\(G=\frac{18.123+9.4567.2+3.5310.6}{1+4+7+...+55+58-410}\)

\(\rightarrow G=\frac{18.123+18.4567+18.5310}{\left(58+1\right).20\div2-410}\)

\(\rightarrow G=\frac{18.\left(123+4567+5310\right)}{590-410}\)

\(\rightarrow G=\frac{18.10000}{180}\)

\(\rightarrow G=\frac{180000}{180}\)

\(\rightarrow G=\frac{180.1000}{180}\)

\(\rightarrow G=1000\)

\(G=\left(18\cdot123+9\cdot4567\cdot2+3\cdot5310\cdot6\right)\div\left(1+4+7+10+55+58-410\right)\)

\(\left(58-1\right)\div3+1=20\)

\(G=\left(18\cdot123+9\cdot4567\cdot2+3\cdot5310\cdot6\right)\div\left[\left(58+1\right)\times20\div2-410\right]\)

\(G=180000\div180\)

\(G=1000\)

a,D=1+2+4+8+16+32+64+128+256+512+1024

   D=(1+2)+4+8+16+32+64+128+256+512+1024

   D=(4+4)+8+16+32+64+128+256+512+1024

   D=(8+8)+16+32+64+128+256+512+1024

   D=(16+16)+32+64+128+256+512+1024

   D=(32+32)+64+128+256+512+1024

   D=(64+64)+128+256+512+1024

   D=(128+128)+256+512+1024

   D=(256+256)+512+1024

   D=(512+512)+1024

   D=1024+1024

   D=2048

b, 18.123+9.4567.2+3.5310.6

  =18.123+(9.2).4567+(3.6).5310

  =18.123+18.4567+18.5310

  =18.(123+4567+5310)

  =18.10000

  =180000

tử số =18.123+9.4567.2+3.5310.6=18.123+18.4567+18.5310

        =18(123+4567+5310)

        =18.10000=180000

mẫu số = 1+4+7+....+49+52+55+58-490

          =(1+58)+(4+55)+.....(28+31)-490

          =59+59+59+...+59-490(10 so 59)

         =100

suy ra A=180000:100=1800

Ta có: \(0,18\times12300+9\times45670\times0,2+0,3\times53100\times6\)

\(=18\times123+1,8\times45670+1,8\times53100\)

\(=18\times123+18\times4567+18\times5310\)

\(=18\times\left(123+4567+5310\right)\)

=18x10000

=180000

Số số hạng trong dãy số 1;4;7;...;58 là:

\(\frac{58-1}{3}+1=\frac{57}{3}+1=19+1=20\) (số)

Tổng của dãy số 1;4;7;...;58 là:

\(\left(58+1\right)\times\frac{20}{2}=59\times10=590\)

TA có: \(\frac{0,18\times12300+9\times45670\times0,2+0,3\times53100\times6}{1+4+7+\cdots+58-410}\)

\(=\frac{180000}{590-410}=\frac{180000}{180}=\frac{18000}{18}=1000\)