\(4Al + 3O_2 \xrightarrow{t^o} 2Al_2O_3\\ 2Al + 3Cl_2 \xrightarrow{t^o} 2AlCl_3\\ Al_2O_3 + 6HCl \to 2AlCl_3 + 3H_2O\\ Al_2O_3 + 3H_2SO_4 \to Al_2(SO_4)_3 + 3H_2O\\ AlCl_3 + 3AgNO_3 \to 3AgCl + Al(NO_3)_3\\ Al_2(SO_4)_3 + 3Ba(NO_3)_2 \to Al(NO_3)_2 + 3BaSO_4\\ Al_2(SO_4)_3 + 6KOH \to 2Al(OH)_3 + 3K_2SO_4\\ Al(NO_3)_3 + 3KOH \to Al(OH)_3 + 3KNO_3\\ Al(OH)_3 + NaOH \to NaAlO_2 + 2H_2O\\ 2Al(OH)_3 \xrightarrow{t^o} Al_2O_3 + 3H_2O\)

4Al + 3O2 -> 2Al2O3

Al2O3 + 6HCl -> 2AlCl3 + 3H2O

2Al + 6HCl -> 2AlCl3 + 3H2

Al2O3 + 3H2SO4 -> Al2(SO4)3 + 3H2O

AlCl3 + 3AgNO3 -> Al(NO3)3 + 3AgCl

Al2(SO4)3 + 3Ba(NO3)2 -> 2Al(NO3)3 + 3BaSO4

Al(NO3)3 + 3NaOHvừa đủ -> Al(OH)3 + 3NaNO3

Al2(SO4)3 + 3Ba(OH)2vừa đủ -> 2Al(OH)3 + 3BaSO4

Al(OH)3 + NaOH -> NaAlO2 + 2H2O

2Al(OH)3 -> Al2O3 + 3H2O

Al2O3 + 2NaOH -> 2NaAlO2 + H2O
 

mờ quá mình ko đọc đc

29 - [16+3.(51-40)= 29 - [16+3.11]

                          = 29 - [16+ 33]                       ( vi nhan chia truoc cong tru sau )

                          = 29 - 49

                          = - 20

chuc ban hoc tot

=29-[16+3.11]

=29-[16+33]

=29-49

= - 20

= -5 - 37 - 45 + 51 + 37 - 51

= (-5 -45 )+ (37 - 37) + (51 - 51) 

= -50 

\(-5+\left(-37-45+51\right)-\left(-37+51\right)\)

\(=-5-37-45+51+37-51\)

\(=-\left(5+45\right)-\left(37-37\right)+\left(51-51\right)\)

\(=-50-0+0=-50\)

=-15+15+17-17-22+22

=0+17-17-22+22

=0+0-22+22

=0+0+0

=0

ngu v~

C1: -145.(13-57)+57.(10-145)

=-145.(-44)+57.-135

=6380+(-7695)

=-1315

C2:SGK

âm 145 à bạn

54 - ( 45 - 30 + 54 ) - 30 + 5

= 54 - 45 + 30 - 54 - 30 + 5

= ( 54 - 54 ) - ( 45 - 5 ) + ( 30 - 30 )

= 0 - 40 + 0

= - 40

= 54-45+30-54-30+5

= (54-54) + (30-30) - (45-5)

= -40

1/2 + 1/14 + 1/35 + 1/65 + 1/104 + 1/152 = 12/19

k

ahihi, bít chít liền

TAO

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KO BÍT

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