4 2 .   25 2 +   32.   125 2 3 .   5 2 = 2 4 .5 4 + 2 5 .5 3 2 3 .5 2 = 2 4 .5 3 5 + 2 2 3 .5 2 = 2.5.7 = 70

a)(15 + 37) + (52 -37 -17)

=52+ -2

=50

b) (38- 42 +14) - (23 -21  +10)

=10- 12

=-2

c)-  (21 -32) - ( -12 +32)

=10 - 20

=-9

a: \(3^2\cdot\frac{1}{243}\cdot81^2\cdot\frac{1}{3^2}\)

\(=\frac{3^2}{3^5}\cdot\frac{3^8}{3^2}=\frac{1}{3^3}\cdot3^6=3^3=27\)

b: \(4^6\cdot256^2\cdot2^4=\left(2^2\right)^6\cdot\left(2^8\right)^2\cdot2^4\)

\(=2^{12}\cdot2^{16}\cdot2^4=2^{12}\cdot2^{20}=2^{32}\)

c: \(4^6\cdot9^5+6^9\cdot120\)

\(=2^{12}\cdot3^{10}+2^9\cdot3^9\cdot2^3\cdot3\cdot5\)

\(=2^{12}\cdot3^{10}+2^{12}\cdot3^{10}\cdot5\)

\(=2^{12}\cdot3^{10}\cdot6=2^{13}\cdot3^{11}\)

Ta có \(8^4\cdot3^{12}-6^{11}\)

\(=2^{12}\cdot3^{12}-2^{11}\cdot3^{11}\)

\(=2^{11}\cdot3^{11}\left(2\cdot3-1\right)=2^{11}\cdot3^{11}\cdot5\)

Ta có: \(A=\frac{4^6\cdot9^5+6^9\cdot120}{8^4\cdot3^{12}-6^{11}}\)

\(=\frac{2^{13}\cdot3^{11}}{2^{11}\cdot3^{11}\cdot5}=\frac{2^2}{5}=\frac45\)

d: \(4^2\cdot25^2+32\cdot125\)

\(=2^4\cdot5^4+2^5\cdot5^3\)

\(=2^4\cdot5^3\left(5+2\right)=2^4\cdot5^3\cdot7\)

\(B=\frac{4^2\cdot25^2+32\cdot125}{2^3\cdot5^2}\)

\(=\frac{2^4\cdot5^3\cdot7}{2^3\cdot5^2}=2\cdot5\cdot7=70\)

a)  − 105 + − 25 + ( − 105 ) + 50  

= 105 + 25 + ( - 105) + 50

= [105 + ( -105)] + ( 25 + 50 )

= 0 + 75 = 75

b)  465 + − 38 + − 465 − 12 − − 42

= 465 + ( - 38) + ( -465) – 12 – 42

= [ 465 + (- 465) ] – ( 12 + 42 )

= 0 – 54 = 0 + ( -54 ) = -54

c)  65. − 19 + − 19 .24 + − 19 .11

= ( - 19) . ( 65 + 24 + 11 )

= ( -19) . 100 = -1900

d)  − 3 2 + 2 3 − − 5 2 + 4 3

= 9 + 8 – 25 + 64 = 56

       \(\left(\frac{42}{32}:\frac{7}{8}\right).\frac{3}{4}\)

\(=\left(\frac{42}{32}.\frac{8}{7}\right).\frac{3}{4}\)

\(=\frac{3}{2}.\frac{3}{4}\)

\(=\frac{9}{8}\)

a) -48 + (-35 + 19) - (32 + 45 + 21)

= -48 - 35 + 19 - 32 - 45 - 21

= (-48 - 32) - (35 + 45) + (19 - 21)

= -80 - 80 - 2

= -162

b) -47 + (38 - 13) - (-52 + 31 - 91)

= -47 + 38 - 13 + 52 - 31 + 91

= (-47 - 13) + (38 + 52) - 31

= -60 + 90 - 31

= 30 - 31 = -1

c) 54 + (-37) - (+70) + (-163) - (-246) + (-230

= 54 - 37 - 70 - 163 + 246 - 230

= (54 + 246) - (37 + 163) - (70 + 230)

= 300 - 200 - 300

= -200

còn lại tự lm

Tính hợp lý :

A, (-48)+(-35+19)-(32+45+21)

B, (-47)+(38-13)-(-52+31-91)

C, 54+(-37)-(+70)+(-163)-(-246)+(-230

B3:

a. =-1250000

b. =-20000

c. =0

d. =-24000

B4:

a. =-4100

b. =-2700

c. =400

d. =1007

=1/4.5+1/5.6+1/6.7+...