Phân tích đa thức thành nhân tử : 18x^3 - 8/25.x
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câu b sai r
\(\dfrac{1}{3}xy+x^2z+xz=3x\left(\dfrac{1}{9}y+\dfrac{1}{3}xz+\dfrac{1}{3}z\right)\)
Lời giải:
a.
$=\frac{1}{2}(x^2-4y^2)=\frac{1}{2}[x^2-(2y)^2]=\frac{1}{2}(x-2y)(x+2y)$
b.
$=\frac{1}{3}x(y+3xz+3z)$
c.
$=\frac{2}{25}x(225x^2-4)=\frac{2}{25}(15x-2)(15x+2)$
d.
$=\frac{1}{5}x^2(2+25x+5y)$
a) \(x^3+9x^2+27x+27=\left(x+3\right)^3\)
b) \(3\sqrt{3x^3}+18x^2+12\sqrt{3x}+8=\left(\sqrt{3x}+2\right)^3\)
c) \(\dfrac{1}{4}-x^2=\left(\dfrac{1}{2}-x\right)\left(\dfrac{1}{2}+x\right)\)
a: \(\frac12x^2-2y^2=\frac12\left(x^2-4y^2\right)\)
\(=\frac12\left(x-2y\right)\left(x+2y\right)\)
b: \(\frac13xy+x^2z+xz\)
\(=x\cdot\frac13y+x\cdot xz+x\cdot z\)
\(=x\left(\frac13y+xz+z\right)\)
c: \(18x^3-\frac{8}{25}x=2x\left(9x^2-\frac{4}{25}\right)\)
\(=2x\left\lbrack\left(3x\right)^2-\left(\frac25\right)^2\right\rbrack\)
\(=2x\left(3x-\frac25\right)\left(3x+\frac25\right)\)
d: \(\frac25x^2+5x^3+x^2y=x^2\cdot\frac25+x^2\cdot5x+x^2\cdot y=x^2\left(\frac25+5x+y\right)\)
e: \(\frac12\left(x^2+y^2\right)^2-2x^2y^2\)
\(=\frac12\left\lbrack\left(x^2+y^2\right)^2-4x^2y^2\right\rbrack\)
\(=\frac12\left(x^2+y^2-2xy\right)\left(x^2+y^2+2xy\right)\)
\(=\frac12\left(x-y\right)^2\cdot\left(x+y\right)^2\)
f: \(27x^3-\frac18y^3=\left(3x\right)^3-\left(\frac12y\right)^3\)
\(=\left(3x-\frac12y\right)\left(9x^2+\frac32xy+\frac14y^2\right)\)
\(=\left(x^2+2x\right)^2+9\left(x^2+2x\right)+20\)
\(=\left(x^2+2x+4\right)\left(x^2+2x+5\right)\)
=5(x2-\(\frac{18}{5}x\)-\(\frac{8}{5}\))=5(x2+\(\frac{2}{5}x-4x-\frac{8}{5}\))
=5(x-4)(\(\frac{2}{5}+x\))
\(4\left(x^2+15x+50\right)\left(x^2+18x+72\right)-3x^2\)
\(=4\left(x+5\right)\left(x+10\right)\left(x+12\right)\left(x+6\right)-3x^2\)
\(=4\left(x^2+17x+60\right)\left(x^2+16x+60\right)-3x^2\)
\(=4\left(x+60\right)^2+132x\left(x+60\right)+1088x^2-3x^2\)
\(=4\left(x+60\right)^2+132x\left(x+60\right)+1085x^2\)
\(=4\left(x+60\right)^2+62x\left(x+60\right)+70x\left(x+60\right)+1085x^2\)
\(=2\left(x+60\right)\left[2\left(x+60\right)+31x\right]+35x\left[2\left(x+60\right)+31x\right]\)
\(=\left(33x+120\right)\left(2x+120+35x\right)\)
\(=3\left(11x+40\right)\left(37x+120\right)\)
\(\Rightarrow\left(x^2+2x\right)^2+9\left(x^2+2x\right)+20=\left(x^2+2x\right)^2+4\left(x^2+2x\right)+5\cdot\left(x^2+2x\right)+20=\left(x^2+2x\right)\left(x^2+2x+4\right)+5\left(x^2+2x+4\right)=\left(x^2+2x+4\right)\left(x^2+2x+5\right)\)
Đặt x ra ngoài