Ta có:

\(\left(\right. \frac{13 \frac{2}{9} - 15 \frac{2}{3}}{18 \frac{3}{7} - 17 \frac{1}{4}} \cdot \frac{30^{2} - 5^{4}}{25 - 12 \cdot 5^{2}} \left.\right) \cdot x = \frac{\frac{2}{11} + \frac{3}{13} + \frac{4}{15} + \frac{5}{17}}{4 \frac{1}{11} + \frac{5}{13} + \frac{9}{15} + \frac{13}{17}}\)

Bước 1: Đổi hỗn số về phân số

• \(13 \frac{2}{9} = \frac{119}{9}\),
• \(15 \frac{2}{3} = \frac{47}{3}\),
• \(18 \frac{3}{7} = \frac{129}{7}\),
• \(17 \frac{1}{4} = \frac{69}{4}\)

Bước 2: Tính toán từng phần

Ta có:

\(\frac{119}{9} - \frac{47}{3} = \frac{119 - 141}{9} = \frac{- 22}{9}\) \(\frac{129}{7} - \frac{69}{4} = \frac{516 - 483}{28} = \frac{33}{28}\) \(30^{2} - 5^{4} = 900 - 625 = 275\) \(25 - 12 \cdot 25 = 25 - 300 = - 275\)

Khi đó:

\(\left(\right. \frac{- 22}{9} \div \frac{33}{28} \cdot \frac{275}{- 275} \left.\right) = \left(\right. \frac{- 22}{9} \cdot \frac{28}{33} \cdot \left(\right. - 1 \left.\right) \left.\right) = \frac{616}{297}\)

Bước 3: Tính vế phải

Tử số:

\(\frac{2}{11} + \frac{3}{13} + \frac{4}{15} + \frac{5}{17} = \frac{35494}{36465}\)

Mẫu số:

\(4 \frac{1}{11} + \frac{5}{13} + \frac{9}{15} + \frac{13}{17} = \frac{149645}{36465}\)

→ Vế phải:

\(\frac{35494}{36465} \div \frac{149645}{36465} = \frac{35494}{149645}\)

Bước 4: Giải phương trình

\(\frac{616}{297} \cdot x = \frac{35494}{149645} \Rightarrow x = \frac{35494}{149645} \cdot \frac{297}{616} = \frac{813}{7118}\)

Vậy:

\(\boxed{x = \frac{813}{7118}}\)

hỉu không =]]]

= \(\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{3}{4}\cdot\cdot\cdot\frac{19}{20}=\frac{1}{20}\)

=\(\frac{1}{2}.\frac{2}{3}.\frac{3}{4}......\frac{19}{20}\)

= đến đây bn xem trong thống kê hỏi đáp nhé

 = :))

\(B=\left(-\frac{5}{9}\right).\frac{3}{11}+\left(-\frac{13}{18}\right).\frac{3}{11}\)

\(=\frac{3}{11}.\left[\left(-\frac{5}{9}\right)+\left(-\frac{13}{18}\right)\right]\)

\(=\frac{3}{11}.\left[\left(-\frac{10}{18}\right)+\left(-\frac{13}{18}\right)\right]\)

\(=\frac{3}{11}.\frac{-23}{18}\)

\(=-\frac{23}{66}\)

bạn hạn chế trl lại những câu hỏi đã có người trl nếu ko cs đáp án khác nhé!

Mk ko biết lm nhưng cứ k thoải mái nha

SORRY

13.737373244

S=\(^{2^{2010}-2^{2009}-2^{2008}-...-2-1}\)

$A=\left(\dfrac14-1\right)\left(\dfrac19-1\right)\left(\dfrac1{16}-1\right)\cdots\left(\dfrac1{100}-1\right)\left(\dfrac1{121}-1\right)$

$=\left(-\dfrac34\right)\left(-\dfrac89\right)\left(-\dfrac{15}{16}\right)\cdots\left(-\dfrac{99}{100}\right)\left(-\dfrac{120}{121}\right)$

$=(-1)^{10}\cdot\dfrac34\cdot\dfrac89\cdot\dfrac{15}{16}\cdots\dfrac{99}{100}\cdot\dfrac{120}{121}$

$=\dfrac34\cdot\dfrac89\cdot\dfrac{15}{16}\cdot\dfrac{24}{25}\cdots\dfrac{99}{100}\cdot\dfrac{120}{121}$

$=\dfrac{3\cdot8\cdot15\cdot24\cdots99\cdot120}{4\cdot9\cdot16\cdot25\cdots100\cdot121}$

$=\dfrac{(1\cdot2\cdot3\cdots10)\,(3\cdot4\cdot5\cdots12)}{(2\cdot3\cdot4\cdots11)^2}$

$=\dfrac{1\cdot12}{2\cdot11}$

$=\dfrac6{11}.$

$A=\dfrac{\left(\dfrac49\right)^2\cdot\left(-\dfrac9{16}\right)\cdot(-1)^{19}}{\left(\dfrac4{25}\right)^2\cdot\left(-\dfrac{25}{144}\right)^2\cdot\left(-\dfrac{49}{144}\right)^2}$

$=\dfrac{\dfrac{16}{81}\cdot\left(-\dfrac9{16}\right)\cdot(-1)}{\dfrac{16}{625}\cdot\dfrac{625}{144^2}\cdot\dfrac{49^2}{144^2}}$

$=\dfrac{\dfrac19}{\dfrac{49^2}{144^4}}$

$=\dfrac19\cdot\dfrac{144^4}{49^2}$

$=\dfrac19\cdot\dfrac{(2^4\cdot3^2)^4}{7^4}$

$=\dfrac19\cdot\dfrac{2^{16}\cdot3^8}{7^4}$

$=\dfrac{2^{16}\cdot3^6}{7^4}$

$=\dfrac{65536\cdot729}{2401}$

$=\dfrac{47775744}{2401}.$

\(T=\frac{3}{4}.\frac{8}{9}.\frac{15}{16}......\frac{575}{576}.\frac{624}{625}\)

\(T=\frac{1.3}{2.2}.\frac{2.4}{3.3}.\frac{3.5}{4.4}.....\frac{23.25}{24.24}.\frac{24.26}{25.25}\)

\(T=\frac{1.2.3....24}{2.3.4...25}.\frac{3.4.5....26}{2.3.4....25}=\frac{1}{25}.\frac{26}{2}=\frac{13}{25}\)