Sửa đề: \(B=\frac{\left(3\cdot4\cdot2^{16}\right)^2}{11\cdot2^{13}\cdot4^{11}-16^9}\cdot\frac{3+\frac37-\frac{3}{11}}{\frac97-\frac{9}{11}+9}\)

\(=\frac{\left(3\cdot2^2\cdot2^{16}\right)^2}{11\cdot2^{13}\cdot2^{22}-2^{36}}\cdot\frac{3\left(1+\frac17-\frac{1}{11}\right)}{9\left(1+\frac17-\frac{1}{11}\right)}\)

\(=\frac{\left(3\cdot2^{18}\right)^2}{11\cdot2^{35}-2^{36}}\cdot\frac13\)

\(=\frac{9\cdot2^{36}}{2^{35}\left(11-2\right)}\cdot\frac13=\frac23\)

( 169 - 4² ).( 169 - 5² ).( 169 - 6² )........( 169 - 14² ).( 169 - 15² )

= ( 13² - 4² ).( 13² - 5² ).( 13² - 6² )........( 13² - 13² ).( 13² - 14² ).( 13² - 15² )

= ( 13² - 4² ).( 13² - 5² ).( 13² - 6² ) ........0.( 13² - 14² ).( 13² - 15² )

= 0

Bn vt thiếu đề nhé, đề đúng phải như này :)

(169 - 1).(169 - 2²).(169 - 3²)...(169 - 12²).(169 - 13²)

= (169 - 1).(169 - 2²).(169 - 3²)...(169 - 12²).(169 - 169)

= (169 - 1).(169 - 2²).(169 - 3²)...(169 - 12²).0

= 0

Cảm ơn nhé

(169-4²).(169-5²)…(169-12²).(169-13²)

=(169-4²).(169-5²)…(169-12²).(169-169)

=(169-4²).(169-5²)…(169-12²).0

=0

(169 - 4^2) . (169 - 5^2) ... (169 - 13^2)

=(169-4^2).(169-5^2)...(169-169)

=0

(169 - 4 mũ 2) (169 -5 mũ 2) ...( 169 - 13 mũ 2)

= (169-4²)(169-5²)...(169-13²)

=(199-4²)(169-5²)...(169-169)

=_____________...0

=       0