12x+12y+13x+13q+14a+14b=100000^2
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Ta có: \(x^2=y^2+z^2\)
\(\Leftrightarrow x^2-y^2=z^2\)
\(\Leftrightarrow25\left(x-y\right)\left(x+y\right)=25z^2\)
\(\Leftrightarrow\left(25x-25y\right)\left(x+y\right)=25z^2\)
\(\Leftrightarrow\left(13x-12y+12x-13y\right)\left(13x-12y-12x+13y\right)=25z^2\)
\(\Leftrightarrow\left(13x-12y\right)^2-\left(12x-13y\right)^2=25z^2\)
\(\Leftrightarrow\left(13x-12y\right)^2-\left(5z\right)^2=\left(12x-13y\right)^2\)
\(\Leftrightarrow\left(13x-12y-5z\right)\left(13x-12y+5z\right)=\left(12x-13y\right)^2\)(ĐPCM).
`12x2 + 5x – 12y2 + 12y – 10xy – 3`
`= 12x2 + 9x – 4x – 12y2 – 18xy + 8xy – 3 + 6y – 6y`
`= (12x2 – 18xy + 9x) – (4x – 6y + 3) + (8xy – 12y2 + 6y)`
`= 3x(4x – 6y + 3) – (4x – 6y + 3) + 2y(4x – 6y + 3)`
`= (4x – 6y + 3)(3x + 2y – 1).`
$12x2 + 5x – 12y2 + 12y – 10xy – 3$
$= 12x2 + 9x – 4x – 12y2 – 18xy + 8xy – 3 + 6y – 6y$
$= (12x2 – 18xy + 9x) – (4x – 6y + 3) + (8xy – 12y2 + 6y)$
$= 3x(4x – 6y + 3) – (4x – 6y + 3) + 2y(4x – 6y + 3)$
$= (4x – 6y + 3)(3x + 2y – 1).$
b) Ta có: \(B=5x\left(x-4y\right)-4y\left(y-5x\right)\)
\(=5x^2-20xy-4y^2+20xy\)
\(=5x^2-4y^2\)
\(=5\cdot\left(-\dfrac{1}{5}\right)^2-4\cdot\left(-\dfrac{1}{2}\right)^2\)
\(=5\cdot\dfrac{1}{25}-4\cdot\dfrac{1}{4}\)
\(=\dfrac{1}{5}-1=\dfrac{-4}{5}\)
12x2 + 5x - 12y2 + 12y - 10xy - 3
= -(12x2 + 10xy + 3 -12x2 - 5x - 12y)
Có
12y2 + 10xy + 3 - 12x2 - 5x - 12y
= 18xy + 12y2 - 6y - 12x2 - 8xy + 4x - 9x - 6y + 3
= 6y (3x + 2y - 1) - 4 . x (3x + 2y - 1) - 3 . (3x + 2y - 1)
= (6y - 4x - 3) . (3x + 2y - 1)
a. Ta có: 11a + 14b
= 110 + a + 140 + b
= 110 + 140 + a + b
= 250 + a + b
= 50 . 5 + a + b chia hết cho 5
b. Ta có: 14a + 26b
= 140 + a + 260 + b
= 140 + 260 + a +b
= 500 + a + b
= 5 . 100 + a + b chia hết cho 5
Chúc bn hk tốt nhé !!
a) chứng minh 11a +14b chia hết cho 5
\(11a+14b=110+a+140+b\)
Mà \(110⋮5\)
\(140⋮5\)
\(\Rightarrow11a+14b⋮5\)
b)chúng minh 14a + 26b chia hết cho 5
\(14a+26b=140+a+260+b\)
Mà : \(140⋮5\)
\(260⋮5\)
\(\Rightarrow14a+26b⋮5\)
Học tốt
