a) Ta có: A = (x + y)³ + 2x² + 4xy + 2y²

    A = 7³ + 2(x² + 2xy + y²)

   A = 343 + 2(x + y)²

 A = 343 + 2. 7²

  A = 343 + 98 = 441

b) B = (x - y)³ - x² + 2xy - y²

=> B = (-5)³ - (x² - 2xy + y²)

=> B = -125 - (x - y)²

=> B = -125 - (-5)²

=> B = -125 - 25 = -150

Bài 3:

3: \(6x\left(x-y\right)-9y^2+9xy\)

\(=6x\left(x-y\right)+9xy-9y^2\)

\(=6x\left(x-y\right)+9y\left(x-y\right)\)

\(=\left(x-y\right)\left(6x+9y\right)\)

\(=3\left(2x+3y\right)\left(x-y\right)\)

Bài 4:

$(x-1)(x^2+x+1)-x^3-6x=11$

Dùng $(x-1)(x^2+x+1)=x^3-1$:

$x^3-1-x^3-6x=11$

$-6x-1=11$

$-6x=12$

$x=-2$

Vậy $x=-2$.

$16x^2-(3x-4)^2=0$

$(4x)^2-(3x-4)^2=0$

$(4x-3x+4)(4x+3x-4)=0$

$(x+4)(7x-4)=0$

$x=-4$ hoặc $x=\dfrac47$

Vậy $x=-4,\dfrac47$.

$x^3-x^2+3-3x=0$

$=x^2(x-1)-3(x-1)=0$

$=(x-1)(x^2-3)=0$

$x-1=0$ hoặc $x^2-3=0$

$x=1$ hoặc $x=\pm\sqrt3$

Vậy $x=1,\sqrt3,-\sqrt3$.

$\dfrac{x-1}{x+2}=\dfrac{x+2}{x+1}$

Điều kiện: $x\ne-2,-1$.

$(x-1)(x+1)=(x+2)^2$

$x^2-1=x^2+4x+4$

$-4x=5$

$x=-\dfrac54$

Vậy $x=-\dfrac54$.

$\dfrac1{x+2}+\dfrac2{x+1}=0$

Điều kiện: $x\ne-2,-1$.

$\dfrac{x+1+2(x+2)}{(x+2)(x+1)}=0$

$x+1+2x+4=0$

$3x+5=0$

$x=-\dfrac53$

Vậy $x=-\dfrac53$.

$\dfrac{9-x^2}{x}:(x-3)=1$

Điều kiện: $x\ne0,3$.

$\dfrac{9-x^2}{x(x-3)}=1$

$9-x^2=x(x-3)$

$9-x^2=x^2-3x$

$2x^2-3x-9=0$

$(2x+3)(x-3)=0$

$x=-\dfrac32$ hoặc $x=3$

Nhưng $x=3$ không thỏa điều kiện.

Vậy $x=-\dfrac32$.

vì x=5+y => x-y=5

đặt \(A=x^2+y\left(y-2x\right)+75\)

          \(=x^2+y^2-2xy+75\)

             \(=\left(x-y\right)^2+75\)

            \(=5^2+75\)

               =100

b)   đặt \(B=x\left(x+2\right)+y\left(y-2\right)-2xy+65\) 

                 \(=x^2+2x+y^2-2y-2xy+65\)

                   \(=\left(x^2+y^2-2xy\right)+\left(2x-2y\right)+65\)

                   \(=\left(x-y\right)^2+2\left(x-y\right)+65\)

                    \(=5^2+2.5+65\)

                     =100

a) P = \(x^2+3x+y^2-3y-2xy+90\)

= \(\left(x-y\right)^2+3\left(x-y\right)+90\)

= \(5^2+3.5+90=130\)

b) P = \(4x^2+9y^2-12xy-12x+24xy-18y+118\)

= \(4x^2+9y^2+12xy-12x-18y+118\)

= \(\left(2x+3y\right)^2-6\left(2x+3y\right)+118\)

= \(\left(-7\right)^2-6.\left(-7\right)+118=209\)

Các bạn ơi cho tui hỏi câu này : noise in / kept / night / the / awake / city / at / the / him / .

Giúp mình với , cảm ơn.

a)  \(A=x^2+2xy+y^2-4x-4y+1\)

\(=\left(x+y\right)^2-4\left(x+y\right)+1\)

\(=3^2-4.3+1=-2\)

b)  \(B=x\left(x+2\right)+y\left(y-2\right)-2xy+37\)

\(=x^2+2x+y^2-2y-2xy+37\)

\(=\left(x-y\right)^2+2\left(x-y\right)+37\)

\(=7^2+2.7+37=100\)

c)  \(C=x^2+4y^2-2x+10+4xy-4y\)

\(=\left(x+2y\right)^2-2\left(x+2y\right)+10\)

\(=5^2-2.5+10=25\)

a) \(A=x^2+2xy+y^2-4x-4v+1\)

\(=\left(x+y\right)^2-4\left(x+y\right)+1\)

\(=3^2-4.3+1=-2\)

a) \(M=\left(x+y\right)^3+2x^2+4xy+2y^2\)

\(=7^3+2\left(x^2+2xy+y^2\right)\)

\(=343+2\left(x+y\right)^2\)

\(=343+2.7^2\)

\(=343+98=441\)

b) \(N=\left(x-y\right)^3-x^2+2xy-y^2\)

\(=\left(-5\right)^3-\left(x-y\right)^2\)

\(=-125-\left(-5\right)^2\)

\(=-125-25=-150\)

vo dich cai gi ma van phai hoi