b: \(27\cdot77+27\cdot27-27\)

\(=27\left(77+27-1\right)=27\cdot103\)

=2781

c: 52:(43-30)+144-16

=52:13+128

=4+128

=132

d: \(174:\left\lbrace2\cdot\left\lbrack36+\left(4^2-23\right)\right\rbrack\right\rbrace\)

\(=\frac{174}{2\cdot\left\lbrack36+16-23\right\rbrack}=\frac{87}{29}=3\)

=174:{2[36+(16-23)]}

=174:{2[36+(-7)]}

=174:{2x29}

=174:58

=3

174:{2.[36+(4^2-23 )]}=174:{2.[36+(16-23)]}=174:{2.[36+ -7]}=174:{2.29}=174:58=3

174 : {2.[36 + (4⁴ - 23)]}

= 174 : {2.[36+(-7)]}

= 174 : {2. 29}

= 174 : 58

= 3

Ta có 174 : {2.[36 + (4² - 23)]}

= 174 : {2.[36 + (-7)]}

= 174 : (2 . 29)

= 174 : 58

= 3

\(27.77+24.27-27\)

\(=27.\left(77+24-1\right)\)

\(=27.100\)

\(=2700\)

\(174\div\left\{2\left[36+\left(4^2-23\right)\right]\right\}\)

\(=174\div\left\{2\left[36+\left(16-23\right)\right]\right\}\)

\(=174\div\left\{2\left[36+\left(-7\right)\right]\right\}\)

\(=174\div\left\{2.29\right\}\)

\(=174\div58\)

\(=3\)

\(3^2.4-\left[30-\left(5-2\right)^2\right]\)

\(=9.4-\left[30-3^2\right]\)

\(=36-\left[30-9\right]\)

\(=36-21\)

\(=15\)

c) \(174:\left\{2.\left[36+\left(4^2-23\right)\right]\right\}\)

\(=174:\left\{2.\left[36-7\right]\right\}\)

\(=174:\left[2.29\right]\)

\(=174:58\)

\(=3\)

=174/{2[36+(16-23)]}

=174/{2[36+(-7)]}

=174/{2*19}

=174/38

=87/19

1: \(5\cdot25\cdot2\cdot16\cdot4=10\cdot25\cdot4\cdot16=10\cdot100\cdot16=16000\)

2: \(25\cdot5\cdot4\cdot2\cdot27\)

\(=25\cdot4\cdot5\cdot2\cdot27\)

\(=100\cdot10\cdot27=27000\)

3: \(2^3\cdot17-2^3\cdot17=2^3\left(17-17\right)=0\)

4: \(58\cdot75+58\cdot50-58\cdot25\)

\(=58\left(75+50-25\right)\)

\(=58\cdot100=5800\)

7: \(5\cdot23+35\cdot41+64\cdot65\)

\(=5\left(23+7\cdot41\right)+64\cdot65\)

\(=5\cdot310+64\cdot65=1550+4160=5710\)

n: =345:(-345)=-1

sao bạn ko làm 2 cau trên ??

/ là j v.

\(=\left(\dfrac{19}{42}+\dfrac{23}{42}\right)+\left(\dfrac{1}{37}+\dfrac{36}{37}\right)+10\)

=12