=5*[55+13+32]

=5*100                     [* là dấu nhân]

=500

5x55+13x5+32

=5x(55+13+32)

=5x100

=500

a: \(\frac{23}{45}\cdot\frac{15}{16}\cdot\frac{32}{23}+0,3\cdot x=5\frac35\cdot7\frac{7}{12}\cdot\frac{2}{27}\cdot\frac{5}{13}\)

=>\(\frac{12}{16}\cdot\frac{15}{45}+0,3x=\frac{28}{5}\cdot\frac{91}{12}\cdot\frac{2}{27}\cdot\frac{5}{13}\)

=>\(0,3x+\frac{1}{12}=\frac{91}{13}\cdot\frac{2}{12}\cdot\frac{28}{27}=7\cdot\frac16\cdot\frac{28}{27}=\frac{7\cdot14}{3\cdot27}=\frac{98}{81}\)

=>\(0,3x=\frac{98}{81}-\frac{1}{12}=\frac{365}{324}\)

=>\(x=\frac{365}{324}:0,3=\frac{365}{324\cdot0,3}=\frac{365}{97,2}=\frac{1825}{486}\)

b: \(\left\lbrack\left(35\frac57+2\frac34\right)-5\frac57+\frac14\right\rbrack:11+x=3\)

=>\(\left\lbrack35+\frac57+2+\frac34-5-\frac57+\frac14\right\rbrack:11+x=3\)

=>(32+1):11+x=3

=>33/11+x=3

=>x+3=3

=>x=0

=-9/23x( 5/8+3/8)

=9/23x8/8

=9/23x1

=9/23.

\(\text{x+5+y+5+x+5+y+5}=2\left(x+y\right)+20\)

\(=2.20+20\)

\(=60\)

x+5+y+5+x+5+y+5 = x+y+x+y+5x4 = 20 + 20 + 20 = 20 x 3 = 60

Giải:

a) \(2\dfrac{17}{20}-1\dfrac{15}{11}+6\dfrac{9}{20}:3\)

\(=\dfrac{57}{20}-\dfrac{26}{11}+\dfrac{129}{20}:3\) 

\(=\dfrac{107}{220}+\dfrac{43}{20}\)

\(=\dfrac{29}{11}\)

b) \(4\dfrac{3}{7}:\left(\dfrac{7}{5}.4\dfrac{3}{7}\right)\) 

\(=\dfrac{31}{7}:\left(\dfrac{7}{5}.\dfrac{31}{7}\right)\) 

\(=\dfrac{31}{7}:\dfrac{31}{5}\) 

\(=\dfrac{5}{7}\) 

c) \(\left(3\dfrac{2}{9}.\dfrac{15}{23}.1\dfrac{7}{29}\right):\dfrac{5}{23}\) 

\(=\left(\dfrac{29}{9}.\dfrac{15}{23}.\dfrac{36}{29}\right):\dfrac{5}{23}\) 

\(=\dfrac{60}{23}:\dfrac{5}{23}\) 

\(=12\)

chịu

\(a,2.\left(x+3\right)-3x=-2x+7\)

\(\Leftrightarrow2x+6-3x=-2x-7\)

\(\Leftrightarrow-x+6=-2x+7\)

\(\Leftrightarrow x=-6+7\)

\(\Leftrightarrow x=1\)

\(b,5.\left(x-3\right)-29=-2.\left(7-x\right)-23\)

\(\Leftrightarrow5x-15-29+23=14-2x\)

\(\Leftrightarrow5x-21=14-2x\)

\(\Leftrightarrow5x+2x=35\)

\(\Leftrightarrow x=5\)

\(c,-17+\left|5-x\right|=-2.7\)

\(\Leftrightarrow-17+\left|5-x\right|=-14\)

\(\Leftrightarrow\left|5-x\right|=3\)

\(\Leftrightarrow\orbr{\begin{cases}5-x=3\\5-x=-3\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=2\\x=8\end{cases}}\)

\(d,21-\left|x+7\right|=-42:\left(-2\right)\)

\(\Leftrightarrow21-\left|x+7\right|=21\)

\(\Leftrightarrow\left|x+7\right|=0\)

\(\Leftrightarrow x+7=0\)

\(\Leftrightarrow x=7\)

\(f,\left|3x-5\right|-\left(-15\right)=5\)

\(\Leftrightarrow\left|3x-5\right|+15=5\)

\(\Leftrightarrow\left|3x-5\right|=-10\)

Vì \(\left|a\right|\ge0\)mà \(-10< 0\)nên \(x\in\Phi\)

Đã giải quyết xong!!!

giúp mình với: so sánh -37/56 với -377/567 ai giải đc mình cho

pt vt lại:

\(\dfrac{x+4}{x^2-3x+2}+\dfrac{x+1}{x^2-4}+5=\dfrac{2x+5}{x^2-4x+5}\)

pt này đk?