giải pt:

a,\(\left(13-4x\right)\sqrt{2x-3}+\left(4x-3\right)\sqrt{5-2x}=2+8\sqrt{-4x^2+16x-15}\)

b,\(\left(9x-2\right)\sqrt{3x-1}+\left(10-9x\right)\sqrt{3-3x}-4\sqrt{-9x^2+12x-3}=4\)

c, \(\left(6x-5\right)\sqrt{x+1}-\left(6x+2\right)\sqrt{x-1}+4\sqrt{x^2-1}=4x-3\)

giải pt :

a,\(\left(6x-5\right)\sqrt{x+1}-\left(6x+2\right)\sqrt{x-1}+4\sqrt{x^2-1}=4x-3\)

b, \(\left(9x-2\right)\sqrt{3x-1}+\left(10-9x\right)\sqrt{3-3x}-4\sqrt{-9x^2+12x-3}=4\)

c, \(\left(13-4x\right)\sqrt{2x-3}+\left(4x-3\right)\sqrt{5-2x}=2+8\sqrt{-4x^2+16x-15}\)

Giải phương trình:

1, \(x^2+2x\sqrt{x-\dfrac{1}{x}}=3x+1\)

2, \(\left(13-4x\right)\sqrt{2x-3}+\left(4x-3\right)\sqrt{5-2x}=2+8\sqrt{16x-4x^2-15}\)

3, \(7\sqrt{3x-7}+\left(4x-7\right)\sqrt{7-x}=32\)

giải pt :

a, \(\left(2x-6\right)\sqrt{x+4}-\left(x-5\right)\sqrt{2x+3}=3\left(x-1\right)\)

b, \(\left(4x+1\right)\sqrt{x+2}-\left(4x-1\right)\sqrt{x-2}=21\)

c, \(\left(4x+2\right)\sqrt{x+1}-\left(4x-2\right)\sqrt{x-1}=9\)

d, \(\left(2x-4\right)\sqrt{3x-2}+\sqrt{x+3}=5x-7+\sqrt{3x^2+7x-6}\)

giải pt :a,\(\left(2x+6\right)\sqrt{x+4}-\left(x-5\right)\sqrt{2x+3}=3\left(x-1\right)\)

            b, \(\left(4x+1\right)\sqrt{x+2}-\left(4x-1\right)\sqrt{x-2}=21\)

             c, \(\left(4x+2\right)\sqrt{x+1}-\left(4x-2\right)\sqrt{x-1}=9\)

              d, \(\left(2x-4\right)\sqrt{3x-2}+\sqrt{x+3}=5x-7+\sqrt{3x^2+7x-6}\)

1. Giải phương trình nghiệm nguyên

a) \(x^2+4x+2018^{10}\)

b) \(x^2+4x+\left(y-1\right)^2=21\)

c) \(x^2+3\left(y-1\right)^2=2021\)

d) \(\left(3x-1\right)^{2020}-18\left(y-2\right)^{2019}=2019^{2020}\)

2. Tìm x,y ∈ Z

a) \(x^2-y^2+6y=56\)

b) \(x^2-4x+9y^2-6y=11\)

a,Cho \(\left(x-2019+\sqrt{\left(x-2019\right)^2+2020}\right)\left(y-2019+\sqrt{\left(y-2019\right)^2+2020}\right)=2020\)Tính : D = x + y

b, Cho \(\frac{-3}{2}\le x\le\frac{3}{2},x\ne0,a=\sqrt{3+2x}-\sqrt{3-2x}\)

Tính : \(G=\frac{\sqrt{6+2\sqrt{9-4x^2}}}{x}\) theo a.

Em cảm ơn mọi người nhiều ạ.

Cho các số x,y thỏa mãn: \(\left(x+\sqrt{3+x^2}\right).\left(y+\sqrt{3+y^2}\right)=3\). Tính giá trị của biểu thức: \(A=4x^2+xy+y^2+15\)

Ghpt:

a) \(\left\{{}\begin{matrix}\left(4x^2+1\right).x+\left(y-3\right)\sqrt{5-2y}=0\\4x^2+y^2+2\sqrt{3-4x}=7\end{matrix}\right.\)

b) \(\left\{{}\begin{matrix}x^2+y^2=5\\\sqrt{y-1}\left(x+y-1\right)=\left(y-2\right)\sqrt{x+y}\end{matrix}\right.\)