Tìm x, biết :
( 3x - 24 ) . 73= 2 . 74
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(3x − 24).73 = 2.74
3x − 24 = 2.74 : 73
3x − 24 = 2.74 - 1
3x – 16 = 2.7
3x – 16 = 14
3x = 14 + 16
3x = 30
x = 30 : 3
x = 10
Vậy x = 10
a) Xem lại đề.
b) 5. (x - 3)2 + 17 = 142
5. (x - 3)2 = 142 - 17
5. (x - 3)2 = 125
(x - 3)2 = 125 : 5
(x - 3)2 = 25
(x - 3)2 = 52 (cùng số mũ)
⇒ x - 3 = 5
x = 5 + 3 = 8
c) [(6x - 72) : 2 - 84] . 28 = 5628
[(6x - 72) : 2 - 84] = 5628 : 28
[(6x - 72) : 2 - 84] = 201
(6x - 72) : 2 = 201 + 84
(6x - 72) : 2 = 285
6x - 72 = 285. 2
6x - 72 = 570
6x = 570 + 72
6x = 642
x = 642 : 6
x = 107
( 3 \(\times\) \(x\) - 24) \(\times\) 73 = 2\(\times\) 74
(3 \(\times\) \(x\) - 16) \(\times\) 73 = 4802
3\(\times\) \(x\) - 16 = 4802: 73
3\(\times\) \(x\) = \(\dfrac{4802}{73}\) + 16
3\(\times\) \(x\) = \(\dfrac{5970}{73}\)
\(x\) = \(\dfrac{5970}{73}\) : 3
\(x\) = \(\dfrac{1990}{73}\)
\(\left(3x-2^4\right)\cdot73=2\cdot7^4\\ \Leftrightarrow3x-2^4=\dfrac{4802}{73}\\ \Leftrightarrow3x=\dfrac{5970}{73}\\ \Leftrightarrow x=\dfrac{1990}{73}\)
Vậy x = \(\dfrac{1990}{73}\)
g) x - [ 42 + (-28)] = -8
\(\Rightarrow x-\left(42-28\right)=-8\)
\(\Rightarrow x-14=-8\)
\(\Rightarrow x=-8+14\)
\(\Rightarrow x=6\)
e) | x - 3| = |5| + | -7|
\(\Rightarrow\left|x-3\right|=5+7\)
\(\Rightarrow\left|x-3\right|=12\)
\(\Rightarrow\orbr{\begin{cases}x-3=12\\x-3=-12\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=15\\x=-9\end{cases}}\)
a: \(x^3=27\)
=>\(x^3=3^3\)
=>x=3
b: \(\left(2x-1\right)^3=8\)
=>\(\left(2x-1\right)^3=2^3\)
=>2x-1=2
=>2x=2+1=3
=>\(x=\frac32=1,5\)
c: \(\left(x-2\right)^2=16\)
=>\(\left[\begin{array}{l}x-2=4\\ x-2=-4\end{array}\right.\Rightarrow\left[\begin{array}{l}x=4+2=6\\ x=-4+2=-2\end{array}\right.\)
d: \(\left(2x-3\right)^2=9\)
=>\(\left[\begin{array}{l}2x-3=3\\ 2x-3=-3\end{array}\right.\Longrightarrow\left[\begin{array}{l}2x=6\\ 2x=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=3\\ x=0\end{array}\right.\)
e: \(2x+5=3^4:3^2\)
=>\(2x+5=3^2=9\)
=>2x=9-5=4
=>\(x=\frac42=2\)
f: \(\left(3x-2^4\right)\cdot7^3=2\cdot7^4\)
=>\(3x-16=2\cdot\frac{7^4}{7^3}=2\cdot7=14\)
=>3x=16+14=30
=>\(x=\frac{30}{3}=10\)
a: \(x^3=27\)
=>\(x^3=3^3\)
=>x=3
b: \(\left(2x-1\right)^3=8\)
=>\(\left(2x-1\right)^3=2^3\)
=>2x-1=2
=>2x=2+1=3
=>\(x=\frac32=1,5\)
c: \(\left(x-2\right)^2=16\)
=>\(\left[\begin{array}{l}x-2=4\\ x-2=-4\end{array}\right.\Rightarrow\left[\begin{array}{l}x=4+2=6\\ x=-4+2=-2\end{array}\right.\)
d: \(\left(2x-3\right)^2=9\)
=>\(\left[\begin{array}{l}2x-3=3\\ 2x-3=-3\end{array}\right.\Longrightarrow\left[\begin{array}{l}2x=6\\ 2x=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=3\\ x=0\end{array}\right.\)
e: \(2x+5=3^4:3^2\)
=>\(2x+5=3^2=9\)
=>2x=9-5=4
=>\(x=\frac42=2\)
f: \(\left(3x-2^4\right)\cdot7^3=2\cdot7^4\)
=>\(3x-16=2\cdot\frac{7^4}{7^3}=2\cdot7=14\)
=>3x=16+14=30
=>\(x=\frac{30}{3}=10\)
(3x-24).73=3.73
(3x-24).73=219
(3x-24)=219:73
(3x-24)=3
3x=3+24
3x=27
x=27:3
x=9
\(\left(3x-24\right).73=3.73\Leftrightarrow3x-24=3\Leftrightarrow3x=3+24=27\Leftrightarrow x=\dfrac{27}{3}=9\)vậy \(x=9\)
\(\left(3x-2^4\right).7^3=2.7^4\)
\(\left(3x-2^4\right).7^3=4802\)
\(\left(3x-2^4\right)=4802:7^3\)
\(3x-16=14\)
\(3x=14+16\)
\(3x=30\)
\(\Rightarrow x=10\)