1 isn't done

2 is asked

DẠ CẢM ƠN NHIỀU Ạ ^^❤

1, What would he like to have for breakfast?

He would like to have a sandwich

2,Who would you like to go fishing with?

I would like to go fishing with my father

3,What would her children like to do in the summer?

They would like to go swimming

4,When would Mrs Tam like to go shopping?

She would like to go shopping at weekends

5,Where would Hung and Tung like to study

They would like to study in the library

1 What would he like for breakfast? 

He'd like a sandwich

2 Who would you like to go fishing with?

I would like to go with my father

3 What would her children like to do in summer?

They would like to swim inpool

4 When would Mrs Tam like to go shopping?

She would like to go shopping on the weekends

5 Where would Tung and Hung like to study ?

THey would like to study in the school library

a: Để (d) cắt (d') thì \(\frac{1}{m}<>-m\)

=>\(-m^2<>1\)

=>\(m^2<>-1\) (luôn đúng)

=>(d) luôn cắt (d')

1. What will you do?
I will organize free tutoring classes, donate books and school supplies, and raise funds for students in need.

2. Why do you choose to do them?
Because education is very important, and I want to help students have better opportunities to learn and succeed.

3. Do you think the students in need will receive benefits? Why?
Yes, they will. They can improve their knowledge, have enough materials to study, and feel more confident about their future.

4. How can you make more people know about your voluntary activities?
I can share information on social media, invite friends to join, and cooperate with schools or local organizations to spread the message.

\(\%Fe_{FeCl_3}=\dfrac{56}{56+35.5\cdot3}\simeq34,46\%\)

Fe không có trong CuSO4 nha bạn

Cảm ơn bn nhìu🥰. 

\(M_{KNO_3}=39+14+16\cdot3=101g/mol\\ M_{H_2SO_4}=1\cdot2+32+16\cdot4=98g/mol\\ M_{CuSO_4}=64+32+16\cdot4=160g/mol\\ M_{Al\left(OH\right)_3}=27+\left(1+17\right)\cdot3=78g/mol\\ M_{NaCl}=23+35,5=58,5g/mol\)

\(M_{KNO_3}=39+14+16\cdot3=101g/mol\\ M_{H_2SO_4}=1\cdot2+32+16\cdot4=98g/mol\\ M_{CuSO_4}=64+32+16\cdot4=160g/mol\\ M_{Al\left(OH\right)}_{_3}=27+\left(1+16\right)\cdot3=78g/mol\\ M_{NaCl}=23+35,5=58,5g/mol\)