\(\sqrt{\left(-7\right)^2}+\sqrt{\frac{25}{16}}-\frac{3}{2}\)
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\(b,\left(\sqrt{1\frac{9}{16}-\sqrt{\frac{9}{16}}}\right):5\)
\(=\left(\sqrt{\frac{25}{16}-\frac{3}{4}}\right):5\)
\(=\sqrt{\frac{13}{16}}:5\)
\(=\frac{\sqrt{13}}{4}:5\)
\(=\frac{\sqrt{13}}{20}\)
$\textbf{a)}$
$\left(-\dfrac34+\dfrac27\right):\dfrac27+\left(-\dfrac14+\dfrac57\right):\dfrac23$
$=\left(-\dfrac{13}{28}\right)\cdot\dfrac72+\dfrac{13}{28}\cdot\dfrac32$
$=-\dfrac{13}{8}+\dfrac{39}{56}$
$=-\dfrac{13}{14}.$
$\textbf{b)}$
$\left(-\dfrac13\right)^2\cdot\dfrac4{11}+\dfrac7{11}\cdot\left(-\dfrac13\right)^2$
$=\dfrac19\left(\dfrac4{11}+\dfrac7{11}\right)$
$=\dfrac19.$
$\textbf{a)}$
$A=\dfrac23\cdot\sqrt{81}-\left(-\dfrac34\right)\cdot\sqrt{\dfrac9{64}}+\left(\dfrac{\sqrt2}{3}\right)^2$
$=\dfrac23\cdot9+\dfrac34\cdot\dfrac38+\dfrac29$
$=6+\dfrac9{32}+\dfrac29$
$=\dfrac{1873}{288}.$
$\textbf{b)}$
$B=\left(-\sqrt{\dfrac54}\right)^2-\sqrt{\dfrac94}:(-4,5)-\sqrt{\dfrac{25}{16}}\cdot\sqrt{\dfrac{64}{9}}$
$=\dfrac54-\dfrac32:\left(-\dfrac92\right)-\dfrac54\cdot\dfrac83$
$=\dfrac54+\dfrac13-\dfrac{10}{3}$
$=\dfrac{15+4-40}{12}$
$=-\dfrac74.$
\(\sqrt{\left(-7\right)^2}+\sqrt{\frac{25}{16}-\frac{3}{2}}\)
\(=7+\sqrt{\frac{1}{16}}\)
\(=7+\frac{1}{4}\)
\(=7\frac{1}{4}=\frac{29}{4}\)
\(\sqrt{\left(-7\right)^2}\)+ \(\sqrt{\frac{25}{16}}\)
= 7 +\(\frac{5}{4}\)
= \(8\frac{1}{4}\)
=\(\frac{33}{4}\)
\(\sqrt{\left(-7\right)^2}+\sqrt{\frac{25}{16}}-\frac{3}{2}\\ =7+\frac{5}{4}-\frac{3}{2}\\ =\frac{28}{4}+\frac{5}{4}-\frac{6}{4}\\ =\frac{28+5-6}{4}=\frac{27}{4}\)
= 7 + 5/4 - 1/2
= 28/4 + 5/4- 6/4
= 28 + 5 - 6/4
=27/4
chuc ban hc tot
\(\sqrt{\left(-7\right)^2}\) + \(\sqrt{\frac{25}{16}}\) - \(\frac{3}{2}\)
= 7 + \(\frac{5}{4}\) - \(\frac{3}{2}\)
= \(\frac{33}{4}\) - \(\frac{3}{2}\)
= \(\frac{27}{4}\)
\(\sqrt{\left(-7\right)^2}+\sqrt{\frac{25}{16}}-\frac{3}{2}\)
\(=-7+\frac{5}{4}-\frac{3}{2}\)
\(=-\frac{7}{1}+\frac{5}{4}-\frac{3}{2}\)
\(=-\frac{28}{4}+\frac{5}{4}-\frac{6}{4}\)
\(=-29\)