5^x+1 = 125 = 5³

x + 1 = 3 => x = 2

b) 3^x-1 = 81 = 3⁴

x - 1 = 4 => x=  5

c) (x - 6)² = 9 = 3²

x - 6 = 3 => x = 9

(2x - 7)² = 169 = 13²

2x - 7 = 13 => x = 10

d) x³ = 216 = 2³.3

x³ = (2.3)³ = 6³

Vậy x = 6

d) \(\left(7-2x\right)^2=49\)

\(\Rightarrow\left(7-2x\right)^2=\left(\pm7\right)^2\)

\(\Rightarrow\left[{}\begin{matrix}7-2x=7\\7-2x=-7\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}2x=7-7\\2x=7+7\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}2x=0\\2x=14\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=0\\x=7\end{matrix}\right.\)

e) \(\left(9-x\right)^3=216\)

\(\Rightarrow\left(9-x\right)^3=6^3\)

\(\Rightarrow9-x=6\)

\(\Rightarrow x=9-6\)

\(\Rightarrow x=3\)

g) \(6^{x+2}+6^x=1332\)

\(\Rightarrow6^x\cdot\left(6^2+1\right)=1332\)

\(\Rightarrow6^x\cdot37=1332\)

\(\Rightarrow6^x=1332:37\)

\(\Rightarrow6^x=36\)

\(\Rightarrow6^x=6^2\)

\(\Rightarrow x=2\)

\(d,\left(7-2x\right)^2=49\)

\(\Leftrightarrow\left[{}\begin{matrix}7-2x=7\\7-2x=-7\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}2x=0\\2x=14\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=7\end{matrix}\right.\)

\(e,\left(9-x\right)^3=216\)

\(\Leftrightarrow\left(9-x\right)^3=6^3\)

\(\Leftrightarrow9-x=6\)

\(\Leftrightarrow x=3\)

\(f,6^{x+2}+6^x=1332\)

\(\Leftrightarrow6^x\left(6^2+1\right)=1332\)

\(\Leftrightarrow6^x\cdot37=1332\)

\(\Leftrightarrow6^x=36\)

\(\Leftrightarrow6^x=6^2\)

\(\Leftrightarrow x=2\)

#Urushi

a: 128-2x=-8-x

=>-2x+x=-8-128

=>-x=-136

=>x=136

b: \(x-\left(-15\right)\cdot2=55-7\cdot\left(-3\right)\)

=>x+30=55+21

=>x+30=76

=>x=76-30

=>x=46

c: \(66-\left\lbrack5-\left(-x\right)\right\rbrack=169\)

=>66-[5+x]=169

=>x+5=66-169=-103

=>x=-103-5

=>x=-108

d: (8-2x)(8+x)=0

=>2(4-x)(8+x)=0

=>(x-4)(x+8)=0

=>\(\left[\begin{array}{l}x-4=0\\ x+8=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=4\\ x=-8\end{array}\right.\)

e: \(7-\left\lbrack x^2+\left(-9\right)\right\rbrack=-20\)

=>\(x^2-9=7+20=27\)

=>\(x^2=36\)

=>\(\left[\begin{array}{l}x=6\\ x=-6\end{array}\right.\)

chọn câu trả lời của mk nha!!!

a) \(4^n=4096\Rightarrow4^n=4^6\Rightarrow n=6\)

b) \(5^n=15625\Rightarrow5^n=5^6\Rightarrow n=6\)

c) \(6^{n+3}=216\Rightarrow6^{n+3}=6^3\Rightarrow n+3=3\Rightarrow n=0\)

d) \(x^2=x^3\Rightarrow x^3-x^2=0\Rightarrow x^2\left(x-1\right)=0\Rightarrow\left[{}\begin{matrix}x=0\\x-1=0\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)

e) \(3^{x-1}=27\Rightarrow3^{x-1}=3^3\Rightarrow x-1=3\Rightarrow x=4\)

f) \(3^{x+1}=9\Rightarrow3^{x+1}=3^2\Rightarrow x+1=2\Rightarrow x=1\)

g) \(6^{x+1}=36\Rightarrow6^{x+1}=6^2\Rightarrow x+1=2\Rightarrow x=1\)

h) \(3^{2x+1}=27\Rightarrow3^{2x+1}=3^3\Rightarrow2x+1=3\Rightarrow2x=2\Rightarrow x=1\)

i) \(x^{50}=x\Rightarrow x^{50}-x=0\Rightarrow x\left(x^{49}-1\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x=0\\x^{49}-1=0\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=0\\x^{49}=1=1^{49}\end{matrix}\right.\)  \(\Rightarrow\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)

4ⁿ  =  4096 

4ⁿ = 2¹²

n = 12

5ⁿ = 15625 

5ⁿ = 5⁶

n   = 6

6ⁿ⁺³ = 216

6ⁿ⁺³ = 2³.3³

6ⁿ⁺³ = 6³

n + 3 = 3

ai nhanh nhanh giải giúp mk bài này với huhu

cho tớ hỏi đề câu a là:6^2x+5  hay là 6^2x+5

làn sau bn ghi rõ đề nhé,để mình suy ngĩ nữa

Ghi lại đề cho mình,mình nháp cho

ko đảm bảo ra đâu

lười làm quá, bạn làm hết cũng siêng ấy

2^2x+1+4^x+3=264

2^2x+1+2^2x+1*32=264

2^2x+1(1+32)=264

2^2x+1*33=264

2^2x+1=264/33=8=2³

=>2x+1=3

2x=3-1

2x=2

x=2/2

x=1

a, x = 384

b, x = 161

c, x = 8

d, x = 15

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