giúp em tui với

6 x5/3=10   7:8/4+1/3=23/6     2x5/8-1/2=3/4   3/7:5/6x1/4=9/70

   (2 ^ 2 + 1) x (2 ^ 2 - 1) x (2 ^ 4 - 4 ^ 2)

= (2 ^ 2 + 1) x (2 ^ 2 - 1) x (  16  -   16  )

= (2 ^ 2 + 1) x (2 ^ 2 - 1) x 0

= 0

   ( 7 ^ 3 + 7 ^ 5) x (5 ^ 4 + 5 ^ 6) x ( 3 ^ 3 x 3 - 9 ^ 2)

= ( 7 ^ 3 + 7 ^ 5) x (5 ^ 4 + 5 ^ 6) x (    3 ^ 4   - 3 ^ 4)

= ( 7 ^ 3 + 7 ^ 5) x (5 ^ 4 + 5 ^ 6) x 0

= 0

   2 ^ 2 x 5 [( 5 ^ 2 + 2 ^ 3) : 11] - 2 ^ 4 + 2 x 10 ^ 3

=    4   x 5 [(   25  +    8  ) : 11] -    8   + 2 x  1000

=        20  (           33       :  11) -    8   +    2000

=        20 x                 3           -    8    +    2000

=                   60                     -     8    +   2000

=                                 2052

C

C

a)17/6                                  b)5

c)25312                               d)101248

câu1

(3x-1).(1/2x5)=0

=>3x-1=0               hoặc  1/2x5=0

=>x=1/3                            =>x=0

câu2

1/4+1/3 :(2x-1)=5

=> 1/3:(2x-1)=19/4

=>2x-1       =57/4

=>2x=61/4

=>x=61/8

còn hai câu sau bn ghi đề mik ko hỉu

1.

a)(3x-1)(1/2x5)=0

=>3x-1=0 hoặc 1/2x5=0

3x=0+1               x=0:1/2:5

x=1/3                  x=0

Vậy x=1/3 hoặc x=0

b)1/4+1/3:(2x-1)=5

1/3:(2x-1)=5-1/4=20/4-1/4=19/4

2x-1=1/3:19/4=1/3*4/19=4/57

2x=4/57+1=4/57+57/57=61/57

x=61/57:2=61/57*1/2=61/114

Vậy x=61/114

c)(2x+2/5)^2-9/25=0=0^2-9/25

=>2x+2/5=0

2x=0-2/5

x=-2/5:2=-2/5*1/2

x=-1/5

Vậy x=-1/5

d)(3x-1/2)^3+1/9=0=0^3+1/9

=>3x-1/2=0

3x=0+1/2

x=1/2:3=1/2*1/3

x=1/6

Vậy x=1/6

a: \(\frac{4^5\cdot10\cdot5^6+25^5\cdot2^8}{2^8\cdot5^4+5^7\cdot2^5}\)

\(=\frac{2^{10}\cdot2\cdot5\cdot5^6+5^{10}\cdot2^8}{2^8\cdot5^4+5^7\cdot2^5}=\frac{2^8\cdot5^7\left(2^3+3^3\right)}{2^5\cdot5^4\left(2^3+3^3\right)}\)

\(=2^3\cdot5^3=10^3=1000\)

b: \(149-\left(35:x+3\right)\cdot17=13\)

=>\(\left(35:x+3\right)\cdot17=149-13=136\)

=>35:x+3=136:17=8

=>35:x=8-3=5

=>\(x=\frac{35}{5}=7\)

c: \(121:11-\left(4x+5:3\right)=4\)

=>11-(4x+5/3)=4

=>4x+5/3=11-4=7

=>\(4x=7-\frac53=\frac{21}{3}-\frac53=\frac{16}{3}\)

=>\(x=\frac{16}{3}:4=\frac43\)

d: \(720:\left\lbrack41-\left(2x-5\right)\right\rbrack=40\)

=>\(41-\left(2x-5\right)=\frac{720}{40}=18\)

=>2x-5=41-18=23

=>2x=28

=>\(x=\frac{28}{2}=14\)

e: Sửa đề: (x+1)+(x+2)+(x+3)+...+(x+100)=5700

=>100x+(1+2+3+...+100)=5700

=>\(100x+100\cdot\frac{101}{2}=5700\)

=>x+50,5=57

=>x=57-50,5

=>x=6,5

\(a)4(15-18)-(3-5).(-3)^2\)

\(=4.\left(-3\right)-2.9\)

\(=6\)

\(b)(-4-11):(-3)\)

\(=-15:\left(-3\right)\)

\(=5\)

\(c)143-(-57)-(-2)^3.(-3)^0\)

\(=143+57+8.1\)

\(=208\)

\(d,\left(-5\right).\left[\left(90-2.5\right)-10^2+10:\left|-2\right|\right]\)

\(=-5.\left[80-100+10:2\right]\)

\(=-5.-15\)

\(=75\)