Khai triển tích (-2x-3)(2x-3)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
mình nhầm tí.
\(=\left(2x-3-2x-5\right)^2=\left(-8\right)^2=64\) nha
a.(x+3)(x+1)
=x.(x+1)+3.(x+1)
=x2+x+3x+3
=x2+4x+3
b.(x+6)(2x-2)
=x.(2x-2)+6.(2x-2)
=2x2-2x+12x-12
=2x2+10x-12
1: \(x\left(3x-1\right)-2x\left(x-1\right)-\left(x-2\right)^2\)
\(=3x^2-x-2x^2+2x-\left(x^2-4x+4\right)\)
\(=x^2+x-x^2+4x-4=5x-4\)
2: \(x\left(2+x\right)-\left(x-1\right)\left(3-x\right)-\left(3-x\right)^2\)
\(=x^2+2x+\left(x-1\right)\left(x-3\right)-\left(x-3\right)^2\)
\(=x^2+2x+\left(x-3\right)\left(x-1-x+3\right)=x^2+2x+2\left(x-3\right)\)
\(=x^2+4x-6\)
3: \(\left(2x-1\right)^2-2\left(2x-1\right)\left(2x-3\right)+\left(3-2x\right)^2\)
\(=\left(2x-1\right)^2-2\left(2x-1\right)\left(2x-3\right)+\left(2x-3\right)^2\)
\(=\left(2x-1-2x+3\right)^2=2^2=4\)
5:
a: (2x-5)(2x+5)=4x^2-25
b: (3x-5y)(3x+5y)=9x^2-25y^2
c: (3x+7y)(3x-7y)=9x^2-49y^2
d: (2x-1)(2x+1)=4x^2-1
4:
a: 2003*2005=(2004-1)(2004+1)=2004^2-1<2004^2
b: 8(7^2+1)(7^4+1)(7^8+1)
=1/6*(7-1)(7+1)(7^2+1)(7^4+1)(7^8+1)
=1/6(7^2-1)(7^2+1)(7^4+1)(7^8+1)
=1/6(7^16-1)<7^16-1
5:
a: (2x-5)(2x+5)=4x^2-25
b: (3x-5y)(3x+5y)=9x^2-25y^2
c: (3x+7y)(3x-7y)=9x^2-49y^2
d: (2x-1)(2x+1)=4x^2-1
mik chỉ biết bài 5 thôi !


\(=-\left(2x+3\right)\left(2x-3\right)=-\left(4x^2-9\right)=9-4x^2\)
\(-\left(2x+3\right)\left(2x-3\right)=-4x^2+9\)