mn giải giúp mik nha. mik đg cần gấp!!!!!


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\(\text{Bài 1:a)}25\dfrac{3}{19}.\left(-\dfrac{4}{5}\right)-35\dfrac{3}{19}.\left(-\dfrac{4}{5}\right)\)
\(=\dfrac{478}{19}.\left(-\dfrac{4}{5}\right)-\dfrac{668}{19}.\left(-\dfrac{4}{5}\right)\)
\(=\left(-\dfrac{4}{5}\right).\left(\dfrac{478}{19}-\dfrac{668}{19}\right)\)
\(=\left(-\dfrac{4}{5}\right).\left(\dfrac{-190}{19}\right)\)
\(=\left(-\dfrac{4}{5}\right).\left(-10\right)=8\)
\(\text{b)}5:\left(-\dfrac{5}{2}\right)^2+\dfrac{2}{15}.\sqrt{\dfrac{9}{4}}-\left(-2021\right)^0+0,25\)
\(=5:\dfrac{25}{4}+\dfrac{2}{15}.\dfrac{3}{2}-1+\dfrac{1}{4}\)
\(=\dfrac{4}{5}+\dfrac{1}{5}-1+\dfrac{1}{4}\)
\(=1-1+\dfrac{1}{4}\)
\(=0+\dfrac{1}{4}=\dfrac{1}{4}\)
\(\text{Bài 2:a)}\dfrac{8}{5}-\dfrac{3}{5}:x=0,4\)
\(\dfrac{3}{5}:x=\dfrac{8}{5}-0,4=\dfrac{6}{5}\)
\(x=\dfrac{3}{5}.\dfrac{5}{6}=\dfrac{1}{2}\)
\(\text{b)}\left(3x-\dfrac{1}{2}\right)^2+\dfrac{21}{25}=1\)
\(\left(3x-\dfrac{1}{2}\right)^2\) \(=1-\dfrac{21}{25}=\dfrac{4}{25}=\pm\left(\dfrac{2}{5}\right)^2\)
\(\text{Vậy }3x-\dfrac{1}{2}=\dfrac{2}{5}\)
\(3x\) \(=\dfrac{2}{5}+\dfrac{1}{2}=\dfrac{9}{10}\)
\(x\) \(=\dfrac{9}{10}.\dfrac{1}{3}=\dfrac{3}{10}\)
\(\text{hoặc }3x-\dfrac{1}{2}=\dfrac{-2}{5}\)
\(3x\) \(=\left(\dfrac{-2}{5}\right)+\dfrac{1}{2}=\dfrac{1}{10}\)
\(x\) \(=\dfrac{1}{10}.\dfrac{1}{3}=\dfrac{1}{30}\)
\(\Rightarrow x\in\left\{\dfrac{3}{10};\dfrac{1}{30}\right\}\)
Bài 2:
a: =>3/5:x=6/5
hay x=3/5:6/5=1/2
b: \(\Leftrightarrow\left(3x-\dfrac{1}{2}\right)^2=\dfrac{4}{5}\)
\(\Leftrightarrow\left[{}\begin{matrix}3x-\dfrac{1}{2}=\dfrac{2}{5}\\3x-\dfrac{1}{2}=-\dfrac{2}{5}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{10}\\x=\dfrac{1}{30}\end{matrix}\right.\)
Bài 4:
a: Xét ΔABI và ΔACI có
AB=AC
AI chung
BI=CI
Do đó: ΔABI=ΔACI
b: Xét tứ giác ABDC có
I là trung điểm của BC
I là trung điểm của AD
Do đó: ABDC là hình bình hành
Suy ra: AB=CD
Độ dãn của lò xo:
\(F_{đh}=k\cdot\Delta l\Rightarrow\Delta l=\dfrac{F_{đh}}{k}=\dfrac{2}{100}=0,02\)m=2cm
hai bài câu a mik lm đc r nhe mn lm giúp mik câu b thôi ạ mik ko bt lm;-;
Bài 3:
\(a,=-\left(x^2-2x+1\right)-2=-\left(x-1\right)^2-2\le-2\)
Dấu \("="\Leftrightarrow x=1\)
\(b,=-2\left(x^2+2\cdot\dfrac{1}{4}x+\dfrac{1}{16}\right)+\dfrac{9}{8}=-2\left(x+\dfrac{1}{4}\right)^2+\dfrac{9}{8}\le\dfrac{9}{8}\)
Dấu \("="\Leftrightarrow x=-\dfrac{1}{4}\)
Bài 4:
\(a,=\left(x^2+2\cdot\dfrac{5}{2}x+\dfrac{25}{4}\right)-\dfrac{21}{4}=\left(x+\dfrac{5}{2}\right)^2-\dfrac{21}{4}\ge-\dfrac{21}{4}\)
Dấu \("="\Leftrightarrow x=-\dfrac{5}{2}\)
\(b,=\left(x^2-8x+16\right)+1=\left(x-4\right)^2+1\ge1\)
Dấu \("="\Leftrightarrow x=4\)
bài 1
1 an
2 any
3 any
4 some
5 any
6 any
7 some
8 some
9 any
10 some
11 any
12 sone
13 some
14 any
bài 2
1 how many
2 how much
3 how much
4 how many
5 how many
6 how much
7 how much
8 how much
9 how many
10 how many
11 how many
12 how many
bài 3
how many eggs are there ?
