K
Khách

Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.

22 tháng 9 2018

x * 2 + x * 1/5 = 1 và 3/5

x * ( 2 + 1/5) = 8/5

x * 11/5 = 8/5

x = 8/11

17 tháng 4

a: \(1\frac37-\frac78+2\frac45:2\)

\(=\frac{10}{7}-\frac78+\left(2+\frac45\right):2\)

\(=\frac{80}{56}-\frac{49}{56}+1+\frac25=\frac{31}{56}+\frac75=\frac{155+392}{280}=\frac{547}{280}\)

b: \(812\times X+188\times X=10000\)

=>\(X\times\left(812+188\right)=10000\)

=>\(1000\times X=10000\)

=>X=10000:1000=10

DD
17 tháng 1 2022

\(1\frac{3}{7}\times1\frac{3}{10}\times1\frac{3}{13}\times...\times1\frac{3}{67}\)

\(=\frac{10}{7}\times\frac{13}{10}\times\frac{16}{13}\times...\times\frac{70}{67}\)

\(=\frac{10\times13\times16\times...\times70}{7\times10\times13\times...\times67}\)

\(=\frac{70}{7}=10\)

19 tháng 7 2021

Ta có: \(2015\cdot1\dfrac{3}{4}=2015\cdot\dfrac{7}{4}\)

22 tháng 5 2021

D chonj caau tl cuar mk nhes

8 tháng 9 2023

2:

a: =>x^2+3x-4x-12-(x^2-5x+x-5)=8

=>x^2-x-12-x^2+4x+5=8

=>3x-7=8

=>3x=15

=>x=5

b: =>3x^2+3x-2x-2-3x^2-21x=13

=>-20x=15

=>x=-3/4

c: =>x^2-25-x^2-2x=9

=>-2x=25+9=34

=>x=-17

d: =>x^3-1-x^3+3x=1

=>3x-1=1

=>3x=2

=>x=2/3

17 tháng 8 2023

a: =>x-2/5=3/4:1/3=3/4*3=9/4

=>x=9/4+2/5=45/20+8/20=53/20

b: =>x-2/3=7/3:4/5=7/3*5/4=35/12

=>x=35/12+2/3=43/12

c: 1/3(x-2/5)=4/5

=>x-2/5=4/5*3=12/5

=>x=12/5+2/5=14/5

d: =>2/3x-1/3-1/4x+1/10=7/3

=>5/12x-7/30=7/3

=>5/12x=7/3+7/30=77/30

=>x=77/30:5/12=154/25

e: \(\Leftrightarrow x\cdot\dfrac{3}{7}-\dfrac{2}{7}+\dfrac{1}{2}-\dfrac{5}{4}x+\dfrac{5}{2}=0\)

=>\(x\cdot\dfrac{-23}{28}=\dfrac{2}{7}-3=\dfrac{-19}{7}\)

=>x=19/7:23/28=76/23

f: =>1/2x-3/2+1/3x-4/3+1/4x-5/4=1/5

=>13/12x=1/5+3/2+4/3+5/4=257/60

=>x=257/65

i: =>x^2-2/5x-x^2-2x+11/4=4/3

=>-12/5x=4/3-11/4=-17/12

=>x=17/12:12/5=85/144

7 tháng 10 2025

1: \(x\left(1-x\right)+\left(x-1\right)^2\)

\(=x-x^2+x^2-2x+1\)

=-x+1

3: \(\left(x+2\right)^2-\left(x-3\right)\left(x+1\right)\)

\(=x^2+4x+4-\left(x^2+x-3x-3\right)\)

\(=x^2+4x+4-\left(x^2-2x-3\right)\)

\(=x^2+4x+4-x^2+2x+3=6x+7\)

5: \(\left(x-2\right)^2+\left(x-1\right)\left(x+5\right)\)

\(=x^2-4x+4+x^2+5x-x-5\)

\(=2x^2-1\)

7: \(\left(1-2x\right)\left(5-3x\right)+\left(4-x\right)^2\)

\(=\left(2x-1\right)\left(3x-5\right)+\left(x-4\right)^2\)

\(=6x^2-10x-3x+5+x^2-8x+16\)

\(=7x^2-21x+21\)

9: \(\left(x+1\right)^2+\left(x-2\right)\left(x+2\right)-4x\)

\(=x^2+2x+1+x^2-4-4x\)

\(=2x^2-2x-3\)

