2 / x + 13 / =46
2 x +6 = 56
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x la 134
ai ghé qua đây hoặc online thì tick cho mk đc ko zậy
2678:[462-2(x-6)]=13
=> x=134
Tick mk vài cái cho lên 230 nha !!!
2678:[462-2.(x-6)]=13
<=>462-2.(x-6)=2678:13
<=>462-2.(x-6)=206
<=>2.(x-6)=462-206
<=>2.(x-6)=256
<=>x-6=128
<=>x=134
k mik
`(2/(11.13)+2/(13.15)+....+2/(19.21)).462-[0,04/(x+1,05):0,12=19`
`=>(1/11-1/13+1/13-1/15+....+1/19-1/21).462-(2/(50(x+1,05)).25/3=19`
`=>(1/11-1/21).462-1/(3(x+1,05))=19`
`=>10/231. 462-1/(3x+3,15)=19`
`=>20-1/(3x+3,15)=19
`=>1/(3x+3,15)=1`
`=>3x+3,15=1`
`=>3x=-2,15`
`=>x=-43/60`
Vậy `x=-43/60`
Giải:
\(\left(\dfrac{2}{11.13}+\dfrac{2}{13.15}+...+\dfrac{2}{19.21}\right).462-\left[\dfrac{0,04}{x+1,05}:0,12\right]=19\)
\(\left(\dfrac{1}{11}-\dfrac{1}{13}+\dfrac{1}{13}-\dfrac{1}{15}+...+\dfrac{1}{19}-\dfrac{1}{21}\right).462-\left[\dfrac{1}{\dfrac{25}{x+\dfrac{21}{20}}}:\dfrac{3}{25}\right]=19\)
\(\left(\dfrac{1}{11}-\dfrac{1}{21}\right).462-\left[\dfrac{1}{25.\left(x+\dfrac{21}{20}\right)}:\dfrac{3}{25}\right]=19\)
\(20-\left[\dfrac{25.1}{3.25.\left(x+\dfrac{21}{20}\right)}\right]=19\)
\(\dfrac{1}{3.\left(x+\dfrac{21}{20}\right)}=20-19\)
\(\dfrac{1}{3.x+\dfrac{63}{20}}=1\)
\(1:\left(3.x+\dfrac{63}{20}\right)=1\)
\(3.x+\dfrac{63}{20}=1:1\)
\(3.x+\dfrac{63}{20}=1\)
\(3.x=1-\dfrac{63}{20}\)
\(3.x=\dfrac{-43}{20}\)
\(x=\dfrac{-43}{20}:3\)
\(x=\dfrac{-43}{60}\)
\(\left(\frac{2}{11\times13}+\frac{2}{13\times15}+\frac{2}{15\times17}+\frac{2}{17\times19}+\frac{2}{19\times21}\right)\times462-x=19\)
\(\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+...+\frac{1}{19}-\frac{1}{21}\right)\times462-x=19\)
\(\left(\frac{1}{11}-\frac{1}{21}\right)\times462-x=19\)
\(\frac{10}{231}\times462-x=19\)
\(20-x=19\)
\(\Rightarrow x=20-19=1\)
a)x-1,44:1,2=5,9
x-1,44=5,9x1,2
x-1,44=7,08
x=7,08+1,44
x=8,52
b)86,5-x:8,6=23,7
x:8,6=86,5-23,7
x:8,6=62,8
x=62,8x8,6
x=540,08
chúc bạn học tốt !!!
\(2\left|x+13=46\right|\)
\(\left|x+13\right|=46:2\)
\(\left|x+13\right|=13\)
\(\Leftrightarrow\orbr{\begin{cases}x+13=13\\x+13=-13\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=0\\x=-26\end{cases}}\)
Vậy ....
\(2x+6=56\)
\(2x=56-6\)
\(2x=50\)
\(x=50:2\)
\(x=25\)
2x-6=56
2x=56-6=50
x=50:2=5