A=\(\frac{-41000}{973}\)

\(E=\dfrac{\left(\dfrac{53}{4}-\dfrac{59}{27}-\dfrac{65}{6}\right).\dfrac{5751}{25}+\dfrac{187}{4}}{\left(\dfrac{10}{7}+\dfrac{10}{3}\right):\left(\dfrac{37}{3}-\dfrac{100}{7}\right)}\)

\(=\dfrac{\dfrac{25}{108}.\dfrac{5751}{25}+\dfrac{187}{4}}{\dfrac{100}{21}:\left(\dfrac{-44}{21}\right)}\)

\(=\dfrac{53,25+\dfrac{187}{4}}{\dfrac{-25}{11}}\)

\(=\dfrac{100}{\dfrac{-25}{11}}\)

\(=-44\)

Ta có: \(\left(13\frac14-2\frac{5}{27}-10\frac56\right)\cdot230\frac{1}{25}+46\frac34\)

\(=\left(13+\frac14-2-\frac{5}{27}-10-\frac56\right)\cdot230,04+46,75\)

\(=\left(1+\frac14-\frac{5}{27}-\frac56\right)\cdot230,04+46.75\)

\(=\left(\frac{108}{108}+\frac{27}{108}-\frac{20}{108}-\frac{90}{108}\right)\cdot230,04+46,75\)

\(=\frac{25}{108}\cdot230,04+46,75=53,25+46,75=100\)

Ta có: \(\left(1\frac37+\frac{10}{3}\right):\left(12\frac13-14\frac27\right)\)

\(=\left(\frac{10}{7}+\frac{10}{3}\right):\left(12+\frac13-14-\frac27\right)\)

\(=\left(\frac{30}{21}+\frac{70}{21}\right):\left(-2+\frac13-\frac27\right)\)

\(=\frac{100}{21}:\left(-2+\frac{7}{21}-\frac{6}{21}\right)=\frac{100}{21}:\left(-2+\frac{1}{21}\right)=\frac{100}{21}:\frac{-41}{21}=\frac{-100}{41}\)

Ta có: \(\frac{\left(13\frac14-2\frac{5}{27}-10\frac56\right)\cdot230\frac{1}{25}+46\frac34}{\left(1\frac37+\frac{10}{3}\right):\left(12\frac13-14\frac27\right)}\)

\(=100:\frac{-100}{41}=-41\)

\(\frac{\frac{25}{108}.\frac{1151}{5}+\frac{187}{4}}{\frac{139}{30}:\frac{-41}{21}}\)=\(\frac{\frac{5755}{108}+\frac{187}{4}}{\frac{-973}{410}}\)=\(\frac{\frac{8531}{84}}{\frac{-973}{410}}\)=-241,0180

\(\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right)\cdot230\frac{1}{5}+46\frac{3}{4}}{\left(1\frac{3}{10}+\frac{10}{3}\right):\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)

\(=\frac{\left(\frac{53}{4}-\frac{59}{27}-\frac{65}{6}\right)\cdot\frac{1151}{5}+\frac{187}{4}}{\frac{139}{30}:\left(-\frac{41}{21}\right)}\)

\(=\frac{\frac{25}{108}\cdot\frac{1151}{5}+\frac{187}{4}}{\frac{139}{30}\cdot\left(-\frac{21}{41}\right)}=\frac{\frac{2701}{27}}{-\frac{973}{410}}\)

Tính nốt vì số dữ quá , lần sau để số ít thôi

\(-\frac{2000}{139}\)