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NL
Nguyễn Lê Phước Thịnh
CTVHS
13 tháng 7
b: \(\frac{4^6\cdot9^5+6^9\cdot120}{8^4\cdot3^{12}-6^{11}}\)
\(=\frac{2^{12}\cdot3^{10}+2^9\cdot3^9\cdot2^3\cdot3\cdot5}{2^{12}\cdot3^{12}-2^{11}\cdot3^{11}}\)
\(=\frac{2^{12}\cdot3^{10}\left(1+5\right)}{2^{11}\cdot3^{11}\left(2\cdot3-1\right)}=\frac23\cdot\frac65=\frac{12}{15}=\frac45\)
c: \(\frac{7\cdot28^8+2^4\cdot14^{10}}{4^4\cdot14^9-70\cdot16^3\cdot49^4}\)
\(=\frac{7\cdot7^8\cdot2^{16}+2^4\cdot2^{10}\cdot7^{10}}{2^8\cdot2^9\cdot7^9-2\cdot5\cdot7\cdot2^{12}\cdot7^8}=\frac{7^9\cdot2^{14}\left(2^2+7\right)}{2^{13}\cdot7^8\left(2^4-5\cdot7\right)}=\frac{7\cdot2\cdot\left(4+7\right)}{16-35}=\frac{14\cdot11}{-19}=\frac{-154}{19}\)
GN
GV Nguyễn Trần Thành Đạt
Giáo viên
12 tháng 9 2023
1)69.24+69.120+144.31
= 69. (24+120) + 144.31
= 144.69 + 144.31
= 144. (69+31)
= 144.100
=14 400
2)95.103-95.2-95
= 95. (103-2-1)
= 95.100
= 9 500
4)47.62+31.106
= 47. 62+ (31.2). 53
= 47.62 + 62. 53
= 62. (47+53)
= 62.100
= 6 200
5) 54.12+27.77-27
= 27. (2.12) + 27.77 - 27.1
= 27. 24 + 27.77 - 27.1
= 27. (24+77-1)
= 27. 100
= 2 700
6) 49+215+51+83+85
= (49+51) + (215+85)+ 83
= 100 +300 + 83
= 483
\(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
\(=\frac{2^{12}.3^{10}+2^9.3^9.2^3.3.5}{2^{12}.3^{12}-2^{11}.3^{11}}\)
\(=\frac{2^{12}.3^{10}+2^{12}.3^{10}.5}{2^{11}.3^{11}.\left(2.3-1\right)}\)
\(=\frac{2^{12}.3^{10}.\left(1+5\right)}{2^{11}.3^{11}.5}\)
\(=\frac{2.6}{3.5}=\frac{4}{5}\)
\(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
\(=\frac{2^{12}.3^{10}+2^9.3^9.2^3.3.5}{2^{12}.3^{12}-6^{11}}\)
\(=\frac{2^{12}.3^{10}+2^{12}.3^{10}.5}{6^{12}-6^{11}}\)
\(=\frac{2^{12}.3^{10}\left(1+5\right)}{6^{11}.6-6^{11}}\)
\(=\frac{\left(2.3\right)^{10}.2^2.6}{6^{11}\left(6-1\right)}\)
\(=\frac{6^{10}.6.2^2}{6^{11}.5}=\frac{6^{11}.2^2}{6^{11}.5}=\frac{2^2}{5}=\frac{4}{5}\)