X x 2 + X x 8 = 2470

X x ( 2 + 8 )   = 2470

X x     10       = 2470

X                  = 2470 : 10

X                  = 247

X x 197 - X x 97 = 70600

X x ( 197 - 97 )   = 70600

X x      100         = 70600

X                       = 70600 : 100

X                       = 706

X x 2 + X x 8 = 2470

X x ( 2 + 8 )   = 2470

X x     10       = 2470

X                  = 2470 : 10

X                  = 247

X x 197 - X x 97 = 70600

X x ( 197 - 97 )   = 70600

X x      100         = 70600

X                       = 70600 : 100

b) Ta có: \(x-43=\left(57-x\right)-50\)

\(\Leftrightarrow x-43=57-x-50\)

\(\Leftrightarrow x+x=7+43\)

\(\Leftrightarrow2x=50\)

hay x=25

Vậy: x=25

c) Ta có: (x-2)(8-x)=0

\(\Leftrightarrow\left[{}\begin{matrix}x-2=0\\8-x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=8\end{matrix}\right.\)

Vậy: \(x\in\left\{2;8\right\}\)

Bạn làm câu a hộ mình

a: Ta có: \(\left(x-5\right)\left(x+3\right)=x\left(x-3\right)\)

\(\Leftrightarrow x^2-2x-15-x^2+3x=0\)

\(\Leftrightarrow x=15\)

b: Ta có: \(\left(x+2\right)^2=\left(x-1\right)\left(x+2\right)\)

\(\Leftrightarrow x+2=0\)

hay x=-2

c: Ta có: \(\left(x-6\right)\left(x+6\right)=x^2\)

\(\Leftrightarrow x^2-36=x^2\)(vô lý)

a. (x - 5)(x + 3) = x(x - 3)

<=> x² + 3x - 5x - 15 = x² - 3x

<=> x² - x² + 3x - 5x + 3x - 15 = 0

<=> x = 15

b. (x + 2)² = (x - 1)(x + 2)

<=> x² + 4x + 4 = x² + 2x - x - 2

<=> x² - x² + 4x - 2x + x = -2 - 4

<=> 3x = -5

<=> \(x=\dfrac{-5}{3}\)

c. (x - 6)(x + 6) = x²

<=> x² - 36 - x² = 0

<=> x² - x² = 36

<=> 0 = 36 (vô lí)

Vậy nghiệm của PT là \(S=\varnothing\)

d. (2x - 3)² = 4x² - 8 

<=> 4x² - 12x + 9 - 4x² + 8 = 0

<=> 4x² - 4x² - 12x = -8 - 9

<=> -12x = -17

<=> \(x=\dfrac{17}{12}\)

1.Tìm X:

a)  `x : 8 = 107,8 - 29,25`

`x:8=78,55`

`x=78,55xx8`

`x=628,4`

b) `x + 16,7 = 50,5 : 2,5`

`x+16,7=20,2`

`x=20,2-16,7`

`x=3,5`

2.Tìm X:

a) `x - 2,35  =  3,6 : 4,5` 

`x-2,35=0,8`

`x=0,8+2,35`

`x=3,15`

b) `189,5 - x = 7,2 xx 14`

`189,5 - x = 100,8`

`x=189,5-100,8`

`x=88,7`

3. Tính giá trị biểu thức :

`13,5 : 4,5 xx 2,4 + (156,9 – 80,6) `

`=3xx2,4+76,3`

`=7,2+76,3`

`=83,5`

4. Tính giá trị biểu thức :

`1,25 xx 4,2 + 119,6 : 5,2 – 23,19`

`=5,25+23-23,19`

`=5,06`

5. Tính giá trị biểu thức :

`14,75 – 7,15 : 5 + 2,6 xx 3,5`

`=14,75 – 1,43 + 9,1`

`=22,42`

6. Tính nhanh

a) `3,6 xx 78 + 78 xx 6,4=78xx(3,6+6,4)=78xx10=780`

b) `80 xx 5,29 xx 1,25=(80xx1,25)xx5,29=100xx5,29=529`

cám ơn bạn

a) Để (m-4)x+2-m=0 là phương trình bậc nhất ẩn x thì \(m-4\ne0\)

hay \(m\ne4\)

b) Để \(\left(m^2-4\right)x-m=0\) là phương trình bậc nhất ẩn x thì \(m^2-4\ne0\)

