Đặt \(A=\frac{1}{1\cdot3}+\frac{1}{3\cdot5}+\cdots+\frac{1}{19\cdot21}\)

\(=\frac12\left(\frac{2}{1\cdot3}+\frac{2}{3\cdot5}+\cdots+\frac{2}{19\cdot21}\right)\)

\(=\frac12\left(1-\frac13+\frac13-\frac15+\cdots+\frac{1}{19}-\frac{1}{21}\right)\)

\(=\frac12\left(1-\frac{1}{21}\right)=\frac12\cdot\frac{20}{21}=\frac{10}{21}\)

Ta có: \(\left(\frac{1}{1\cdot3}+\frac{1}{3\cdot5}+\cdots+\frac{1}{19\cdot21}\right)\cdot420-\frac{\left\lbrack0,4\left(7,5-2,5x\right)\right\rbrack}{0,25}=212\)

=>\(420\cdot\frac{10}{21}-\frac{3-x}{0,25}=212\)

=>200-4(3-x)=212

=>200+4(x-3)=212

=>4(x-3)=12

=>x-3=3

=>x=6

A(x) ở đâu

 tìm A(x) biết A(x)=M(x)-N(x) ko thấy à 

Cái chỗ 1;1/2 là gì vậy bạn?

; là ngăn cách P vs M

Bài 3: 

a) Đặt f(x)=0

\(\Leftrightarrow x^2-4x+3=0\)

\(\Leftrightarrow\left(x-1\right)\left(x-3\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-1=0\\x-3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1\\x=3\end{matrix}\right.\)

b) Đặt f(x)=0

\(\Leftrightarrow x^2-7x+12=0\)

\(\Leftrightarrow\left(x-3\right)\left(x-4\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-3=0\\x-4=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=4\end{matrix}\right.\)

Bài 3:

c) Đặt f(x)=0

\(\Leftrightarrow x^2+2x+1=0\)

\(\Leftrightarrow\left(x+1\right)^2=0\)

\(\Leftrightarrow x+1=0\)

hay x=-1

d) Đặt f(x)=0

\(\Leftrightarrow x^4+2=0\)

\(\Leftrightarrow x^4=-2\)(Vô lý)

\(a,12,3\cdot4,7+5,3\cdot12,3-1,4\cdot7,5+7,5\cdot5,4\)

\(=12,3\cdot\left(4,7+5,3\right)-7,5\cdot\left(1,4+5,4\right)\)

\(=12,3\cdot10-7,5\cdot6,8\)

\(=123-51\)

\(=72.\)

\(b,3\cdot x-1=\frac{3}{4}:\frac{15}{16}\)

\(\Leftrightarrow3\cdot x-1=\frac{3}{4}\cdot\frac{16}{15}\)

\(\Leftrightarrow3\cdot x-1=\frac{4}{5}\)

\(\Leftrightarrow3\cdot x=\frac{4}{5}+1\)

\(\Leftrightarrow3\cdot x=\frac{9}{5}\)

\(\Leftrightarrow x=\frac{9}{5}\div3\)

\(\Leftrightarrow x=\frac{9}{5}\cdot\frac{1}{3}\)

\(\Leftrightarrow x=\frac{3}{5}\)

a) \(12,3\times4,7+5,3\times12,3-1,4\times7,5+7,5\times5,4\)

\(=12,3\times\left(4,7+5,3\right)+7,5\times\left(5,4-1,4\right)\)

\(=12,3\times10+7,5\times4\)

\(=123+30\)

\(=153\)

b) \(3.x-1=\frac{3}{4}:\frac{15}{16}\)

\(\Rightarrow3.x-1=\frac{4}{5}\)

\(\Rightarrow3.x=\frac{9}{5}\Rightarrow x=\frac{3}{5}\)

m: (x-4)(3-x)=0

=>x-4=0 hoặc 3-x=0

=>x=4 hoặc x=3

n: =>2x-10+4=2

=>2x-6=2

=>2x=8

hay x=4

h: =>2,5x-2x=3+8

=>0,5x=11

hay x=22

tui tk cho ai đúng nhe

\(a,1,3\times0,5< x< 1,8\times1,9\\ \Leftrightarrow0,65< x< 3,42\\ \Rightarrow x=1,x=2,x=3\)

\(b,2,5\times2,7< x< 2,7\times4,5\\ \Rightarrow6,75< x< 12,15\\ \Rightarrow x=7;x=8;x=9;x=10;x=11;x=12\)

Tk mình đi mọi người mình bị âm nè!

Ai tk mình mình tk lại cho!!