\(=\dfrac{-2}{3}\cdot\dfrac{12}{19}-\dfrac{2}{3}\cdot\dfrac{7}{19}+1\)

=-2/3(12/19+7/19)+1

=1-2/3

=1/3

5/6 x 4/19 + 7/12 x 4/19 + 18/19

=(5/6+7/12)×(4/19+18/19)

= 17/12×22/19

= 187/114

1\(\frac{14}{57}\)

Sửa đề: \(19 + 3x + 4\sqrt{-x^2 - x + 6} = 10\sqrt{2 - x} + 10\sqrt{x + 3}\) (1)

ĐKXĐ: -3<=x<=2

Đặt \(u=\sqrt{2-x};v=\sqrt{x+3}\) (Điều kiện: u>0; v>0)

\(u^2+v^2=2-x+3+x=5\)

\(uv=\sqrt{\left(2-x\right)\left(x+3\right)}=\sqrt{2x+6-x^2-3x}=\sqrt{-x^2-x+6}\)

\(v^2=x+3\)

=>\(x=v^2-3\)

=>\(3x=3v^2-9\)

(1) sẽ trở thành: \(19 + (3v^2 - 9) + 4uv = 10u + 10v\)

=>\(10+3v^2+4uv-10u-10v=0\)

=>\(u(4v-10)=-3v^2+10v-10=-3\left(v^2-\frac{10}{3}v+\frac{10}{3}\right)=-3\left(v^2-2\cdot v\cdot\frac53+\frac{25}{9}+\frac59\right)=-3\left(v-\frac53\right)^2-\frac53<0\) ∀v

=>u(4v-10)<0

=>4v-10<0

=>4v<10

=>v<5/2

=>\(u = \frac{3v^2 - 10v + 10}{10 - 4v}\)

=>\(5 - v^2 = \left( \frac{3v^2 - 10v + 10}{10 - 4v} \right)^2\)

=>\((5 - v^2)(10 - 4v)^2 = (3v^2 - 10v + 10)^2\)

=>\((5 - v^2)(16v^2 - 80v + 100) = 9v^4 - 60v^3 + 160v^2 - 200v + 100\)

=>\(-16v^4 + 80v^3 - 20v^2 - 400v + 500 = 9v^4 - 60v^3 + 160v^2 - 200v + 100\)

=>\(25v^4 - 140v^3 + 180v^2 + 200v - 400 = 0\)

=>\(5v^4 - 28v^3 + 36v^2 + 40v - 80 = 0\)

=>\((v - 2)(5v^3 - 18v^2 + 40) = 0\)

=>v-2=0

=>v=2

=>x+3=4

=>x=1(nhận)

1/ \(\left(\dfrac{2021}{2020}+\dfrac{2020}{2021}\right).\left(\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{1}{6}\right)\)

=\(\left(\dfrac{2021}{2020}+\dfrac{2020}{2021}\right).0\)

=\(0\)

mink chịu bài này nó rất khó

a)x=4-12=-8

b)x=19-0=19

c)x=-12+4:2=-4

d)x=6+(-2):2=2

|Câu d:

x = 3/4 + 1/-12

x = 9/12 - 1/12

x = 8/12

x = 2/3

Vậy x = 2/3

Câu e:

x /14 = 1/7 + (-3)/14

x/14 = 1/7 - 3/14

x/14 = 2/14 - 3/14

x/14 = -1/14

x = - 1/14 x 14

x = -1

Vậy x = -1

khó quá 

a) 11/12 x 9/19 - 22/24 x 6/19 + 11/12 x 16/19.

= 11/12 x 9/19 - 11/12 x 6/19 + 11/12 x 16/19.

=11/12 x (  9/19 -6/19 +  16/19)

=11/12x 1

=11/12

mình biết câu a/ thôi

a: x-240:12=8

=>x-20=8

=>x=28

b: \(19+\dfrac{225}{6-x}=64\)

=>\(\dfrac{225}{6-x}=45\)

=>6-x=5

=>x=1

c: Đề thiếu rồi bạn

\(X-240:12=8\\ X-20=8\\ X=8+20=28\\ ---\\ 19+225:\left(6-X\right)=64\\ 225:\left(6-X\right)=64-19=45\\ 6-X=225:45=5\\ X=6-5=1\)