[( 36.36 - 19.19) . 17 -89] : 4 - 2
{ [ ( 37.37 - 12.12) : 25 - 25 ] : 6 - 19} .9
K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Những câu hỏi liên quan
NL
Nguyễn Lê Phước Thịnh
CTVHS
7 tháng 1 2022
7: =-1+8=7
6: \(=-\left(8\cdot125\right)\cdot\left(2\cdot5\right)\cdot\left(25\cdot4\right)=-1000000\)
5: =-50+19+143+79-25-48
=-75+98+95
=23+95
=118
4: =37x9+17x9-35x9-35x11
=18+153-385
=-214
NL
Nguyễn Lê Phước Thịnh
CTVHS
7 tháng 1 2022
3: =187-23-20+180
=367-43
=324
4: \(=37\cdot9+17\cdot9-35\cdot9-35\cdot11=19\cdot9-385\)
\(=171-385=-214\)
5: =-50+19+143+79-25-48
=-75+94+95
=20+94
=114
18 tháng 12 2017
a, 249 - 25 × 8 + 32 × 4
= 249 - 200 + 9 × 4
= 49 + 36
= 85
b,27 : { 480 : [(513 : 9 + 19 ) + 84 ]}
= 27 : { 480 : [(57 + 19) + 84 ]}
= 27 : { 480 : [76 + 84]}
= 27 : { 480 : 160}
= 27 : 3
= 9
c. 73 × 25 + 28 × 25 - 25
= 73 × 25 + 28 × 25 - 25 × 1
= 25 × (73 + 28 - 1)
= 25 × 100
= 2500
d. 2× 9 × 50 - 890
= (2 × 50) × 9 - 1
= 100 × 9 - 1
= 900 - 1
= 899
18 tháng 12 2017
a)\(249-25\cdot8+3^2\cdot4\)
\(=249-200+9\cdot4\)
\(=49+36=85\)
b)\(27:\left\{480:\left[\left(513:9+19\right)+84\right]\right\}\)
\(=27:\left\{480:\left[\left(57+19\right)+84\right]\right\}\)
\(=27:\left\{480:\left[76+84\right]\right\}\)
\(=27:\left\{480:160\right\}\)
\(=27:3=9\)
c)\(73\cdot25+28\cdot25-25\)
\(=73\cdot25+28\cdot25-25\cdot1\)
\(=\left(73+28-1\right)\cdot25\)
\(=100\cdot25=2500\)
d)\(2\cdot9\cdot50-89^0\)
\(=2\cdot9\cdot50-1\)
\(=900-1=899\)
7 tháng 1 2022
1) 125.(-24) + 24.225.
\(=24\left(-125+225\right)=24.100=2400.\)
2) 512.(2 – 128) – 128. (-512).
\(=512\left(2-128+128\right)=512.2=1024.\)
NI
13 tháng 3 2021
1) (-6 - 2) . (-6 + 2) = -8 . (-4) = 32
2) 627 + 125 + (-627) + |-46| -21 = 125 + 46 - 21 = 150
3) (-25) + 30 + (-16) + 25 + (-4) = 30 + (-20) = 10
4) 75 - 5.(15 - 40) - (-60) = 75 - 75 + 80 + 60 = 140
5) |31 - 17| - |15 - 52| = |14| - |-37| = 14 - 37 = -23
6) 13 - 18 - (-42) - 15 = 13 - 18 + 42 - 15 = 22
3 bài sau hết kiên nhẫn rồi, thông cảm nhé.
NL
Nguyễn Lê Phước Thịnh
CTVHS
2 tháng 6
1: \(\left(-\frac{25}{13}\right)+\left(-\frac{19}{17}\right)+\frac{12}{13}+\left(-\frac{25}{17}\right)\)
\(=\left(-\frac{25}{13}+\frac{12}{13}\right)+\left(-\frac{19}{17}-\frac{15}{17}\right)\)
\(=-\frac{13}{13}-\frac{34}{17}=-1-2=-3\)
2: \(\frac12-\left(-\frac13\right)+\frac{1}{23}+\frac16\)
\(=\left(\frac12+\frac13+\frac16\right)+\frac{1}{23}\)
\(=1+\frac{1}{23}=\frac{24}{23}\)
3: \(\left(-\frac37\right)\cdot\frac{5}{11}+\left(-\frac{5}{14}\right)\cdot\frac{5}{11}\)
\(=\frac{5}{11}\left(-\frac37-\frac{5}{14}\right)\)
\(=\frac{5}{11}\cdot\left(-\frac{6}{14}-\frac{5}{14}\right)=\frac{5}{11}\cdot\frac{-11}{14}=\frac{-5}{14}\)
4: \(\left(-\frac{5}{11}\right)\cdot\frac{7}{15}\cdot\frac{11}{-5}\cdot\left(-30\right)=-30\cdot\frac{7}{15}=-14\)
5: \(\left(-\frac59\right)\cdot\frac{3}{11}+\left(-\frac{13}{18}\right)\cdot\frac{3}{11}\)
\(=\frac{3}{11}\left(-\frac59-\frac{13}{18}\right)\)
\(=\frac{3}{11}\cdot\frac{-23}{18}=\frac{-23\cdot1}{11\cdot6}=-\frac{23}{66}\)
6: \(2\frac{2}{15}\cdot\frac{9}{17}\cdot\frac{3}{32}:\left(-\frac{3}{17}\right)\)
\(=\frac{32}{15}\cdot\frac{3}{32}\cdot\frac{9}{17}\cdot\frac{-17}{3}=\frac{3}{15}\cdot\frac{-9}{3}=\frac{-9}{15}=-\frac35\)
7: \(\left(-\frac34+\frac25\right):\frac37+\left(\frac35-\frac14\right):\frac37\)
\(=\left(-\frac34+\frac25+\frac35-\frac14\right):\frac37\)
\(=\left(-1+1\right):\frac37=0\)
8: \(\left(-\frac13\right)\cdot\left(-\frac{15}{19}\right)\cdot\frac{38}{45}=\frac{15}{45\cdot3}\cdot\frac{38}{19}=2\cdot\frac{1}{3\cdot3}=\frac29\)
9: \(\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\cdots+\frac{1}{19\cdot20}\)
\(=\frac12-\frac13+\frac13-\frac14+\cdots+\frac{1}{19}-\frac{1}{20}\)
\(=\frac12-\frac{1}{20}=\frac{9}{20}\)
10: \(\frac{1}{9\cdot10}-\frac{1}{8\cdot9}-\frac{1}{7\cdot8}-\cdots-\frac{1}{2\cdot3}-\frac{1}{1\cdot2}\)
\(=\frac{1}{9\cdot10}-\left(\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\cdots+\frac{1}{8\cdot9}\right)\)
\(=\frac19-\frac{1}{10}-\left(1-\frac12+\frac12-\frac13+\cdots+\frac18-\frac19\right)\)
\(=\frac19-\frac{1}{10}-\left(1-\frac19\right)=\frac19-\frac{1}{10}-\frac89=-\frac79-\frac{1}{10}=\frac{-79}{90}\)