39, 35) = 1

Bài 1:

a: Cách 1: \(\frac37=\frac{3\cdot9}{7\cdot9}=\frac{27}{63};\frac59=\frac{5\cdot7}{9\cdot7}=\frac{35}{63}\)

mà 27<35

nên \(\frac37<\frac59\)

Cách 2: Ta có: \(\frac37=\frac{3\cdot5}{7\cdot5}=\frac{15}{35}\)

\(\frac59=\frac{5\cdot3}{9\cdot3}=\frac{15}{27}\)

mà \(\frac{15}{35}<\frac{15}{27}\left(35>27\right)\)

nên \(\frac37<\frac59\)

b: Cách 1: \(\frac{6}{12}=\frac{6\cdot3}{12\cdot3}=\frac{18}{36};\frac49=\frac{4\cdot4}{9\cdot4}=\frac{16}{36}\)

mà 18>16

nên \(\frac{6}{12}>\frac49\)

Cách 2: \(\frac{6}{12}=\frac{6\cdot2}{12\cdot2}=\frac{12}{24};\frac49=\frac{4\cdot3}{9\cdot3}=\frac{12}{27}\)

mà \(\frac{12}{24}>\frac{12}{27}\left(24<27\right)\)

nên \(\frac{6}{12}>\frac49\)

c: Cách 1: \(\frac{15}{25}=\frac{15\cdot18}{25\cdot18}=\frac{270}{450};\frac{54}{90}=\frac{54\cdot5}{90\cdot5}=\frac{270}{450}\)

Do đó: \(\frac{15}{25}=\frac{54}{90}\)

Cách 2: \(\frac{15}{25}=\frac{15:5}{25:5}=\frac35;\frac{54}{90}=\frac{54:18}{90:18}=\frac35\)

do đó: \(\frac{15}{25}=\frac{54}{90}\)

d: Cách 1: \(\frac{25}{30}=\frac{25\cdot3}{30\cdot3}=\frac{75}{90};\frac{75}{28}=\frac{75\cdot1}{28\cdot1}=\frac{75}{28}\)

mà \(\frac{75}{90}<\frac{75}{28}\left(90>28\right)\)

nên \(\frac{25}{30}<\frac{75}{28}\)

Cách 2: \(\frac{25}{30}=\frac{25\cdot14}{30\cdot14}=\frac{350}{420}\)

\(\frac{75}{28}=\frac{75\cdot15}{28\cdot15}=\frac{1125}{420}\)

mà 350<1125

nên \(\frac{25}{30}<\frac{75}{28}\)

e: cách 1: \(\frac{27}{45}=\frac{27\cdot4}{45\cdot4}=\frac{108}{180};\frac{18}{36}=\frac{18\cdot5}{36\cdot5}=\frac{90}{180}\)

mà 108>90

nên \(\frac{27}{45}>\frac{18}{36}\)

Cách 2: \(\frac{27}{45}=\frac{27\cdot2}{45\cdot2}=\frac{54}{90}\)

\(\frac{18}{36}=\frac{18\cdot3}{36\cdot3}=\frac{54}{108}\)

mà \(\frac{54}{90}>\frac{54}{108}\left(90<108\right)\)

nên \(\frac{27}{45}>\frac{18}{36}\)

12/18=2/3=36/54

a. Ta có: \(5^{36}=\left(5^3\right)^{12}=125^{12}\)

\(11^{24}=\left(11^2\right)^{12}=121^{12}\)

\(Do\)\(125^{12}>121^{12}\Rightarrow5^{36}>11^{24}\)

b) Ta có; \(6.5^{22}>5.5^{22}=5^{23}\)

d) Ta có: \(72^{45}-72^{44}=72^{44}\left(72-1\right)=72^{44}.71\)

\(72^{44}-72^{43}=72^{43}\left(72-1\right)=72^{43}.71\)

Do \(72^{44}.71>72^{43}.71\Rightarrow72^{45}-72^{44}>72^{44}-72^{43}\)

help me

umm, bn nhân A với 1/7 và nhân B với 1/9, sau đó tính ra và so sánh thôi