\(6+\frac{x}{33}=\frac{7}{11}\)

\(\Rightarrow\frac{x}{33}=\frac{7}{11}-6\)

\(\Rightarrow\frac{x}{33}=\frac{-59}{11}\)

\(\Rightarrow x=\frac{33.\left(-59\right)}{11}\)

\(\Rightarrow x=-177\)

Vậy x = -177

_Chúc bạn học tốt_

6 + \(\frac{x}{33}\) = \(\frac{7}{11}\)

       \(\frac{x}{33}\)= \(\frac{7}{11}\)- 6

       \(\frac{x}{33}\)= \(-\frac{59}{11}\)

       \(\frac{x}{33}\)= \(-\frac{177}{33}\)

        \(x\)    = \(-177\)

giải cho mình đi

giải cho mình

b;\(\frac{x}{17}=\frac{60}{204}\)

=> \(x=60.17:204=5\)

c; \(6+\frac{x}{33}=\frac{7}{11}\)

=> \(6=\frac{7}{11}-\frac{x}{33}\)

=> \(6=\frac{21}{33}-\frac{x}{33}\)

=> \(6=\frac{21-x}{33}\)

=> \(21-x=198\)

=> \(x=21-198\)

=> \(x=-117\)

a} x/17 = 60/204

=> x/17 = 5/17

=> x = 5

Vậy x = 5

b} 6 + x / 33 = 7/11

=> 6 + x / 33 = 21/33

=> 6 + x = 21

=> x = 21 - 6 = 15

Vậy x = 15

\(a.\frac{x}{17}=\frac{60}{204}\Rightarrow x=\frac{17\times60}{204}=5\)

\(6+\frac{x}{33}=\frac{7}{11}\Rightarrow\frac{198+x}{33}=\frac{7}{11}\Rightarrow198+x=\frac{33\times7}{11}=21\Rightarrow x=21-198=-177\)

Bạn nào giúp mình, mình lại 3 cái!

Mình 3 cái

a: \(8x\left(2023+x\right)-8x\left(x+2024\right)=56\)

=>\(8x\left(x+2023-x-2024\right)=56\)

=>-8x=56

=>\(x=\frac{56}{-8}=-7\) (nhận)

b: \(5-2025x=9-2026\left(x-1\right)\)

=>-2025x+5=9-2026x+2026

=>-2025x+5=-2026x+2035

=>x=2035-5=2030(nhận)

c: \(\left(-12\right)^2\cdot x=56+10\cdot13x\)

=>144x=56+130x

=>14x=56

=>x=4(nhận)

d: -(x-32+11)=(21-33-x+7)

=>-(x-21)=(-x-5)

=>-x+21=-x-5

=>21=-5(vô lý)

=>x∈∅

e: \(-2\left(x+6\right)+6\left(x+10\right)=8\)

=>-2x-12+6x+60=8

=>4x+52=8

=>4x=8-52=-44

=>\(x=-\frac{44}{4}=-11\) (nhận)

cậu làm được không?

\(\frac{x+6}{33}=\frac{7}{11}\)

33 :3=11

x+6:3=7

7 x 3=21

21-6=15

Vậy\(\frac{15+6}{33}=\frac{7}{11}\)

Bài 6:

\(21,251+6,058+0,749+1,042\)

\(=\left(21,251+0,749\right)+\left(6,058+1,042\right)\)

\(=22+7,1\)

\(=29,1\)

___________________

\(1,53+5,309+12,47+5,691\)

\(=\left(1,53+12,47\right)+\left(5,309+5,691\right)\)

\(=14+11\)

\(=25\)

5:

a: =>x/17=5/17

=>x=5

b; =>6+x=7/11*33=21

=>x=15

c: \(\dfrac{12+x}{43-x}=\dfrac{2}{3}\)

=>3x+36=86-2x

=>5x=50

=>x=10

d: \(\dfrac{x}{5}< \dfrac{3}{7}\)

=>x<3/7*5

=>x<15/7

f: 15/26+x/16=46/52

=>x/16=23/26-15/26=8/26=4/13

=>x=4/13*16=64/13