a) \(3.5^2+15.2^2-26\div2\)

= 3.25 + 15.4 - 13

= 75 + 60 - 13

= 135 - 13

= 122

b) \(5^3.2-100\div4+2^3.5\)

= 125.2 - 25 + 8.5

= 250 - 25 + 40

= 225 + 40

= 265

c)\(6^2\div9+50.2-3^3.33\)

= 36 : 9 + 100 - 9.33

= 4 + 100 - 297

= 104 - 297

= -193

d)\(3^2.5+2^3.10-81\div3\)

= 9.5 + 8.10 - 27

= 45 + 80 - 27

= 125 - 27

= 98

e) \(5^{13}\div5^{10}-25.2^2\)

= 5³ - 25.4

= 125 - 100

= 25

f) \(20\div2^2+5^9\div5^8\)

= 20 : 4 + 5

= 5 + 5

= 10

786 x ( 52 + 18 ) + 232 x ( 18 + 52 )

= 786 x 70 + 232 x 70

= 70 x ( 786 + 232 )

= 70 x 1018

= 71260

786 x ( 52 + 18 ) + 232 x ( 18 + 52 ) 

 = 786 x 70 + 232 x 70

= 70 x ( 786 + 232 )

= 70 x 1018

= 71260

a: \(101^2=\left(100+1\right)^2\)

\(=100^2+2\cdot100\cdot1+1^2=10000+200+1\)

=10201

b: \(97\cdot103=\left(100-3\right)\left(100+3\right)\)

\(=100^2-3^2=10000-9=9991\)

c: \(77^2+23^2+77\cdot46\)

\(=77^2+2\cdot77\cdot23+23^2\)

\(=\left(77+23\right)^2=100^2=10000\)

d: \(105^5-5^2=\left(105-5\right)\left(105+5\right)=100\cdot110=11000\)

e: \(A=\left(x-y\right)\left(x^2+xy+y^2\right)+2y^3\)

\(=x^3-y^3+2y^3=x^3+y^3\)

\(=\left(\frac23\right)^3+\left(\frac13\right)^3=\frac{8}{27}+\frac{1}{27}=\frac{9}{27}=\frac13\)

có lộn đề ko bn ơi 

c). 1081.46

d). 1000

e. P=(x−y)(x2+xy+y2)−2y3=x3−y3−2y3=x3−3y3=(12)3−3.(23)3=−5572

mik k biết nữa

a, 71-(33+x)=26

33+x=71-26

33+x=45

x=45-33

x=12

Vậy x=12

\(71-\left(33+x\right)=26\\ \left(33+x\right)=71-26\\ \left(33+x\right)=45\\ x=45-33\\ x=12\)

a: x-56:4=16

nên x-14=16

hay x=30

b: \(101+\left(36-4x\right)=105\)

\(\Leftrightarrow36-4x=4\)

hay x=8

Vì a: x-56:4=16

    =>x-14=16

   Hay:x=30

Vì b: 

   Hay:x=8

         Vậy x={30:8}

 Nếu sai thì thui nhá,đừng chửi mình!

   232 - 582 - ( 232 - 81) 

= 232 - 582 - 232 + 81

= ( 232 - 232 ) - ( 582 - 81)

= 0 -  501

= - 501

= 232 - 232 - (582 - 81) 

=0 - 501 

= (-501)

Ta có: \(\left(3+\frac{31}{33}\right)\times\left(4+\frac{11}{4}\right)\times\frac{25}{35}\times\frac{11}{195}\times\frac{81}{134}\times\left(5+\frac49\right)\)

\(=\frac{130}{33}\times\frac{1}{195}\times\frac{27}{4}\times\frac{81}{134}\times\frac57\times\frac{49}{9}\)

\(=\frac{2}{3\times33}\times\frac{27}{4}\times\frac{81}{134}\times5\times\frac79=\frac{2}{9\times11}\times\frac{27}{4}\times\frac{81}{134}\times\frac{35}{9}\)

\(=\frac{2\times3}{4\times11}\times\frac{81}{134}\times\frac{35}{9}=\frac{3}{22}\times\frac{9}{134}\times35=\frac{945}{2948}\)