a) (4x-1)(2-x)-(2x-1)²

= 8x-4x²-2+x-(4x²-4x+1) = -8x²+13x-3

b) (15x⁴y⁵-30x³y⁴+35x³y⁴):(5x³y³)

= 3xy²-6y+7y = 3xy²+y

a: \(=8x-4x^2-2+2x-4x^2+4x-1\)

\(=-8x^2+14x-3\)

Bài 3:

3: \(6x\left(x-y\right)-9y^2+9xy\)

\(=6x\left(x-y\right)+9xy-9y^2\)

\(=6x\left(x-y\right)+9y\left(x-y\right)\)

\(=\left(x-y\right)\left(6x+9y\right)\)

\(=3\left(2x+3y\right)\left(x-y\right)\)

Bài 4:

Answer:

\(3x^2.\left(2x^3-x+5\right)\)

\(=3x^2.2x^3+3x^2.(-x)+3x^2.5\)

\(=6x^5-3x^3+15x^2\)

\((4xy+3y-5x).x^2y\)

\(=4xy.x^2y+3y.x^2y-5x.x^2y\)

\(=4x^3+3x^2y^2-5x^3y\)

Câu hỏi của TRẦN THỊ BÍCH HỒNG - Toán lớp 7 - Học toán với OnlineMath

Thực hiện các phép tính sau:      

    \(\text{a) 3x². (2x³ – x + 5)=}6x^6-3x^3+15x^2\)

   \(\text{ b) (4xy + 3y – 5x). x²y}=4x^3y^2+3x^2y^2-5x^3y\)

\(\text{ d) ( 3x – 5 )( x²– 5x + 7 )}=3x^3+21x-35\)

Học tốt

a)=6x^5-3x^3+15x^2

b)=4x^3y^2+3x^2y^2-5x^3y

c)=3x^3-5x^2-15x^2+25x+21x-35=3x^3-20x^2+46x-35

\(=-4a^2x^3y+6x^3y^2-10x^3y^2z\)

b: \(\frac{-20x}{3y^2}:\frac{-4x^3}{5y}=\frac{-20x}{3y^2}\cdot\frac{5y}{-4x^3}=\frac{20\cdot5\cdot xy}{3y^2\cdot4x^3}=\frac{100xy}{12x^3y^2}=\frac{25}{3x^2y}\)

c: \(\frac{4x+12}{\left(x+4\right)^2}:\frac{3\left(x+3\right)}{x+4}\)

\(=\frac{4\left(x+3\right)}{\left(x+4\right)^2}\cdot\frac{x+4}{3\cdot\left(x+3\right)}\)

\(=\frac{4}{3\left(x+4\right)}\)

a: Sửa đề: \(\frac{3y}{28x^2}\cdot\frac{2x}{7y^4}\cdot49x^4y^3\)

\(=\frac{3y}{7y^4}\cdot\frac{2x}{28x^2}\cdot49x^4y^3\)

\(=\frac{3}{7y^3}\cdot\frac{1}{14x}\cdot49x^4y^3=\frac37\cdot\frac{1}{14}\cdot49\cdot\frac{x^4}{x}\cdot\frac{y^3}{y^3}=\frac37\cdot\frac72\cdot x^3=\frac32x^3\)