tim x
a,50 chia hết cho x, 48 chia hết cho x
b,12 chia hết 2x + 1
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a: \(\left(-120\right):15+12\left(2x-1\right)=52\)
=>\(12\left(2x-1\right)-8=52\)
=>\(12\left(2x-1\right)=60\)
=>\(2x-1=\dfrac{60}{12}=5\)
=>2x=5+1=6
=>\(x=\dfrac{6}{2}=3\)
c: \(x+4⋮x+1\)
=>\(x+1+3⋮x+1\)
=>\(3⋮x+1\)
=>\(x+1\in\left\{1;-1;3;-3\right\}\)
=>\(x\in\left\{0;-2;2;-4\right\}\)
d: \(2x+7⋮x+2\)
=>\(2x+4+3⋮x+2\)
=>\(3⋮x+2\)
=>\(x+2\in\left\{1;-1;3;-3\right\}\)
=>\(x\in\left\{-1;-3;1;-5\right\}\)
e: \(3x⋮x-1\)
=>\(3x-3+3⋮x-1\)
=>\(3⋮x-1\)
=>\(x-1\in\left\{1;-1;3;-3\right\}\)
=>\(x\in\left\{2;0;4;-2\right\}\)
7A. Tìm x ∈ Z sao cho:
a) x + 6 chia hết cho x
b) x + 9 chia hết cho x + 1
c) 2x + 1 chia hết cho x - 1
a: x+6⋮x
=>6⋮x
=>x∈{1;-1;2;-2;3;-3;6;-6}
b: x+9⋮x+1
=>x+1+8⋮x+1
=>8⋮x+1
=>x+1∈{1;-1;2;-2;4;-4;8;-8}
=>x∈{0;-2;1;-3;3;-5;7;-9}
c: 2x+1⋮x-1
=>2x-2+3⋮x-1
=>3⋮x-1
=>x-1∈{1;-1;3;-3}
=>x∈{2;0;4;-2}
Sao câu này giống https://hoc24.vn/cau-hoi/7a-tim-x-z-sao-choa-x-6-chia-het-cho-xb-x-9-chia-het-cho-x-1c-2x-1-chia-het-cho-x-1.3203518129748 thế?
a: \(x\in\left\{1;7\right\}\)
b: \(x+1=1\)
hay x=0
\(a,\Rightarrow x\inƯ\left(7\right)=\left\{-7;-1;1;7\right\}\\ b,\Rightarrow2\left(x+1\right)-1⋮x+1\\ \Rightarrow x+1\inƯ\left(1\right)=\left\{-1;1\right\}\\ \Rightarrow x\in\left\{-2;0\right\}\)
b: 2x-10⋮2x+1
=>2x+1-11⋮2x+1
=>-11⋮2x+1
=>2x+1∈{1;-1;11;-11}
=>2x∈{0;-2;10;-12}
=>x∈{0;-1;5;-6}
c: 2x+10⋮x+1
=>2x+2+8⋮x+1
=>8⋮x+1
=>x+1∈{1;-1;2;-2;4;-4;8;-8}
=>x∈{0;-2;1;-3;3;-5;7;-9}
d: x+3⋮12-x
=>x+3⋮x-12
=>x-12+15⋮x-12
=>15⋮x-12
=>x-12∈{1;-1;3;-3;5;-5;15;-15}
=>x∈{13;11;15;9;17;7;27;-3}
{ 1;2;4;8}
{-1;-2;-3;-4;-6;-12}
{-1;-2;-4;1;2;4}
{-18;-12}
{-36;36}
a/
50 chia hết cho x
48 chia hết cho x
=> x thuộc ƯC (50;48)
UCNN(50;48)=2
=>x thuộc U(2)={1;2}
b/
12 chia hết cho 2x+1
=> 2x+1 thuộc Ư(12)={1;2;3;4;6;12}
+/2x+1=1=>2x=0=>x=0(TM)
+/2x+1=2=>2x=1(L)
+/2x+1=3=>2x=2=>x=1(TM)
+/2x+1=4=>2x=3(L)
+/2x+1=6=>2x=5(L)
+/2x+1=12=>2x=11(L)
vậy x thuộc {0;1}
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