=>x(x^2-9/16)=0

=>x(x-3/4)(x+3/4)=0

=>x=0; x=3/4; x=-3/4

\(a,x-1⋮x-3\)

\(\Rightarrow x-3+2⋮x-3\)

\(\Rightarrow2⋮x-3\)

\(x-3=\left\{-2;-1;1;2\right\}\)

\(x=\left\{1;2;4;5\right\}\)

\(b,x+6⋮x-1\)

\(\Rightarrow x-1+7⋮x-1\)

\(\Rightarrow7⋮x-1\)

\(x=\left\{-6;0;2;8\right\}\)

\(c,x⋮x-5\)

\(x-5+5⋮x-5\)

\(5⋮x-5\)

\(x=\left\{0;4;6;11\right\}\)

Ta có : a mũ chẵn \(\ge\)0.

=>\(2\times y-8=0\)

=> 2 x y = 8

=> y = 4

Ta có : 2x-y = 0.

=> 2x=y=8

=>x= 4

x = 2 nhé.

Voi x la so nguyen

\(\Rightarrow\hept{\begin{cases}3x-2=-x+4\Rightarrow\\3x-2=x-4\Rightarrow\end{cases}\hept{\begin{cases}x=loại\\x=-1\end{cases}}}\)

\(\Rightarrow\)trị tuyệt đối 3x-2= -x +9-5=-x+4

\(\Rightarrow\hept{\begin{cases}3x-2=-x+4\Rightarrow\\3x-2=x-4\Rightarrow\end{cases}\hept{\begin{cases}x=loại\\x=-1\end{cases}}}\)

\(-12.\left(x-5\right)+7.\left(3-x\right)=5\)

\(-12x+60+21-7x=5\)

\(-12x-7x+81=5\)

\(-19x+81=5\)

\(-19x=5-81\)

\(-19x=-76\)

\(x=\left(-76\right):\left(-19\right)\)

\(x=4\)

Học tốt nhé bn !!!!!

-12 ( x- 5 ) + 7.(3-x) =5

 -12x+60+21-7x      =5

60+21-5                   =12x+7x

76                            =19x

x                              = 76:19

x                              =    4

câu b

Q-14y^4+6y^3=-12y^2

Q=\(-12y^5+y^4-1-14y^4+6y^5-3\)

Q=\(-6y^5-13y^4-4\)

a) \(P+\left(3x^2-4+5x\right)=x^2-4x\)

\(\Rightarrow P=x^2-4x-\left(3x^2-4+5x\right)\)

\(\Rightarrow P=x^2-4x-3x^2+4-5x\)

\(\Rightarrow P=\left(x^2-3x^2\right)+\left(-4x-5x\right)+4=-2x^2-9x+4\)

b) Q ở đâu,sao ko thấy?

a, số x = 0

b, x : 4 = 5 dư 3

x = 5 x 4 ( dư 3 )

x = 20 + 3

x = 23

a , x : 9 = x

x : 9 = 9

x = 9 x 9 = 81

b, x : 4 = 5 dư 3

x : 4 = 8

x = 8 x 4

= 32