a: 13/35=1/5+1/7+1/35

b: 17/63=1/9+1/7+1/63

a: 13/35=1/5+1/7+1/35

b: 17/63=1/9+1/7+1/63

a: 1-1/2=1/2

b: 1-3/10=7/10

c:3-1/3=8/3

d: 4-1/9=35/9

e: 8-2/3=22/3

f: 5-2/5=23/5

a: bằng 1 phần 2

b: bằng 7 phần 10

c: bằng 2 phần 3

d:bằng 35 phần 9

e: bằng 22 phần 3

g: bằng 23 phần 5

chúc bn học tốt

Tổng hai phân số ban đầu là

7/9+1/5=35/45+9/45=44/45

7/9+1/5=35/45+9/45=44/45

a: \(\dfrac{5}{3}\cdot\dfrac{4}{5}=\dfrac{4}{3}\)

b: \(\dfrac{2}{3}\cdot\dfrac{3}{5}=\dfrac{2}{5}\)

c: \(\dfrac{7}{6}\cdot\dfrac{6}{5}=\dfrac{7}{5}\)

d: \(\dfrac{8}{5}\cdot\dfrac{5}{7}=\dfrac{8}{7}\)

e: \(\dfrac{7}{6}\cdot\dfrac{6}{7}=\dfrac{7}{7}=1\)

g: \(\dfrac{9}{5}\cdot\dfrac{5}{2}=\dfrac{9}{2}\)

h: \(\dfrac{4}{3}\cdot\dfrac{3}{5}=\dfrac{4}{5}\)

\(a,\dfrac{13}{4}\times\dfrac{2}{3}\times\dfrac{4}{13}\times\dfrac{3}{2}=\left(\dfrac{13}{4}\times\dfrac{4}{3}\right)\times\left(\dfrac{2}{3}\times\dfrac{3}{2}\right)=1\times1=1\)

\(b,\dfrac{75}{100}+\dfrac{18}{21}+\dfrac{19}{32}+\dfrac{1}{4}+\dfrac{3}{21}+\dfrac{13}{32}=\left(\dfrac{3}{4}+\dfrac{1}{4}\right)+\left(\dfrac{18}{21}+\dfrac{3}{21}\right)+\left(\dfrac{19}{32}+\dfrac{13}{32}\right)=1+1+1=3\\ c,\dfrac{4}{7}\times\dfrac{5}{6}+\dfrac{4}{7}\times\dfrac{1}{6}=\dfrac{4}{7}\times\left(\dfrac{5}{6}+\dfrac{1}{6}\right)=\dfrac{4}{7}\times1=\dfrac{4}{7}\\ d,\dfrac{3}{5}\times\dfrac{7}{9}-\dfrac{3}{5}\times\dfrac{2}{9}=\dfrac{3}{5}\times\left(\dfrac{7}{9}-\dfrac{2}{9}\right)=\dfrac{3}{5}\times\dfrac{5}{9}=\dfrac{1}{3}\)

\(e,\dfrac{5}{9}\times\dfrac{1}{4}+\dfrac{4}{9}\times\dfrac{3}{12}=\dfrac{5}{9}\times\dfrac{1}{4}+\dfrac{4}{9}\times\dfrac{1}{4}=\dfrac{1}{4}\times\left(\dfrac{5}{9}+\dfrac{4}{9}\right)=\dfrac{1}{4}\times1=\dfrac{1}{4}\\ f,\dfrac{7}{9}\times\dfrac{8}{5}\times\dfrac{3}{5}=\dfrac{56}{75}\\ g,\dfrac{2}{5}\times\dfrac{3}{4}+\dfrac{3}{4}\times\dfrac{3}{5}=\dfrac{3}{4}\times\left(\dfrac{2}{5}+\dfrac{3}{5}\right)=\dfrac{3}{4}\times1=\dfrac{3}{4}\\ h,\dfrac{2006}{2005}\times\dfrac{3}{4}-\dfrac{3}{4}\times\dfrac{1}{2005}=\dfrac{3}{4}\times\left(\dfrac{2006}{2005}-\dfrac{1}{2005}\right)=\dfrac{3}{4}\times1=\dfrac{3}{4}\)

a: \(=\dfrac{13}{4}\cdot\dfrac{4}{13}\cdot\dfrac{2}{3}\cdot\dfrac{3}{2}=1\cdot1=1\)

b: \(=\dfrac{3}{4}+\dfrac{1}{4}+\dfrac{6}{7}+\dfrac{1}{7}+\dfrac{19}{32}+\dfrac{13}{32}=1+1+1=3\)

c: \(=\dfrac{4}{7}\left(\dfrac{5}{6}+\dfrac{1}{6}\right)=\dfrac{4}{7}\)

d: \(=\dfrac{3}{5}\left(\dfrac{7}{9}-\dfrac{2}{9}\right)=\dfrac{3}{5}\cdot\dfrac{5}{9}=\dfrac{1}{3}\)

e: \(=\dfrac{1}{4}\left(\dfrac{5}{9}+\dfrac{4}{9}\right)=\dfrac{1}{4}\)

C

C

c. 27/7 nha bn

1: Ta có: \(\frac{3x-2y}{4}=\frac{2z-4x}{3}=\frac{4y-3z}{2}\)

=>\(\frac{12x-8y}{16}=\frac{6z-12x}{9}=\frac{8y-6z}{4}\)

Áp dụng tính chất của dãy tỉ số bằng nhau, ta được:

\(\frac{12x-8y}{16}=\frac{6z-12x}{9}=\frac{8y-6z}{4}=\frac{12x-8y+6z-12x+8y-6z}{16+9+4}=0\)

=>12x=8y=6z

=>6x=4y=3z

=>\(\frac{6x}{12}=\frac{4y}{12}=\frac{3z}{12}\)

=>\(\frac{x}{2}=\frac{y}{3}=\frac{z}{4}\)

mà x+y+z=18

nên Áp dụng tính chất của dãy tỉ số bằng nhau, ta được:

\(\frac{x}{2}=\frac{y}{3}=\frac{z}{4}=\frac{x+y+z}{2+3+4}=\frac{18}{9}=2\)

=>\(\begin{cases}x=2\cdot2=4\\ y=3\cdot2=6\\ z=4\cdot2=8\end{cases}\)

2:

Áp dụng tính chất của dãy tỉ số bằng nhau, ta được:

\(\frac{y+z+6}{x}=\frac{z+x+7}{y}=\frac{x+y-13}{z}=\frac{y+z+6+z+x+7+x+y-13}{x+y+z}=2\)

=>y+z+6=2x; z+x+7=2y; x+y-13=2z

=>y+z=2x-6; x+z=2y-7; x+y=2z+13

Ta có: \(\frac{y+z+6}{x}=\frac{1}{x+y+z}\)

=>\(\frac{1}{x+y+z}=2\)

=>\(x+y+z=\frac12\)

Ta có: \(x+y+z=\frac12\)

=>\(x+2x-6=\frac12\)

=>\(3x=6+\frac12=\frac{13}{2}\)

=>\(x=\frac{13}{6}\)

Ta có: \(x+y+z=\frac12\)

=>\(2y-7+y=\frac12\)

=>\(3y=7+\frac12=\frac{15}{2}\)

=>\(y=\frac52\)

Ta có: \(x+y+z=\frac12\)

=>\(z=\frac12-\frac52-\frac{13}{6}=-2-\frac{13}{6}=-\frac{25}{6}\)

1. D

2. B

3. 3/8 : 3/8 = 1 [m]

1.D

2.B

3.C

4.B

5.B

6.B