\(\)
\(0,5\cdot x-\frac{3}{7}:\frac{1}{2}=1\frac{1}{7}\)
vậy x bằng bao nhiêu
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( 1/7 . x - 2/7 ) . ( -1.5 . x + 3/5 ) . ( 1/ 3 . x + 4/3) + 0
<=> +) 1/7 . x - 2/7 = 0 +) (- 1 / 5) . x +3/5 = 0 +) 1/ 3 . x + 4/ 3 = 0
x = 2 x = 3 x = 4
Vậy x = 2 : x = 3 ; x=4
$\left(\dfrac17x-\dfrac27\right)\left(-\dfrac15x+\dfrac35\right)\left(\dfrac13x+\dfrac43\right)=0$
$\Leftrightarrow\dfrac{x-2}{7}\cdot\dfrac{3-x}{5}\cdot\dfrac{x+4}{3}=0$
$\Leftrightarrow x-2=0\ \text{hoặc}\ 3-x=0\ \text{hoặc}\ x+4=0$
$\Leftrightarrow x=2\ \text{hoặc}\ x=3\ \text{hoặc}\ x=-4.$
Vậy $\boxed{x\in\{-4,\ 2,\ 3\}.}$
\(\frac{2x}{3}-\frac{1}{6}.x-\frac{x+4}{2}=0\)
\(\Rightarrow\frac{4x}{6}-\frac{x}{6}-\frac{3x+12}{6}=0\)
\(\Rightarrow\frac{4x-x-3x-12}{6}=0\)
\(\Rightarrow0-12=0\Rightarrow-12=0\left(\text{vô lí}\right)\)
Vậy không có x thỏa mãn
Vi \(\left(\frac{1}{7}x-\frac{2}{7}\right)\cdot\left(-\frac{1}{5}x+\frac{3}{5}\right)\cdot\left(\frac{1}{3}x+\frac{4}{3}\right)=0\)
\(\Rightarrow\hept{\begin{cases}\frac{1}{7}x-\frac{2}{7}=0\\-\frac{1}{5}x+\frac{3}{5}=0\\\frac{1}{3}x+\frac{4}{3}=0\end{cases}\Rightarrow\hept{\begin{cases}\frac{1}{7}x=\frac{2}{7}\\-\frac{1}{5}x=-\frac{3}{5}\\\frac{1}{3}x=-\frac{4}{3}\end{cases}\Rightarrow}\hept{\begin{cases}x=2\\x=3\\x=-4\end{cases}}}\)
Vậy \(x\in\left\{-4;3;2\right\}\)
\(\Rightarrow\frac{1}{7}x-\frac{2}{7}=0\text{ hoặc }-\frac{1}{5}x+\frac{3}{5}=0\text{ hoặc }\frac{1}{3}x+\frac{4}{3}=0\)
\(\Rightarrow x=2\text{ hoặc }x=3\text{ hoặc }x=-4\)
Vậy tập nghiệm của pt là \(S=\left\{2;3;-4\right\}\)
a) \(\left(x-\frac{1}{2}\right).\frac{1}{3}+\frac{5}{7}=9\frac{5}{7}\)
\(\left(x-\frac{1}{2}\right).\frac{1}{3}=9\frac{5}{7}-\frac{5}{7}\)
\(x-\frac{1}{2}=9:\frac{1}{3}\)
\(x=27+\frac{1}{2}\)
\(x=\frac{55}{2}\)
b)\(\frac{1}{2}.x+150\%.x=2014\)
\(\left(\frac{1}{2}+150\%\right)x=2014\)
\(2x=2014\)
\(x=2014:2\)
\(x=1007\)
c) \(2-\left|\frac{3}{4}\right|=\frac{7}{2}\)???????
và bài này nữa
tính nhanh
a, \(5\frac{7}{5}\cdot4\frac{2}{7}+5\frac{5}{7}\cdot4\frac{2}{7}\)
b, \(b,\frac{-7}{11}\cdot\frac{4}{19}+\frac{-7}{19}\cdot\frac{7}{11}+2\frac{7}{19}\)
cảm ơn giúp nhiều
$\textbf{a)}$
$\dfrac{x-1}{2}+\dfrac{x-2}{5}=\dfrac14+\dfrac{x-7}{10}$
$\Leftrightarrow\dfrac{5(x-1)+2(x-2)}{10}=\dfrac14+\dfrac{x-7}{10}$
$\Leftrightarrow\dfrac{7x-9}{10}=\dfrac14+\dfrac{x-7}{10}$
$\Leftrightarrow14x-18=5+2x-14$
$\Leftrightarrow12x=9$
$\Leftrightarrow x=\dfrac34.$
$\textbf{b)}$
$\dfrac{3-2}{2x-3}=\dfrac25+\dfrac1{2x-3}-\dfrac32$
$\Leftrightarrow1-\dfrac2{2x-3}=-\dfrac{11}{10}+\dfrac1{2x-3}$
$\Leftrightarrow\dfrac{21}{10}=\dfrac3{2x-3}$
$\Leftrightarrow21(2x-3)=30$
$\Leftrightarrow42x=93$
$\Leftrightarrow x=\dfrac{31}{14}.$
0,5 . x - \(\frac{3}{7}\) : \(\frac{1}{2}\)= 1 \(\frac{1}{7}\)
\(\frac{1}{2}\). x - \(\frac{3}{7}\)x \(\frac{2}{1}\)= \(\frac{8}{7}\)
\(\frac{1}{2}\) . x - \(\frac{6}{7}\) = \(\frac{8}{7}\)
\(\frac{1}{2}\) . x = \(\frac{8}{7}\) + \(\frac{6}{7}\)
\(\frac{1}{2}\) . x = \(\frac{14}{7}\)
\(\frac{1}{2}\) . x = 2
x = 2 : \(\frac{1}{2}\)
x = 4
Vậy x = 4