=>2x-4=2

hay x=3

\(2^8\) mới bằng 256 thôi ạ.

52-2(3x-6)=10                              3636:(12x-91)=36                                      2x+3=32

2(3x-6)=52-10                              12x-91=3636:36                                         2x=32-3

2(3x-6)=42                                    12x-91=101                                                2x=29

3x-6=42:2                                      12x=101+91                                               x=29:2   (loại vì x thuộc N)

3x-6=21                                         12x=192

3x=21+6                                         x=192:12=16

3x=27

x=27:3=9

                 2x.8=512                                                 (24-x)³=64

                 2x=512:8                                                  (24-x)³=4³

                  2x=64                                                      =>  24-x=4

                  x=64:2=32                                                          x=24-4=20

a,52-2(3x-6)=10

2(3x-6)=52-19=42

3x-6=42:2=21

3x=21+6=27

x=27:3

x=9

b,3636:(12x-91)=36

12x-91=3636:36=101

12x=101+91=192

x=192:12

x=16

c,2x+3=32

2x=32-3=29

x=29:2

x=29/2.Vì x thuộc tập số tự nhiên=> không tồn tại x thỏa mãn đề bài

d,2x.8=512

2x=512:8=64

x=64:2

x=32

e,(24-x)^3=64

(24-x)^3=4^3

=>24-x=4

x=24-4

x=20

a: 3^x=243

=>3^x=3^5

=>x=5

b: 4^x=4096

=>4^x=4^5

=>x=5

c: 5^3-x=25

=>3-x=2

=>x=1

d: =>2x-3=3

=>2x=6

=>x=3

j: =>2^x*8+2^x*2=80

=>2^x=8

=>x=3

Bài 2: 

a: =>x-1=1 hoặc x-1=-1

=>x=2 hoặc x=0

b: =>x+1=-1

hay x=-2

c: =>(135-7x):9=8

=>135-7x=72

=>7x=63

hay x=9

d: =>(x+7)(x-3)<0

=>-7<x<3

e: \(\Leftrightarrow3^{x-3}=18+9=27\)

=>x-3=3

hay x=6

f: =>4-2x=0

hay x=2

bài 1 ik

\(\frac{2x-3}{-8}=\frac{512}{3-2x}\)

\(\left(2x-3\right)\cdot\left(3-2x\right)=-8\cdot512\)

\(\Rightarrow12x-4x^2-9=-4096\)

\(\Rightarrow-4x^2+12x-3^2=-4096\)

\(\Rightarrow-\left(4x^2-12x+3^2\right)=-4096\)

\(\Rightarrow-\left(2x-3\right)^2=-4096\)

\(\Rightarrow2x-3=4096\)

\(\Rightarrow2x=4099\)

\(\Rightarrow x=\frac{4099}{2}\)

a: \(x^3=27\)

=>\(x^3=3^3\)

=>x=3

b: \(\left(2x-1\right)^3=8\)

=>\(\left(2x-1\right)^3=2^3\)

=>2x-1=2

=>2x=2+1=3

=>\(x=\frac32=1,5\)

c: \(\left(x-2\right)^2=16\)

=>\(\left[\begin{array}{l}x-2=4\\ x-2=-4\end{array}\right.\Rightarrow\left[\begin{array}{l}x=4+2=6\\ x=-4+2=-2\end{array}\right.\)

d: \(\left(2x-3\right)^2=9\)

=>\(\left[\begin{array}{l}2x-3=3\\ 2x-3=-3\end{array}\right.\Longrightarrow\left[\begin{array}{l}2x=6\\ 2x=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=3\\ x=0\end{array}\right.\)

e: \(2x+5=3^4:3^2\)

=>\(2x+5=3^2=9\)

=>2x=9-5=4

=>\(x=\frac42=2\)

f: \(\left(3x-2^4\right)\cdot7^3=2\cdot7^4\)

=>\(3x-16=2\cdot\frac{7^4}{7^3}=2\cdot7=14\)

=>3x=16+14=30

=>\(x=\frac{30}{3}=10\)

a: \(x^3=27\)

=>\(x^3=3^3\)

=>x=3

b: \(\left(2x-1\right)^3=8\)

=>\(\left(2x-1\right)^3=2^3\)

=>2x-1=2

=>2x=2+1=3

=>\(x=\frac32=1,5\)

c: \(\left(x-2\right)^2=16\)

=>\(\left[\begin{array}{l}x-2=4\\ x-2=-4\end{array}\right.\Rightarrow\left[\begin{array}{l}x=4+2=6\\ x=-4+2=-2\end{array}\right.\)

d: \(\left(2x-3\right)^2=9\)

=>\(\left[\begin{array}{l}2x-3=3\\ 2x-3=-3\end{array}\right.\Longrightarrow\left[\begin{array}{l}2x=6\\ 2x=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=3\\ x=0\end{array}\right.\)

e: \(2x+5=3^4:3^2\)

=>\(2x+5=3^2=9\)

=>2x=9-5=4

=>\(x=\frac42=2\)

f: \(\left(3x-2^4\right)\cdot7^3=2\cdot7^4\)

=>\(3x-16=2\cdot\frac{7^4}{7^3}=2\cdot7=14\)

=>3x=16+14=30

=>\(x=\frac{30}{3}=10\)

1: =>5(2x+6)=40

=>2x+6=8

=>2x=2

=>x=1

2: =>12-(x+3)=256:64=4

=>(x+3)=8

=>x=5

3: =>2x-1=3 hoặc 2x-1=-3

=>x=2 hoặc x=-1

4: \(\Leftrightarrow3^{x+2017}=3^{2015}\)

=>x+2017=2015

=>x=-2

1: =>5(2x+6)=40

=>2x+6=8

=>2x=2

=>x=1

2: =>12-(x+3)=256:64=4

=>(x+3)=8

=>x=5

3: =>2x-1=3 hoặc 2x-1=-3

=>x=2 hoặc x=-1

4: \Leftrightarrow3^{x+2017}=3^{2015}⇔3x+2017=32015

=>x+2017=2015

=>x=-2