Tính ra thừa số nguyên tố

\(A=\frac{2^9.3^6:2^2:3^6}{2^2.271}\)

\(A=\frac{2^5}{271}=\frac{32}{271}\)

\(C=\frac{72^3.54^2}{1084}\)

 \(=\frac{\left(8.9\right)^3.\left(2.27\right)^2}{1084}\)

\(=\frac{8^3.9^3.2^2.27^2}{1084}\)

\(=\frac{\left(2^3\right)^3.\left(3^2\right)^3.2^2.\left(3^3\right)^2}{1084}\)

\(=\frac{2^9.3^6.2^2.3^6}{1084}\)

\(=\frac{2^{11}.3^{12}}{1084}\)

\(=\frac{2^9.4.3^{12}}{271.4}\)

\(=\frac{2^9.3^{12}}{271}\)

bang 1004050.893

ket qua xau qua

nho h cho mik nha

1004050,893

=373248.2916:1084

=1088391168:1084

=1004050,893

\(C=\dfrac{72^3.54^2}{1084}\)

\(C=\dfrac{\left(2^3.3^2\right)^3.\left(2.3^3\right)^2}{2^2.271}\)

\(C=\dfrac{2^9.3^6.2^6.3^6}{2^2.271}\)

\(C=\dfrac{2^9.3^{12}}{271}\)

a: Sửa đề: \(\frac{72^3\cdot54^2}{108^4}\)

\(=\frac{\left(2^3\cdot3^2\right)^3\cdot\left(2\cdot3^3\right)^2}{\left(2^2\cdot3^3\right)^4}\)

\(=\frac{2^9\cdot3^6\cdot2^2\cdot3^6}{2^8\cdot3^{12}}=\frac{2^{11}}{2^8}\cdot\frac{3^{12}}{3^{12}}\)

\(=2^3=8\)

b: Sửa đề: \(\frac{3^{10}\cdot5+3^{10}\cdot11}{3^9\cdot2^4}=\frac{3^{10}\cdot\left(11+5\right)}{3^9\cdot16}=\frac{3^{10}}{3^9}=3\)

Sai đề.