\(a,\left(-x-6\right).\left(x+9\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}-x-6=0\\x+9=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=-6\\x=-9\end{cases}}}\)

\(b,-2.\left(x+3\right)-15=3.4+2x+7\)

            \(-2x-6-15=12+2x+7\)

                    \(-2x-21=19+2x\)

                    \(-2x-2x=19+21\)

                              \(-4x=40\)

                                    \(x=-10\)

a) x - 14 = 3x + 18

=> x - 3x = 18 + 14

=> -2x = 32

=> x = 32 : (-2)

=> x = -16

b) 2(x - 5) - 3(x - 4) = -6 + 15.(-3)

=> 2x - 10 - 3x + 12 = -6 - 45

=> -x + 2 = -51

=> -x = -51 - 2

=> -x = -53

=> x = 53

c) (x + 7)(x - 9) = 0

=> \(\orbr{\begin{cases}x+7=0\\x-9=0\end{cases}}\)

=> \(\orbr{\begin{cases}x=-7\\x=9\end{cases}}\)

Vậy ...

d) |2x - 5| - 7 = 22

=> |2x - 5| = 22 + 7

=> |2x - 5| = 29

=> \(\orbr{\begin{cases}2x-5=29\\2x-5=-29\end{cases}}\)

=> \(\orbr{\begin{cases}2x=34\\2x=-24\end{cases}}\)

=> \(\orbr{\begin{cases}x=17\\x=-12\end{cases}}\)

Vậy ...

• a\(x-14=3x+18\Rightarrow3x-x=-14-18=-32\Rightarrow x=-16\)
• b, \(2\left(x-5\right)-3\left(x-4\right)=-6+15.\left(-3\right)\Rightarrow2x-10-3x+12=-6-45\)
• \(\Rightarrow-x+2=-51\Rightarrow-x=-53\Rightarrow x=53\) 
• c.\(\left(x+7\right).\left(x-9\right)=0\Rightarrow\orbr{\begin{cases}x+7=0\\x-9=0\end{cases}\Rightarrow\orbr{\begin{cases}x=-7\\x=9\end{cases}}}\)
• d.Bạn tự làm nhé

d) \(\left|2x-5\right|-7=22\)

\(\Rightarrow\left|2x-5\right|=22+7\)

\(\Rightarrow\left|2x-5\right|=29\)

\(\Rightarrow\orbr{\begin{cases}2x-5=29\\2x-5=-29\end{cases}}\) \(\Rightarrow\orbr{\begin{cases}2x=34\\2x=-24\end{cases}}\) \(\Rightarrow\orbr{\begin{cases}x=17\\x=-12\end{cases}}\)

Vậy x = 17 hoặc x = -12

d) |2x – 5| –7 = 22

| 2x -5 | = 22+7

| 2x -5 | = 29

TH1: 2x-5 = -29

2x = -29+5

2x= -24

x= -24:2

x= -12

TH2: 2x -5 =29

2x = 29+5

2x= 34

x= 34:2

x= 17 

Vậy...

a) x – 14 = 3x + 18

x -14 - 3x = 18

-2x -14 =18

-2x = 18-14

-2x = 4

x = 4:( -2) 

x= -2

Vậy...

Bài 15:

a: 2x+x=45

=>3x=45

=>\(x=\frac{45}{3}=15\)

b: 2x+7x=918

=>\(x\cdot\left(7+2\right)=918\)

=>9x=918

=>\(x=\frac{918}{9}=102\)

c: 2x+3x=60+5

=>5x=65

=>\(x=\frac{65}{5}=13\)

d: \(11x+22x=33\cdot2\)

=>33x=66

=>\(x=\frac{66}{33}=2\)

Bài 14:

a: (12-x)(2-x)=0

=>\(\left[\begin{array}{l}12-x=0\\ 2-x=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=12\\ x=2\end{array}\right.\)

b: (x-33)(11-x)=0

=>\(\left[\begin{array}{l}x-33=0\\ 11-x=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=33\\ x=11\end{array}\right.\)

c: (21-x)(12-x)=0

=>\(\left[\begin{array}{l}21-x=0\\ 12-x=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=21\\ x=12\end{array}\right.\)

d: (50-x)(x-150)=0

=>\(\left[\begin{array}{l}50-x=0\\ x-150=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=50\\ x=150\end{array}\right.\)

Bài 13:

a: (x-2)(x-3)=0

=>\(\left[\begin{array}{l}x-2=0\\ x-3=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=2\\ x=3\end{array}\right.\)

b: (x-3)(x-4)=0

=>\(\left[\begin{array}{l}x-3=0\\ x-4=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=3\\ x=4\end{array}\right.\)

c: (x-7)(6-x)=0

=>\(\left[\begin{array}{l}x-7=0\\ 6-x=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=7\\ x=6\end{array}\right.\)

d: (x-3)(x-13)=0

=>\(\left[\begin{array}{l}x-3=0\\ x-13=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=3\\ x=13\end{array}\right.\)

Mọi người giúp mình nhanh nhé ! Mình đang cần gấp

1.Tìm x,y thuộc Z biết

1,x+(-45)=(-62)+17

2,x+29=|-43|+(-43)

3,43+(9-21)=317-(x+317)

4,|x|+|-4|=7

5,|x|+|y|=0

6,(15-x)+(x-12)=7-(-5+x)

7,(2x-5)^2=9

8,(2x+6).(x-9)=0

9,(1-3x)^3=-8

10,3x+4y-xy=15

3.Tìm x+y biết

|x|=5

|x|=7

4.Tìm giá trị lớn nhất hoặc nhỏ nhất của các biểu thức sau (x,y thuộc Z)

A=|x-3|+1

B=3-|x+1|

C=|x-5|+|y+3|+7