\(\Leftrightarrow m^2\ne4\)

hay \(m\notin\left\{2;-2\right\}\)

c) Để \(\left(m-1\right)x^2-6x+8=0\) là phương trình bậc nhất ẩn x thì \(m-1=0\)

hay m=1

d) Để \(\dfrac{m-2}{m-1}x+5=0\) là phương trình bậc nhất ẩn x thì \(\dfrac{m-2}{m-1}\ne0\)

\(\Leftrightarrow\left\{{}\begin{matrix}m-2\ne0\\m-1\ne0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}m\ne2\\m\ne1\end{matrix}\right.\)

Bài 2:

a: Ta có: \(2x+79=x+45\)

nên 2x-x=45-79

hay x=-24

b: Ta có: \(15-\left(x+7\right)=\left(x-8\right)+22\)

\(\Leftrightarrow8-x-x-14=0\)

\(\Leftrightarrow2x=22\)

hay x=11

a) `(x-8)(x^3+8)=0`

`<=>(x-8)(x+2)(x^2-2x+4)=0`

`<=>` \(\left[ \begin{array}{l}x=8\\x=-2\end{array} \right.\) (Vì `x^2-2x+4 \ne 0 forall x)`

Vậy `A={8;-2}`.

b) `(4x-3)-(x+5)=3(10-x)`

`,=>4x-3-x-5=30-3x`

`<=>3x-8=30-3x`

`<=>6x=38`

`<=>x=19/3`

Vậy `S={19/3}`.

a) Ta có: \(\left|4-5x\right|=24\)

\(\Leftrightarrow\left[{}\begin{matrix}-5x+4=24\\-5x+4=-24\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}-5x=20\\-5x=-28\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-4\\x=\dfrac{28}{5}\end{matrix}\right.\)

Vậy: \(x\in\left\{-4;\dfrac{28}{5}\right\}\)

b) Ta có: \(\left(8+x\right)\left(6-x\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x+8=0\\6-x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-8\\x=6\end{matrix}\right.\)

Vậy: \(x\in\left\{-8;6\right\}\)

a) \(\left|4-5x\right|=24\)

\(\Leftrightarrow\left[{}\begin{matrix}4-5x=24\\4-5x=-24\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=-4\\x=\dfrac{28}{5}\end{matrix}\right.\)

b) \(\left(8+x\right)\left(6-x\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}8+x=0\\6-x=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=-8\\x=6\end{matrix}\right.\)

\(a,\) \(5x\left(4-x\right)+\left(5x^2-12\right)=x+6\)

\(< =>20x-5x^2+5x^2-12-x-6=0\)

\(< =>19x-18=0\)

\(< =>x=\dfrac{18}{19}\)

\(b,\left(2x-7\right)\left(5+4x\right)-8\left(x^2-4x+5\right)=-30\)

\(< =>10x+8x^2-35-28x-8x^2+24x-40+30=0\)

\(< =>6x-45=0< =>x=\dfrac{45}{6}=7,5\)

a) \(5x\left(4-x\right)+\left(5x^2-12\right)=x+\Rightarrow6\\ \Leftrightarrow20x-5x^2+5x^2-12=x+6\\ \Leftrightarrow20x-12=x+6\\\Rightarrow20x-x=6+12\\ \Rightarrow19x=18\\ \Rightarrow x=\dfrac{18}{19}\)

b) \(\left(2x-7\right)\left(5+4x\right)-8\left(x^2-3x+5\right)=-30\\ \Rightarrow10x+8x^2-35-28x-8x^2+24x-40=-30\\ \Rightarrow6x-75=-30\\ \Rightarrow6x=45\\ \Rightarrow x=\dfrac{15}{2}\)