bn viết tke bố tôi cx ko hiểu đc

\(\frac{4}{5}\). X -X-\(\frac{3}{2}\). X+\(\frac{4}{3}\)

X.(\(\frac{4}{5}\)-1+\(\frac{4}{3}\))-3/2

X.17/15-3/2=-7/10

X.17/15     =4/5

X               =12/17

k nhé

10/3 x 1/2 - ( 1/2 x X - 1/3) + 1/5 = 3/5 :1/2

5/3 - ( 1/2 x X - 1/3) + 1/5 = 6/5

5/3 - ( 1/2 x X - 1/3) = 6/5 + 1/5

5/3 - ( 1/2 x X - 1/3) = 7/5

1/2 x X - 1/3 = 5/3 - 7/5

1/2 x X - 1/3 = 4/15

1/2 x X = 4/15 + 1/3

1/2 x X = 9/15

X = 9/15 : 1/2

X = 18/15.

Đây nha

\(a=4^5.9^4-2.\dfrac{6^9}{2^{10}}.3^8+6^8.20\)

Đề là như vầy đúng ko bn?

$\textbf{A)}$

$\dfrac{4^5\cdot9^4-2\cdot6^9}{2^{10}\cdot3^8+6^8\cdot20}$

$=\dfrac{(2^2)^5(3^2)^4-2(2\cdot3)^9}{2^{10}\cdot3^8+2^2\cdot5(2\cdot3)^8}$

$=\dfrac{2^{10}3^8-2^{10}3^9}{2^{10}3^8+2^{10}\cdot5\cdot3^8}$

$=\dfrac{2^{10}3^8(1-3)}{2^{10}3^8(1+5)}$

$=\dfrac{-2}{6}$

$=-\dfrac{1}{3}.$

co ai giai dc ko cau 60 % .....

$\textbf{Ta có:}$

$A=\dfrac{-5^2-5\cdot3^2}{5^3+5^2\cdot3^2}$

$=\dfrac{-25-45}{125+225}$

$=\dfrac{-70}{350}$

$=-\dfrac15.$

Và

$B=\dfrac{2^{12}\cdot3^{10}+6^9\cdot120}{2^{12}\cdot3^{12}-2^{11}\cdot3^{11}}$

$=\dfrac{2^{12}3^{10}+2^{12}3^{10}\cdot5}{2^{11}3^{11}(2\cdot3-1)}$

$=\dfrac{2^{12}3^{10}(1+5)}{2^{11}3^{11}\cdot5}$

$=\dfrac{2^{12}3^{10}\cdot6}{2^{11}3^{11}\cdot5}$

$=\dfrac{2^2}{5}$

$=\dfrac45.$

=> $M=B-A$$=\dfrac45-\left(-\dfrac15\right)$

$=\dfrac55$$=1.$

`(3)/(10).x=2-(1)/(5)`

`(3)/(10).x=(9)/(5)`

`x=(9)/(5):(3)/(10)`

`x=6`

=6