a) 3. 5 ^ 2 + 15. 2 ^2 - 26 : 2

= 15 ^ 2 + 15. 4 - 13

= 225 + 60 - 13

= 272

b) 5 ^ 3. 2 - 100 : 4 + 2 ^ 3. 5

= 125. 2 - 25 + 40

= 250 - 25 + 40

= 265

c) 6 ^ 2 : 9 + 50. 2 - 3 ^ 3. 3

= 36 : 9 + 100 - 81

= 4 + 100 - 81

= 23

d) 3 ^ 2. 5 + 2 ^ 3 . 10 - 81 : 3

= 45 + 8 . 10 - 27

= 53 + 80 - 27

= 160

e) 5 ^ 13 : 5 ^ 10 - 25. 2 ^ 2

= 1220703125 : 9765625 - 25. 4

= 125 - 100

= 25

f) 20 : 2 ^ 2 + 5 ^ 9 : 5 ^ 8

= 20 : 4 + 1953125 : 390625

= 5 + 5

= 10

g) 100 : 5 ^ 2 + 7. 3 ^ 2

= 100 : 25 + 7 . 9

= 4 + 63

= 67

h) 84 :4 + 3 ^ 9 : 3 ^ 7 + 5 ^ 0

= 21 + 19683 : 2187 + 1

= 21 + 9 + 1

= 31

i) 29 - [ 16 + 3. ( 51 - 49) ]

= 29 - [ 16 + 3. 2 ]

= 29 - 22

= 7

Mình làm xong rồi nhé!

cam on a

a) 4³.27 - 4³.23

= 4³.(27-23)

= 4³.4

= 4⁴

b) 35.77+23.35+5³.2³

= 35.(77+23) + (5.2)³

= 35.100 + 10³

= 35.10²+ 10².10

= 10².(35+10)

= 100.45

= 4500

c) 3².5 + 2³.10 - 81 : 3

= 9.5 + 8.2.5 - 27

= 5.(9+8.2) - 27

= 5.25 - 27

= 5³ - 27

= 98

d) 151-2⁹¹:2⁸⁸+1³.3

= 151 - 2³+3

= 151 - 8 + 3

= 146

a: \(5^6:5^3+2^3:2^2\)

\(=5^3+2\)

=125+2

=127

b: \(3333:3+225:15\)

=1111+15

=1126

c: \(15\cdot2^3+4\cdot3^2-5\cdot7\)

\(=15\cdot8+4\cdot9-35\)

=120+36-35

=121

d: \(5\cdot4^2-18:3^2\)

\(=5\cdot16-18:9\)

=80-2=78

e: \(6^2:4\cdot3+2\cdot5^2\)

\(=36:4\cdot3+2\cdot25\)

=27+50

=77

f: \(80-\left(4\cdot5^2-3\cdot2^3\right)\)

=80-(100-24)

=80-76

=4

\(2^3.10-3^2.5-1^{2021}\\ =8.10-9.5-1\\ =80-45-1\\ =34\)

...=8.10-9.5-1=80-45-1=34

\(3^2\cdot5+2^3\cdot10-3^4:3\\ =9\cdot5+8\cdot10-3^4\\ =45+80-27\\ =98\)

\(3^2.5+2^3.10-3^4:3\)

\(=9.5+8.10-3^3\)

\(=45+80-27\)

\(=125-27\)

\(=98\)

\(#WendyDang\)

tu tinh đi

[3.(26+32:2³)-15.2²]+2018⁰

=[3.(26+32:8)-15.4]+1

=[3.(26+4)-15.4]+1

=[3.30-15.4]+1

=[90-60]+1

=30+1=31

CẢM ƠN ĐÃ GỬI CÂU HỎI CHÚC BẠN NHỮNG ĐIỀU TỐT LÀNH.

mn làm nhanh chiều mình còn đi học.

=3.25+15.1-13

=75+15-13

=90-13

=77

3.5²+15.2⁰-26:2

=3.25+15.1-13

=75+15-13

=90-13

=77

Ta có: \(7\cdot6^{10}\cdot2^{21}\cdot3^6-2^{19}\cdot6^{15}\)

\(=7\cdot3^{10}\cdot2^{10}\cdot2^{21}\cdot3^6-2^{19}\cdot3^{15}\cdot2^{15}\)

\(=7\cdot2^{31}\cdot3^{16}-2^{34}\cdot3^{15}\)

\(=2^{31}\cdot3^{15}\left(7\cdot3-2^3\right)=2^{31}\cdot3^{15}\cdot13\)

Ta có: \(9\cdot6^{15}\cdot2^{13}-4\cdot3^{15}\cdot2^{26}\)

\(=3^2\cdot3^{15}\cdot2^{15}\cdot2^{13}-2^2\cdot3^{15}\cdot2^{26}\)

\(=3^{17}\cdot2^{28}-3^{15}\cdot2^{28}=3^{15}\cdot2^{28}\left(3^2-1\right)=3^{15}\cdot2^{31}\)

Ta có: \(B=\frac{7\cdot6^{10}\cdot2^{21}\cdot3^6-2^{19}\cdot6^{15}}{9\cdot6^{15}\cdot2^{13}-4\cdot3^{15}\cdot2^{26}}\)

\(=\frac{2^{31}\cdot3^{15}\cdot13}{3^{15}\cdot2^{31}}=13\)