how much tomato juice is there ?
how many packet of pasta is there ?
how many red peper are there ?
how many beans are there ?
how many pizza is there ?
how much salt is there ?
bài 4
1 are
2 aren't
3 a
4 an
5 any
6 isn't
7 many
8 is
9 some
10 much
11 any
12 some
bài 4
mình làm những cái đếm dcd còn mấy cái còn lại là ko đếm dcd
2 C
5 C
6 C
7 c
8 c
10 c
11 c
14c
15c
16c
18c
20c
22c
23c
24c
25c
26c
Câu 4:
a: Xét ΔABD và ΔAED có
AB=AE
\(\widehat{BAD}=\widehat{EAD}\)
AD chung
Do đó: ΔABD=ΔAED
Câu 1:
\(a,=\dfrac{1}{2}+9\cdot\dfrac{1}{9}-18=\dfrac{1}{2}+1-18=-\dfrac{33}{2}\\ b,=2-1+4\cdot\dfrac{1}{4}+9\cdot\dfrac{1}{9}\cdot9=1+1+9=11\\ c,=-21,3\left(54,6+45,4\right)=-21,3\cdot100=-2130\\ d,B=\left(\dfrac{1}{16}+\dfrac{1}{2}-\dfrac{1}{16}\right):\left(\dfrac{1}{8}-\dfrac{1}{8}+1\right)=\dfrac{1}{2}:1=\dfrac{1}{2}\)
đề khó nhìn quá
I.
1A
2C
3A
4C
5B
6B
7C
8B
9B
10C
II.
1T
2F
3F
4T
5F
6T
7F
8T
9F
10F








Câu 1:
a: \(5\cdot4^2-18:3^2\)
\(=5\cdot16-18:9\)
=80-2
=78
b: \(3^3\cdot18-3^3\cdot12=3^3\cdot\left(18-12\right)=27\cdot6=162\)
c: \(39\cdot213+87\cdot39\)
\(=39\cdot\left(213+87\right)\)
\(=39\cdot300=11700\)
d: \(80-\left\lbrack130-\left(12-4\right)^2\right\rbrack\)
\(=80-130+8^2\)
=-50+64
=14
e: \(27\cdot75+25\cdot27-150\)
\(=27\cdot\left(75+25\right)-150\)
=2700-150
=2550
f: \(12:\left\lbrace390:\left\lbrack500-\left(125+35\cdot7\right)\right\rbrack\right\rbrace\)
\(=12:\left\lbrace390:\left\lbrack500-125-245\right\rbrack\right\rbrace\)
=12:{390:130}
=12:3
=4
Câu 2:
a: 541+(218-x)=735
=>541+218-x=735
=>769-x=735
=>x=769-735
=>x=34
b: 5(x+35)=515
=>x+35=515:5=103
=>x=103-35
=>x=68
c: 96-3(x+1)=42
=>3(x+1)=96-42=54
=>x+1=18
=>x=17
d: \(12x-33=3^2\cdot3^3\)
=>\(12x-33=3^5=243\)
=>12x=33+243=276
=>x=276:12=23
Câu 3:
a: Các số là ước của 96 là 3;4;16;48;96
b: Các ước lớn hơn 20 của 130 là 26;65;130
c: Các bội lớn hơn 50, nhỏ hơn 150 của 15 là 60;75;90;105;120;135
d: Ư(30)={1;-1;2;-2;3;-3;5;-5;6;-6;10;-10;15;-15;30;-30}