1001 * abc = 1b5a2c

 abcabc = 1b5a2c

Suy ra a = 1 ; b = 2 ; c = 5

Vậy abc = 125

Thiếu dấu phẩy ở 5 nha bạn

Kết quả bằng 125

1 là a,2 là b,5 là c

ê Mình ko biết

1000.abc + abc = 1000.abc + 1.abc = abc( 1000 + 1 ) = abc.1001 

Thanks

a)

\(\overline{ab}\times101=\overline{ab}\times\left(100+1\right)=\overline{ab00}+\overline{ab}=\overline{abab}\)

b)

\(\overline{ab}\times10101=\overline{ab}\times\left(10000+101\right)=\overline{ab0000}+\overline{abab}=\overline{ababab}\)

c)

\(\overline{abc}\times1001=\overline{abc}\times\left(1000+1\right)=\overline{abc000}+\overline{abc}=\overline{abcabc}\)

d)

\(\overline{ab}\times1001=\overline{ab}\times\left(1000+1\right)=\overline{ab000}+\overline{ab}=\overline{ab0ab}\)

1001=abcabc:abc

=>abc*1001=abc.abcabc:abc=abcabc

ab*1001=ab.abcabc:abc=ababc

Ta có:

\(abc.1001=abc\left(1000+1\right)=abc000+abc=abcabc\)

\(ab.1001=ab\left(1000+1\right)=ab000+ab=ab0ab\)

Ta có:\(1001=1000+1=x+1\)

\(x^8-1001x^7+1001x^6+...+1001x^2-1001x+250\\ =x^8-\left(x+1\right)x^7+\left(x+1\right)x^6+...+\left(x+1\right)x^2-\left(x+1\right)x\\ =x^8-x^8-x^7+x^7+x^6+...+x^3+x^2-x^2-x+250\\ =-x+250=-1000+250\\ =-750\)