cứu

a: \(\sqrt{4\left(a-3\right)^2}=2\left(a-3\right)=2a-6\)

b: \(\sqrt{9\left(b-2\right)^2}=3\left(2-b\right)=-3b+6\)

c: \(\sqrt{25x^2\left(1-4y+4y^2\right)}=-5x\left(2y-1\right)=-10xy+5x\)

rút gọn nha

a, (x²+1)(x-3)-(x-3)(x²+3x+9)

=(x-3)(x²+1+x²+3x+9)

(x-3)(2x²+3x+10)

a: \(\left(x^2+1\right)\left(x-3\right)-\left(x-3\right)\left(x^2+3x+9\right)\)

\(=\left(x-3\right)\left(x^2+1-x^2-3x-9\right)\)

=(x-3)(-3x-8)

b: \(\left(x+2\right)^2+x\left(x+5\right)\)

\(=x^2+4x+4+x^2+5x\)

\(=2x^2+9x+4=2x^2+8x+x+4\)

=2x(x+4)+(x+4)

=(x+4)(2x+1)

c: \(\left(5x+4y\right)\left(5x-4y\right)-24x^2+15y^2\)

\(=25x^2-16y^2-24x^2+15y^2\)

\(=x^2-y^2=\left(x-y\right)\left(x+y\right)\)

tl mình nha

a) \(\left(x^2+1\right)\left(x-3\right)-\left(x-3\right)\left(x^2+3x+9\right)\)

\(=\left(x-3\right)\left[x^2+1-\left(x^2+3x+9\right)\right]\)

\(=\left(x-3\right)\left(x^2+1-x^2-3x-9\right)\)

\(=\left(x-3\right)\left(-3x-8\right)\)

\(\text{(-75).(-x) với 0}\)

\(\text{(-75).(-x) =0}\)

\(75x=0\)

\(\Leftrightarrow\)75 nhân với bất kì số nào cx lớn hơn 0 trừ 0 

\(\Rightarrow75x\le0\)

a,x là số nguyên âm

b,x =0

c,x=1;2

d,x=3

e,x=4;5;6