11: \(\left(x+4\right)^2+\left(x+5\right)\left(x-5\right)-2x\left(x+1\right)\)

\(=x_{}^2+8x+16+x^2-25-2x^2-2x\)

=6x-9

13: \(\left(x-1\right)^2-2\left(x+3\right)\left(x-3\right)+4x\left(x-4\right)\)

\(=x^2-2x+1-2\left(x^2-9\right)+4x^2-16x\)

\(=5x^2-18x+1-2x^2+18=3x^2-18x+19\)

2: \(\left(x-3\right)^2-x^2+10x-7\)

\(=x^2-6x+9-x^2+10x-7\)

=4x+2

4: \(\left(x+4\right)\left(x-2\right)-\left(x-3\right)^2\)

\(=x^2-2x+4x-8-\left(x^2-6x+9\right)\)

\(=x^2+2x-8-x^2+6x-9=8x-17\)

6: (x-3)(x+3)-x(x+23)

\(=x^2-9-x^2-23x\)

=-23x-9

8: (x-2)(x+2)-(x-3)(x+1)

\(=x^2-4-\left(x^2+x-3x-3\right)\)

\(=x^2-4-\left(x^2-2x-3\right)\)

\(=x^2-4-x^2+2x+3=2x-1\)

10: \(\left(x+2\right)^2-\left(x+3\right)\left(x-3\right)+10\)

\(=x^2+4x+4-\left(x^2-9\right)+10\)

\(=x^2+4x+14-x^2+9=4x+23\)

12: \(\left(x-1\right)^2-\left(x-4\right)\left(x+4\right)+\left(x+3\right)^2\)

\(=x^2-2x+1-\left(x^2-16\right)+x^2+6x+9\)

\(=2x^2+4x+10-x^2+16=x^2+4x+26\)

14 tháng 4 2023

Bài 1: 

a) \(-5\left(x^2-3x+1\right)+x\left(1+5x\right)=x-2\)

\(\Rightarrow-5x^2+15x-5+x+5x^2=x-2\)

\(\Rightarrow16x-5=x-2\)

\(\Rightarrow16x-x=5-2\)

\(\Rightarrow15x=3\)

\(\Rightarrow x=\dfrac{15}{3}=5\)

b) \(12x^2-4x\left(3x+5\right)=10x-17\)

\(\Rightarrow12x^2-12x^2-20x=10x-17\)

\(\Rightarrow-20x=10x-17\)

\(\Rightarrow-20x-10x=-17\)

\(\Rightarrow-30x=-17\)

\(\Rightarrow x=\dfrac{-30}{-17}=\dfrac{30}{17}\)

c) \(-4x\left(x-5\right)+7x\left(x-4\right)-3x^2=12\)

\(\Rightarrow-4x^2+20x+7x^2-28x-3x^2=12\)

\(\Rightarrow-8x=12\)

\(\Rightarrow x=\dfrac{12}{-8}=-\dfrac{4}{3}\)

Bài 2: 

a) \(\left(x+5\right)\left(x-7\right)-7x\left(x-3\right)\)

\(=x^2-7x+5x-35-7x^2+21x\)

\(=-6x^2+19x-35\)

b) \(x\left(x^2-x-2\right)-\left(x-5\right)\left(x+1\right)\)

\(=x^3-x^2-2x-x^2+x-5x-5\)

\(=x^3-2x^2-6x-5\)

c) \(\left(x-5\right)\left(x-7\right)-\left(x+4\right)\left(x-3\right)\)

\(=x^2-7x-5x+35-x^2-3x+4x-12\)

\(=11x+23\)

d) \(\left(x-1\right)\left(x-2\right)-\left(x+5\right)\left(x+2\right)\)

\(=x^2-2x-x+2-x^2+2x+5x+10\)

\(=4x+12\)

12 tháng 9 2021

1: Ta có: \(x^2-2x+5-\left(x-7\right)\left(x+2\right)\)

\(=x^2-2x+5-x^2-2x+7x-14\)

\(=3x-9\)

2: Ta có: \(-5x\left(x-5\right)+\left(x-3\right)\left(x^2-7\right)\)

\(=-5x^2+25x+x^3-7x-3x^2+21\)

\(=x^3-8x^2+18x+21\)

3: Ta có: \(x\left(x^2-x-2\right)-\left(x+5\right)\left(x-1\right)\)

\(=x^3-x^2-2x-x^2-4x+5\)

\(=x^3-2x^2-6x+5\)